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Question Paper Name: Paper II EHG 8th Jan 2019 Shift 2a
Subject Name: Paper II EHG
Creation Date: 2019-01-08 16:07:24
Duration: 180
Total Marks: 390
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Display Marks: Yes
Paper II
Group Number : 1
Group Id : 416529137
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Group Maximum Duration : 0
Group Minimum Duration : 180
Revisit allowed for view?: No
Revisit allowed for edit?: No
Break time: 0
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Group Marks: 390
Mathematics
Section Id : 416529193
Section Number : 1
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Section type : Online
Mandatory or Optional: Mandatory
Number of Questions: 120
Number of Questions to be attempted:
Section Marks: 390
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Display Number Panel: Yes
Group All Questions: No
Sub-Section Number: 1
Sub-Section Id: 416529255
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Question Shuffling Allowed : Yes
Question Number : 1 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
The function f: R?R, is given by
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f(x)= x / (1+|x|) is:
Options:
- one-one and onto
- onto but not one-one
- neither one-one nor onto
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Question Number: 1 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
f: R?R, f(x)= x / (1+|x|) ? ? ? :
Options:
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- ? ? ? ?
- ? ? ? ? ? ?
- ? ? ? ? ? ?
- ? ? ? ? ? ? ? ?
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Question Number: 1 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
? f : R?R, f(x)= x / (1+|x|) ?
Options:
- ?-? ? ? ?.
- ? ? ? ?-? ?.
- ?-? ? ? ? ?.
- ?-? ? ? ? ? ?.
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Question Number : 2 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
If z1, z2 and z3 are any three distinct complex
numbers such that |z1| =1, |z2| = 2, |z3| = 4,
arg z2 = arg z1 - p / 2 and arg z3 = arg z1 + p / 2
then z2z3 is equal to :
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Options:
- 8i / z1^2
- 8iz1^2
- -8iz1^2
- 8i / z1^2
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Question Number: 2 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
? ? ? ? ? ? z1, z2 ? z3
? ? ? ? |z1| =1, |z2| = 2, |z3| = 4,
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arg z2 = arg z1 - ? / 2 ? arg z3 = arg z1 + p / 2
? z2z3 ? ? :
Options:
- 8i / z1^2
- 8iz1^2
- -8iz1^2
- 8i / z1^2
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Question Number: 2 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
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? z1, z2 ? z3 ? ? ? ? ? ?
? ? ? ? |z1| =1, |z2| = 2, |z3| = 4,
arg z2 = arg z1 - p / 2 ? arg z3 = arg z1 + p / 2
?, ? z2z3 =
Options:
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- 8i / z1^2
Question Number: 3 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
If 2a is a root of ax²+bx+c=0, ß is a root
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of ax²-2bx-c=0, and the real numbers a,
b, c (a>0), are such that ß < a; then a root ?
of ax²+4bx+2c=0 always satisfies :
Options:
- a < ? <2ß
- ß< ? <a
- ?<ß<a
- ß < a <?
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Question Number: 3 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks: 4 Wrong Marks : 1
? ax²+bx+c=0 ? ? ? 2a ?,
ax² - 2bx - c = 0 ? ? ? ? ? ? ?
? a, b, c, (a>0) ? ? ? ? ß < a, ?
ax²+4bx + 2c=0 ? ? ? ? ? ? ?
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? :
Options:
- a < ? <2ß
- ß< ? <a
- ?<ß<a
- ß < a <?
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Question Number: 3 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
ax²- 2bx-c=0 ? ? ? B ?, ? a, b, c
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(a>0) ? ? ? ? ? ? ? B < a
?, ? ax²+4bx +2c=0 ? ? ? ? ?
? ?.
Options:
- a < ? <2ß
- ß< ? <a
- ?<ß<a
- ß < a <?
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Question Number : 4 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
If B = [-2 -2] and A is a matrix such
[-1 0]
that A?¹B=B?¹ and kA?¹=2B?¹+I,
where k is some scalar and I is the 2×2
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identity matrix, then the value of k is :
Options:
- -2
- -1
- 1
- 2
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Question Number: 4 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
? B = [-2 -2] ? ? A ? ? ?
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[-1 0]
? A?¹B = B?¹ ? kA?¹=2B?¹+I, ? k
? ? (scalar) ? ? I, 2×2 ? ?
(identity) ? ?, ? k ? ? ? :
Options:
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- -2
Question Number: 4 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
? B = [-2 -2] ? A ? ? ? ? ?
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[-1 0]
? A?¹B = B?¹ ? kA?¹=2B?¹+I, ?
k ? ? ? I ? 2X2 ? ? ? ?,
? k ? ? ?.
Options:
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- -2
- -1
- 1
- 2
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Question Number : 5 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
If for positive real numbers a, b and c, the
system of linear equations
x=a(y+z), y=b(z+x), z= c(x + y)
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has non-trivial solutions, then
1 / (1+a) + 1 / (1+b) + 1 / (1+c) is equal to :
Options:
- 3 / 2
- 3
- 2
- 1 / 2
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Question Number: 5 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
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? ? ? ? a, b ? c ?
? ? ? ? x = a (y+z),
y=b(z+x), z=c(x + y) ? ? (non-trivial)
? ?, ? 1 / (1+a) + 1 / (1+b) + 1 / (1+c) ? ? :
Options:
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- 3 / 2
- 3
- 2
- 1 / 2
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Question Number: 5 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
? ? ? a, b ? c ?, ? ?
? ? x = a(y+z), y=b(z+x),
z=c(x+y) ? ? ? (non-trivial
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solutions) ?, ? 1 / (1+a) + 1 / (1+b) + 1 / (1+c) =
Options:
- 3 / 2
- 3
- 2
- 1 / 2
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Question Number : 6 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
n
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where C1 = nCr and (C0 + C1) (C1 + C2)....
(Cn-1+Cn) = AC0C1C2....Cn. Then for n=5,
A is equal to:
Options:
- 324/5
- 3125/24
- 128/3
- 625/24
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Question Number: 6 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks: 4 Wrong Marks : 1
? (1+x)n = C0+ C1x + C2x² + ... + C?xn ,
? C? = nC? ? (C0 + C1) (C1 + C2)....
(C?1+C?) = AC0C1C2....C? ? n=5 ? ?
A ? ? :
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Options:
- 324/5
- 3125/24
- 128/3
- 625/24
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Question Number: 6 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
? ? (1+x)n = C0+ C1x + C2x² + .... + C?xn
? C? = nC? ? (C0 + C1) (C1 + C2)....
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(C?1+C?) = AC0C1C2....C? ? ? n = 5 ?
A=
Options:
- 324/5
- 3125/24
- 128/3
- 625/24
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Question Number : 7 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
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For ß?0, if the coefficient of x³ in the
binomial expansion of (1 + ßx)6 and the
coefficient of x4 in the binomial expansion
of (1-ßx)8 are equal, then the value of ß
is:
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Options:
- 1/7
- -2/7
- 2/7
- -1/7
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Question Number: 7 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
B?0 ? ?, ? (1 + ßx) 6 ? ? ? ? x³
? ? ? (1-ßx) 8 ? ? ? ? x4 ?
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? ? ?, ? ß ? ? ? :
Options:
- 1/7
- -2/7
- 2/7
- -1/7
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Question Number: 7 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
B?0 ? ? (1 + ßx)6 ? ? ? x³
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? ? ? (1 – ßx)8 ? ? ? x4
? ? ? ? ? B ? ?
?.
Options:
- 1/7
- -2/7
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Question Number : 8 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
For distinct positive numbers a, b and c, if
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a², b², c² are in A.P., then which one of the
following triplets is also in A.P.?
Options:
- 1 / (b-c), 1 / (c-a), 1 / (a-b)
- 1 / (b-c), 1 / (a-b), 1 / (c-a)
- 1 / (b+c), 1 / (c+a), 1 / (a+b)
- 1 / (b+2c), 1 / (c+2a), 1 / (a+2b)
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Question Number: 8 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
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? ? ? ? a, b ? c ?
?, ? a², b², c² ? ? ? ?, ? ? ?
? ? ? ? (triplet) ? ? ? ? ?
Options:
- 1 / (b-c), 1 / (c-a), 1 / (a-b)
- 1 / (b-c), 1 / (a-b), 1 / (c-a)
- 1 / (b+c), 1 / (c+a), 1 / (a+b)
- 1 / (b+2c), 1 / (c+2a), 1 / (a+2b)
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Question Number: 8 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
? ? (A.P.) ? ?, ? ? ? ?
? ? ? (A.P.) ? ?
Options:
- 1 / (b-c), 1 / (c-a), 1 / (a-b)
- 1 / (b-c), 1 / (a-b), 1 / (c-a)
- 1 / (b+c), 1 / (c+a), 1 / (a+b)
- 1 / (b+2c), 1 / (c+2a), 1 / (a+2b)
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Question Number : 9 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
Let S? be the sum of the first n terms of
the series
1²+2·5²+3²+2·7²+5²+2·9²+ .....
If S20 = 20 A, then A is equal to :
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Note: For this question, discrepancy is found in question/answer. Full Marks is being awarded to all
candidates.
Options:
- 1851
- 1951
- 2001
- 2019
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Question Number: 9 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
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? ? 1²+ 2·5²+3²+2·7²+5²+2·9²+.....
? ? n ? ? ? S? ? ? S20 = 20A, ?
A ? ? :
Note: For this question, discrepancy is found in question/answer. Full Marks is being awarded to all
candidates.
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Options:
- 1851
Question Number: 9 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
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? ? 1²+2·5²+3²+2·7²+5² +2·9²+.....
? ? n ? ? S? ?. ? S20 = 20 A
?, ? A =
Note: For this question, discrepancy is found in question/answer. Full Marks is being awarded to all
candidates.
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Options:
- 1851
- 1951
- 2001
- 2019
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Question Number : 10 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
Let m and k be positive integers (m?k).
Then
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lim n? [ (1+1/n)? + (1+2/n)? + ..... + (1+k/n)? ] - k is :
n?8
Options:
- 0
- k(k+1) / 2 * m
- m(m+1)k / 2
- km
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Question Number: 10 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
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? m ? k ? ? ? (m?k), ?
lim n? [ (1+1/n)? + (1+2/n)? + ..... + (1+k/n)? ] - k
n?8
Options:
- 0
- k(k+1) / 2 * m
- m(m+1)k / 2
- km
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Question Number : 11 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
For f(x) = (e^(x?¹) - e^(-x?¹)) / (e^(x?¹) + e^(-x?¹)), x ? 0
0 , x = 0
Options:
- f'(0)=1
- f'(0)=0
- f is not continuous at 0
- f is not differentiable at 0
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Question Number: 11 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks: 4 Wrong Marks : 1
f(x) = (e^(x?¹) - e^(-x?¹)) / (e^(x?¹) + e^(-x?¹)), x ? 0 ? ? :
0 , x = 0
Options:
- f'(0)=1
- f'(0)=0
- x = 0 ? f ? ? ?
- x = 0 ? f ? ? ?
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Question Number: 11 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
f(x) = (e^(x?¹) - e^(-x?¹)) / (e^(x?¹) + e^(-x?¹)), x ? 0 ?
0 , x = 0
Options:
- f'(0)=1
- f'(0)=0
- f ? 0 ? ? ?.
- f ? 0 ? ? ?.
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Question Number : 12 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
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Correct Marks : 4 Wrong Marks : 1
Let F(x) = ? f(t) dt, If
0
f(x)=2+ sinx - cosx. If
F(x)-F(y) = k|x-y| for all x and y in R,
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then a possible value of k is :
Options:
- 2 + v2
- 2-v2
- 1 + 1/v2
- v2-1
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Question Number: 12 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks: 4 Wrong Marks : 1
? F(x) = ? f(t) dt, ?
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0
f(x) = 2+ sinx - cosx. ? R ? ? x ? y
? ? |F(x) - F(y)| = k|x-y|, ? k ? ?
? ? ? :
Options:
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- 2 + v2
- 2-v2
- 1 + 1/v2
- v2-1
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Question Number: 12 Question Type : MCQ Option Shuffling: Yes Display Question Number : Yes Single Line Question Option : No Option Orientation : Vertical
Correct Marks : 4 Wrong Marks : 1
? ? F(x) = ? f(t) dt ?
0
f(x) = 2+ sinx - cosx ?. ? R ? ? x
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? y ? |F(x) - F(y)| = k|x-y| ?, ? k ?
? ? ?.
Options:
- 2 + v2
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