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Download JEE-Main 2019 Paper II EHG 7th April 2019 S1 S2 Question Paper

Download JEE-Main 2019 Paper II EHG 7th April 2019 S1 S2 Previous Question Paper || The Joint Entrance Examination (JEE)-Main) Last 10 Years Question Paper

This post was last modified on 21 January 2021

JEE-Main Last 10 Years 2011-2021 Previous Question Papers


Question Paper Name: Paper II EHG 7th April 2019 S1 S2

Subject Name: Paper II EHG

Creation Date: 2019-04-07 14:22:38

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Duration: 180

Total Marks: 390

Display Marks: Yes

Paper II

Group Number : 1

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Group Id : 416529185

Group Maximum Duration : 0

Group Minimum Duration : 180

Revisit allowed for view?: No

Revisit allowed for edit?: No

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Break time: 0

Group Marks: 390

Mathematics

Section Id : 416529349

Section Number : 1

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Section type : Online

Mandatory or Optional: Mandatory

Number of Questions: 120

Number of Questions to be attempted:

Section Marks: 390

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Display Number Panel: Yes

Group All Questions: No

Sub-Section Number: 1

Sub-Section Id: 416529529

Question Shuffling Allowed : Yes

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Question Number : 1 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? Z X Z ? ? ? R ? ? ? ?:

(a, b) R (c, d) = a-d=b-c, ? Z ? ? ? ? ?, ? ? R :

Options:

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1. ? ? ? ? ? ? ? ? ? ? ?

2. ? ? ? ? ? ? ? ? ? ? ?

3. ? ? ? ? ? ? ? ? ? ? ?

4. ? ? ? ? ? ? ? ?

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Question Number : 1 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? R ? Z X Z ?

(a, b) R (c, d) = a-d=b-c, i Z ? ? ? ? ? ?. ? R ?

Options:

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1. ? ? ? ? ? ? ? ? ?.

2. ? ? ? ? ? ? ? ? ?.

3. ? ? ? ? ? ? ? ? ?.

4. ? ? ? ? ? ? ?

Question Number : 1 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

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Correct Marks: 4 Wrong Marks : 1

Let R be a relation defined on ZXZ by

(a, b) R (c, d) = a-d=b-c, where Z is the set of all integers, then R is:

Options:

1. reflexive but neither symmetric nor transitive.

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2. transitive.

3. transitive but neither reflexive nor symmetric.

4. symmetric and transitive but not reflexive.

Question Number: 2 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

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Let z(-1) be any complex number such that |z| = 1. Then the imaginary part of

z(1-z)

is:

z(1 + z)

(Here 0 = arg z)

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Options:

1. -tan(?/2)sin?

2. tan(?/2)cos?

3. -tan(?/2)cos?

4. tan(?/2)sin?

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Question Number : 2 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

? z (? -1) ? ? ? ?, ? |z| = 1 ?, ? Im (z(1-z)/(1+z)) ? ? :

(? 0 = arg z)

Options:

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1. tan(?/2)cos?

2. -tan(?/2)cos?

3. tan(?/2)sin?

Question Number: 2 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

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? ? z (#-1) ? ? ? ? ? ? ? |z/ = 1 ?. ? z(1-z)/(1+z) ? ? ? ?.

(? 0 = arg z.)

Options:

1. -tan(?/2)sin?

2. tan(?/2)cos?

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3. -tan(?/2)cos?

4. tan(?/2)sin?

Question Number: 3 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

The set of all real values of a for which the equation, |x+2|-|x-2| = a²-2x has real solutions for x, is:

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Options:

2. (-8,0] ? [2,1+v5]

3. [-1-v5,1-v5] ? [1+v5, 8)

4. [1-v5,0] ? [2,1+v5]

Question Number: 3 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

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Correct Marks: 4 Wrong Marks : 1

a ? ? ? ? ?, ? ? ? |x+2|-|x-2| = a²-2x, ? x ? ? ? ?, ? ? ? :

Options:

1. (-8,0] ? [2,8)

2. (-8,0] ? [2,1 + v5]

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3. [-1-v5,1-v5] ? [1+v5, 8)

4. [1-v5,0] ? [2,1+v5]

Question Number: 3 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

x ? ? |x+ 2|-|x-2| = a²- 2x ? ? ? ? ? ? @ ? ? ? ? ? ?.

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Options:

1. (-8,0] ? [2,8)

2. (-8,0] ? [2,1 + v5]

3. [-1-v5,1-v5] ? [1+ v5, 8)

4. [1-v5,0] ? [2,1+v5]

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Question Number : 4 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

Let A be a 2x2 matrix such that A²+A+I=0, where I=I2. Then |adj(I-A)6)| is equal to:

Options:

1. 3³

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2. 34

3. 36

4. 3?

Question Number : 4 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

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? A ? 2×2 ?, ? ? A²+A+I=0, ? I=I2 ?, ? |adj (I-A)6)| ? ? :

Options:

1. 3³

2. 34

3. 36

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4. 3?

Question Number : 4 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? A ? ? 2×2 ? ? ? ? A²+A+I=0 ?, ? I = I2. ? |adj (I – A)6) | ? ?.

Options:

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1. 3³

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3. 36

4. 3?

Question Number: 5 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

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Correct Marks: 4 Wrong Marks : 1

If the system of linear equations

x+4y-3z=2

2x+7y-4z=a

-x-5y+5z=ß

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has infinitely many solutions, then the ordered pair (a, ß) cannot take the value :

Options:

1. (4,-2)

2. (2,-4)

3. (3, -3)

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4. (-3,3)

Question Number: 5 Question Type : MCQ Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? ? ?

x+4y-3z=2

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2x+7y-4z = a

-x-5y+5z=ß

? ? ? ?, ? ? ? (a, (B) ? ? ? ? ? ? ? ? ? ?

Options:

1. (4,-2)

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2. (2,-4)

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4. (-3,3)

Question Number : 5 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

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? ? ? ?

x+4y-3z=2

2x+7y-4z = a

-x-5y+5z=ß

? ? ? ?, ? ? ? (a, B) ? ? ? ? ?.

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Options:

1. (4,-2)

2. (2,-4)

3. (3, -3)

4. (-3,3)

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Question Number: 6 Question Type : MCQ Option Shuffling Es Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

Let A be the set of all 3-digit natural numbers and B = {x ? A : H.C.F. (x, 15) =1}. Then the number of elements in B is:

Options:

1. 420

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2. 360

3. 480

4. 240

Question Number : 6 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

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Options:

1. 420

2. 360

3. 480

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4. 240

Question Number : 6 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? A ? 3-? ? ? ? ? ? ? B = {x ? A : H.C.F. (x, 15) =1}. ? B ? ? ? ?.

Options:

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1. 420

2. 360

3. 480

4. 240

Question Number: 7 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option: No Option Orientation : Vertical

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Correct Marks: 4 Wrong Marks : 1

If r is the remainder obtained on dividing (98)5 by 12, then the coefficient of x³ in the Binomial expansion of (1 + x/2)²r is:

Options:

1. 55/2

2. 91/2

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4. 70

Question Number : 7 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? (98)5 ? 12 ? ? ? ? ? 1 ?, ? (1+x/2)²r ? ? ? ?, x³ ? ? ?:

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Options:

1. 55/2

2. 91/2

3. 102

4. 70

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Question Number: 7 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? (98)5 ? 12 ? ? ? ? x ?, ? (1+x/2)²r ? ? ? 3 ? ? ?.

Options:

1. 55/2

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2. 91/2

3. 102

4. 70

Question Number : 8 Question Type : MCQ Option www.FirstRanker.com

No Option Orientation : Vertical

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Correct Marks : 4 Wrong Marks : 1

4. 128

Question Number : 8 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? ? ? ?, ? ? ? ? ? ? 66 ? ? ? ? ? ? ? ? 128 ?, ? ? ? ? 6 ? ? ? ? :

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Options:

1. 127

2. 129

3. 126

4. 128

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Question Number: 8 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

? ? ? ? ? ? ? ? ? 66 ? ? ? ? ? ? 128 ?. ? ? ? ? 6 ? ? ?.

Options:

1. 127

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3. 126

4. 128

Question Number: 9 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

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The sum of the infinite series 1 + 2/3 + 6/3² + 10/3³ + 14/34 + ......: is:

Options:

1. 4

2. 5

3. 6

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4. 9/2

Question Number: 9 Question Type: MCQ Option Shuffling: Yo Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? 1 + 2/3 + 6/3² + 10/3³ + 14/34 + ? ? ? ? :

Options:

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1. 4

2. 5

3. 6

4. 9/2

Question Number : 9 Question Type: MCQ Option www.FirstRanker.com

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No Option Orientation : Vertical

1+ 2/3 + 6/3² + 10/3³ + 14/34 + ? ? ?.

Options:

1. 4

2. 5

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3. 6

4. 9/2

Question Number : 10 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

lim (vx + 6 - sin(x - 3) - 3) / ((x-3)cos(x - 3)) is equal to:

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x?3

Options:

1. 5/6

2. 1/6

3. 2/3

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4. 5/6

Question Number: 10 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

lim (vx + 6 - sin(x - 3) - 3) / ((x-3)cos(x - 3)) ? ? :

x?3

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Options:

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2. 1/6

3. 2/3

4. 5/6

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Question Number : 11 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

Question Number : 11 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? f ?

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a sin2x - b cosx, x > p/2

f(x) = 4, x = p/2

2b cosx, x < p/2

? ? ? ? ?, ? a + b ? ? ?.

Options:

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1. 1

2. 4

3. 5

4. 8

Question Number: 12 Question Type: MCQ Option Shuffling: Wag: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

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Correct Marks: 4 Wrong Marks : 1

Let y be an implicit function of x defined by

(x+y)/2 - 1/(x+y) + 12y = 0.

If y(0) = -1, then dy/dx at x = 0 is:

Options:

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1. 1/2

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3. 5/4

4. -4/5

Question Number : 12 Question Type : MCQ Option Shuffling : Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

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Correct Marks: 4 Wrong Marks : 1

? ? ? ? ? :

? y, x ? ? (implicit) ?

(x+y)/2 - 1/(x+y) + 12y = 0.

? y(0) = - 1, ? x = 0 ? dy/dx ? ? ? :

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Options:

1. 1/2

2. -1/2

3. 5/4

4. -4/5

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Question Number : 12 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? ?. ?y(0) = -1, ? x = 0 ? dy/dx =

Options:

1. 1/2

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2. -1/2

3. 5/4

4. -4/5

Question Number : 13 Question Type : MCQ Option Shuffling: Yes Displa Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

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Let f: R-{0} ? R be defined by

f(x) = a loge |x| +bx3+x2.

If x=-1 and x = 1 are the critical points of f(x), then:

Options:

1. f"(1)+f"(-1)=0

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2. f"(1)-f"(-1)=4

3. both x=1 and x= 1 are local minima of f(x)

4. x=1 is a local minima and x = -1 is a local maxima of f(x)

Question Number : 13 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks: 4 Wrong Marks : 1

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Options:

1. f"(1)+f"(-1)=0

2. f"(1)-f"(-1)=4

3. x = 1 ? x = 1, ? f(x) ? ? ? ? ?

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4. f(x) ? x = 1, ? ? ? ? ? ? x = - 1, ? ? ? ? ?

Question Number : 13 Question Type : MCQ Option Shuffling : Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? ? f : R- {0} ? R ? f(x)=a loge |x| +bx3 + x2 ? ? ?. ? x=-1 ? x = 1 ? f(x) ? ? ? ?, ?

Options:

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1. f"(1)+f"(-1)=0

2. f"(1)-f"(-1)=4

3. x=1 ? x =-1 ? ? /(x) ? ? ?.

4. x=1 ? f(x) ? ? ? x= - 1 ? f(x) ? ? ?.

Question Number : 14 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

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Correct Marks : 4 Wrong Marks : 1

such that f(x) = 3 for all x ? [0, 5] and if ?05 f(t)dt = 3. Then the value of ?03 f(t)dt can be :

Options:

1. -4

2. 6

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3. 10

4. 12

Question Number : 14 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? f: [0, 5] ? R ? ? ? ? ? ? ? ? x ? [0, 5] ? ? |f(x)| = 3 ? ?05 f(t)dt = 3 ?, ? ?03 f(t)dt ? ? ? ? ? ? ? ?

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Options:

1. -4

2. 6

3. 10

4. 12

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Question Number : 14 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

? x € [0, 5] ? |f(x) = 3 ? ?05 f (t)dt = 3 ?. ? ?03 f(t)dt ? ? ? ?.

Options:

1. -4

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2. 6

3. 10

4. 12

Question Number : 15 Question Type : MCQ Option Shuffling: Yes Display Question Number: Yes Single Line Question Option : No Option Orientation : Vertical

Correct Marks : 4 Wrong Marks : 1

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? secx / v(sinx.cosx) dx is equal to : (where C is a constant of integration)

Options:

1. 2(tanx)^(1/2) + (2/5)(tanx)^(5/2) + C

2. (1/2)(tanx)^(1/2) + (2/5)(tanx)^(5/2) + C

3. 2(tanx)^(1/2) + (1/5)(tanx)^(5/2) + C

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4. (1/2)(tan.x)^(2) + (2/5)(tanx)^(5/2) + C

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