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Download DUET Master 2018 DU PhD in Electronics Question Paper With Answer Key

Download DUET (Delhi University Entrance Test conducted by the NTA) 2018 DU PhD in Electronics Question Paper With Solution Key

This post was last modified on 29 January 2020

This download link is referred from the post: DUET Last 10 Years 2011-2021 Question Papers With Answer Key || Delhi University Entrance Test conducted by the NTA


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DU PhD in Electronics

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Topic:- DU_J18_PHD_ELEC

  1. An optical fiber consists of a core of refractive index 2.0 and a cladding of refractive index 1.732. For total internal reflection of light inside the optical fiber, the maximum angle that the light rays can make with the axis of the optical fiber is

    [Question ID = 52503]

    1. 60° [Option ID = 90006]
    2. 30° [Option ID = 90004]
    3. --- Content provided by FirstRanker.com ---

    4. 90° [Option ID = 90007]
    5. 15° [Option ID = 90005]

    Correct Answer :-

    30° [Option ID = 90004]

  2. --- Content provided by FirstRanker.com ---

  3. The solution of the following differential equation is

    x ln x dy/dx + y = 2ln x

    [Question ID = 52525]

    1. y = (lnx)² + C [Option ID = 90093]
    2. y = 2lnx+C [Option ID = 90092]
    3. --- Content provided by FirstRanker.com ---

    4. y = x(lnx)² + C [Option ID = 90095]
    5. y ln x = (lnx)² + C [Option ID = 90094]

    Correct Answer :-

    y ln x = (lnx)² + C [Option ID = 90094]

  4. --- Content provided by FirstRanker.com ---

  5. If φ = tan-1(y/x), ∇⋅(∇φ) is

    [Question ID = 52523]

    1. 2 [Option ID = 90087]
    2. 0 [Option ID = 90085]
    3. 1 [Option ID = 90084]
    4. --- Content provided by FirstRanker.com ---

    5. -1 [Option ID = 90086]

    Correct Answer :-

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  1. The longest wavelength that can be absorbed by silicon, which has the band gap of 1.12 eV, is 1.1 mm. If the longest wavelength that can be absorbed by another material is 0.87mm, then the band gap of this material is

    --- Content provided by FirstRanker.com ---

    [Question ID = 52500]

    1. 0.706 eV [Option ID = 89995]
    2. 0.854 eV [Option ID = 89994]
    3. 0.886 eV [Option ID = 89993]
    4. 1.416 eV [Option ID = 89992]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    1.416 eV [Option ID = 89992]

  2. The Newton Raphson method formula for finding the square root of a real number R from the equation x² - R = 0 is

    [Question ID = 52483]

    --- Content provided by FirstRanker.com ---

    1. Xi+1 = (3xi - R/xi)/2 [Option ID = 89927]
    2. Xi+1 = xi/2 [Option ID = 89925]
    3. Xi+1 = (xi + R/xi)/2 [Option ID = 89926]
    4. Xi+1 = 3xi/2 [Option ID = 89924]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    Xi+1 = (xi + R/xi)/2 [Option ID = 89926]

  3. The velocity of a body is given by

    v(t) = 2t 1≤ t ≤5

    =5t² +3 5<t≤14

    --- Content provided by FirstRanker.com ---

    where t is in secs and v in m/s. Using 2 segment Trapezoidal rule, the distance covered from t=2 to t=8 secs is obtained as

    [Question ID = 52480]

    1. 780 m [Option ID = 89912]
    2. 2340 m [Option ID = 89913]
    3. 585 m [Option ID = 89914]
    4. --- Content provided by FirstRanker.com ---

    5. 1170 m [Option ID = 89915]

    Correct Answer :-

    1170 m [Option ID = 89915]

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  1. The short-circuit current delivered by a 10 cm by 10 cm photocell (with 100% quantum efficiency) illuminated by monochromatic light of 400 nm wavelength with a power density of 2000 W/m² is,

    [Question ID = 52501]

    1. 8.88 A [Option ID = 89996]
    2. 6.45 μA [Option ID = 89997]
    3. 6.45 A [Option ID = 89999]
    4. --- Content provided by FirstRanker.com ---

    5. 11 A [Option ID = 89998]

    Correct Answer :-

    6.45 A [Option ID = 89999]

  2. Consider a silicon diode with ideality factor n =1. For a decade change in current the diode voltage drop changes approximately by

    --- Content provided by FirstRanker.com ---

    [Question ID = 52520]

    1. 60 mV [Option ID = 90072]
    2. 30 mV [Option ID = 90075]
    3. 80 mV [Option ID = 90073]
    4. 120 mV [Option ID = 90074]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    60 mV [Option ID = 90072]

  3. The eigen values of the matrix [cosθ sinθ] [sinθ cosθ] are

    [Question ID = 52521]

    --- Content provided by FirstRanker.com ---

    1. ejθ/2 [Option ID = 90079]
    2. e±jθ [Option ID = 90078]
    3. e3jθ [Option ID = 90076]
    4. e2jθ [Option ID = 90077]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    e±jθ [Option ID = 90078]

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  1. The table below gives values of function F(x) for values of x at intervals of 0.2.

    --- Content provided by FirstRanker.com ---

    x 1.8 2.0 2.2 2.4 2.6
    F(x) 6.05 7.39 9.03 11.02 13.46

    Using central difference, the second derivative F"(x) at x=2.0 is obtained as

    [Question ID = 52481]

    1. 7.5 [Option ID = 89919]
    2. 5.5 [Option ID = 89916]
    3. 6.5 [Option ID = 89918]
    4. --- Content provided by FirstRanker.com ---

    5. 4.5 [Option ID = 89917]

    Correct Answer :-

    7.5 [Option ID = 89919]

  2. The value of i x (a x i) + j x (a x j) + k x (a x k) is

    --- Content provided by FirstRanker.com ---

    [Question ID = 52522]

    1. 2a [Option ID = 90081]
    2. -2a [Option ID = 90083]
    3. -a [Option ID = 90082]
    4. a [Option ID = 90080]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    2a [Option ID = 90081]

  3. The skin depth of copper at a frequency of 3 GHz is 1 µm. At 12 GHz, for a non-magnetic conductor whose conductivity is 1/9 times that of copper, the skin depth will be

    [Question ID = 52493]

    --- Content provided by FirstRanker.com ---

    1. 2.5 cm [Option ID = 89966]
    2. 1.5 µm [Option ID = 89964]
    3. 1.0 cm [Option ID = 89967]
    4. 1.0 µm [Option ID = 89965]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    1.5 µm [Option ID = 89964]

  4. In a p-type semiconductor, the Fermi level is 0.2 eV above the valence band at room temperature of 300 K. The position of Fermi level at 400 K will move

    [Question ID = 52519]

  5. --- Content provided by FirstRanker.com ---

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    1. down by 0.047 eV [Option ID = 90070]
    2. down by 0.07 eV [Option ID = 90069]
    3. up by 0.047 eV [Option ID = 90071]
    4. up by 0.07 eV [Option ID = 90068]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    up by 0.07 eV [Option ID = 90068]

  1. The real part of f(z) = tanhz, where z=x+iy, is

    [Question ID = 52524]

    --- Content provided by FirstRanker.com ---

    1. sinh 2x / (cosh 2x + cosh 2y) [Option ID = 90090]
    2. sinh 2x / (cosh 2x - cos 2y) [Option ID = 90088]
    3. - sinh 2x / (cosh 2x + cos 2y) [Option ID = 90089]
    4. sinh 2x / (cosh 2x + cos 2y) [Option ID = 90091]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    sinh 2x / (cosh 2x + cos 2y) [Option ID = 90091]

  2. Assuming that for uniaxial Lithium Niobate no = 2.297 and ne = 2.208 at λo = 890 nm. What should be the thickness of a Lithium Niobate plate to make a half wave plate at λo = 890nm?

    [Question ID = 52507]

    1. 5 nm [Option ID = 90021]
    2. --- Content provided by FirstRanker.com ---

    3. 5 μm [Option ID = 90023]
    4. 25 µm [Option ID = 90022]
    5. 2.5 µm [Option ID = 90020]

    Correct Answer :-

    5 μm [Option ID = 90023]

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  1. A silicon pn junction with doping profile of Na = 1016 cm-3 and Nd = 1015 cm-3 with mobility μn = 1350 cm²/V - s and μp = 480 cm²/V-s has a cross sectional area of 10-2 cm². The length of the p-region is 200 mm and length of the n-region is 100 mm. The approximately series resistance of the diode is

    [Question ID = 52517]

    --- Content provided by FirstRanker.com ---

    1. 81 Ω [Option ID = 90063]
    2. 43 Ω [Option ID = 90062]
    3. 72 Ω [Option ID = 90060]
    4. 62 Ω [Option ID = 90061]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    72 Ω [Option ID = 90060]

  2. For pure silica the refractive index variation can be assumed to be given by an empirical formula n(λ0) = 1.451 - αλ0² + α/λ0²; α = 0.003 and λ0 is in microns. The group velocity dispersion (GVD) will be zero at the wavelength is

    [Question ID = 52506]

    1. 0.8 µm [Option ID = 90016]
    2. --- Content provided by FirstRanker.com ---

    3. 2.0 µm [Option ID = 90018]
    4. 1.5 µm [Option ID = 90017]
    5. 1.31 μm [Option ID = 90019]

    Correct Answer :-

    1.31 µm [Option ID = 90019]

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  3. Electrons are accelerated by 900 V and reflected by a crystal. If the reflection maximum occurs when the glancing angle is 60°, then the spacing of the crystal is

    [Question ID = 52514]

    1. 0.059 Å [Option ID = 90048]
    2. 0.029 nm [Option ID = 90051]
    3. --- Content provided by FirstRanker.com ---

    4. 0.059 nm [Option ID = 90050]
    5. 0.029 Å [Option ID = 90049]

    Correct Answer :-

    0.029 nm [Option ID = 90051]

  4. --- Content provided by FirstRanker.com ---

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  1. The rates of spontaneous and stimulated emission are equal for a transition at room temperature for a wavelength approximately given by [given that kT at room temperature of 300 K is 0.025 eV]

    [Question ID = 52509]

    1. 72 μm [Option ID = 90031]
    2. --- Content provided by FirstRanker.com ---

    3. 92 μm [Option ID = 90028]
    4. 50 μm [Option ID = 90030]
    5. 100 μm [Option ID = 90029]

    Correct Answer :-

    72 μm [Option ID = 90031]

    --- Content provided by FirstRanker.com ---

  2. The solution of the partial differential equation ∂u/∂x - ∂u/∂y = 0 is

    [Question ID = 52497]

    1. u = keλx²e2λy [Option ID = 89981]
    2. u = keλxe2λy [Option ID = 89982]
    3. --- Content provided by FirstRanker.com ---

    4. u = keλx²e-2λy [Option ID = 89980]
    5. u = keλxe2y [Option ID = 89983]

    Correct Answer :-

    u = keλx²e2λy [Option ID = 89981]

  3. --- Content provided by FirstRanker.com ---

  4. What is the polarization of a plane wave propagating in free space with electric field given as E = (2x+j2y)ej(ωt-kz) V/m?

    [Question ID = 52486]

    1. elliptically polarized [Option ID = 89937]
    2. unpolarized [Option ID = 89936]
    3. linearly polarized [Option ID = 89938]
    4. --- Content provided by FirstRanker.com ---

    5. circularly polarized [Option ID = 89939]

    Correct Answer :-

    circularly polarized [Option ID = 89939]

  5. If the vector potential in a region is given as A = -yâx + 2xây, the associated magnetic field B is

    --- Content provided by FirstRanker.com ---

    [Question ID = 52495]

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    1. B = 3âz [Option ID = 89974]
    2. B = -âx + ây + âz [Option ID = 89975]
    3. --- Content provided by FirstRanker.com ---

    4. B = âx + âz [Option ID = 89973]
    5. B = -âx + 2ây [Option ID = 89972]

    Correct Answer :-

    B = 3âz [Option ID = 89974]

  1. --- Content provided by FirstRanker.com ---

  2. The electron concentration in a sample of uniformly doped n-type silicon at 300 K varies linearly from 1017 cm-3 at x = 0 to 6x1016 cm-3 at x = 2 µm. Assuming a situation that electrons are supplied to keep this concentration gradient with time. and considering that no electric field is present, the current density Jx in the silicon is (Diffusion constant Dn = 35 cm²/s)

    [Question ID = 52512]

    1. 560 A/cm² [Option ID = 90043]
    2. 1120 A/cm² [Option ID = 90040]
    3. -560 A/cm² [Option ID = 90042]
    4. --- Content provided by FirstRanker.com ---

    5. -1120 A/cm² [Option ID = 90041]

    Correct Answer :-

    -1120 A/cm² [Option ID = 90041]

  3. Using a unit step size, the value of integral ∫x ln xdx from 1 to 2 by trapezoidal rule is

    --- Content provided by FirstRanker.com ---

    [Question ID = 52484]

    1. 0.543 [Option ID = 89930]
    2. 0.693 [Option ID = 89931]
    3. 0.715 [Option ID = 89929]
    4. 0.621 [Option ID = 89928]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    0.693 [Option ID = 89931]

  4. If f(x) = (x+1)/(x-1), g(x) = (2x+5)/(4x-3) then f(g(x)) is

    [Question ID = 52498]

    --- Content provided by FirstRanker.com ---

    1. (3x+1)/(4-x) [Option ID = 89984]
    2. (5x+3)/(x+2) [Option ID = 89986]
    3. (7x-3)/(x+7) [Option ID = 89985]
    4. (x-5)/(2x+3) [Option ID = 89987]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    (3x+1)/(4-x) [Option ID = 89984]

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  1. The lowest resonant frequency of a rectangular cavity resonator with cavity dimensions a = 2cm,b=1cm and d = 3cm is

    [Question ID = 52494]

    --- Content provided by FirstRanker.com ---

    1. 6 GHz [Option ID = 89968]
    2. 7 GHz [Option ID = 89969]
    3. 9 GHz [Option ID = 89971]
    4. 3 GHz [Option ID = 89970]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    9 GHz [Option ID = 89971]

  2. Inverse Laplace transform of f(s) = 9/(s²+3s) is given by

    [Question ID = 52526]

    1. 9/2 (e-t-1) [Option ID = 90098]
    2. --- Content provided by FirstRanker.com ---

    3. 9/2 -(e-t-1) [Option ID = 90099]
    4. 9/2 (1-e-3t) [Option ID = 90096]
    5. 9/2 (1-e3t) [Option ID = 90097]

    Correct Answer :-

    9/2 (1-e-3t) [Option ID = 90096]

    --- Content provided by FirstRanker.com ---

  3. The intrinsic carrier concentration of a silicon sample at 300 K is 1.5×1016m-3. If after doping the number of majority carriers is 5×1020/m3, the minority carrier density is

    [Question ID = 52513]

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    1. 4.5×1011m-3 [Option ID = 90044]
    2. 3×105m-3 [Option ID = 90047]
    3. 3.33×104m-3 [Option ID = 90045]
    4. 5×1020m-3 [Option ID = 90046]

    Correct Answer :-

    --- Content provided by FirstRanker.com ---

    4.5×1011 m-3 [Option ID = 90044]

  1. For which of the following radii range is a step index fiber with numerical aperture 0.2 and single-moded for operation at the infrared wavelength λ = πμm

    [Question ID = 52502]

    1. a ≤ 3.9 µm [Option ID = 90000]
    2. --- Content provided by FirstRanker.com ---

    3. a ≤ 6 μm [Option ID = 90002]
    4. a ≤ 7.8 µm [Option ID = 90003]
    5. a ≥ 6 µm [Option ID = 90001]

    Correct Answer :-

    a ≤ 6 μm [Option ID = 90002]

    --- Content provided by FirstRanker.com ---

  2. Which of the following is NOT correct for a plane wave with H = 0.5e-αx cos(2π×108t-3x)ây, A/m

    [Question ID = 52491]

    1. The phase constant is 3 rad/m [Option ID = 89957]
    2. The wave frequency is 100 MHz [Option ID = 89956]
    3. --- Content provided by FirstRanker.com ---

    4. The wave is travelling in the +ve x-direction [Option ID = 89958]
    5. The wave is polarized along the y-direction [Option ID = 89959]

    Correct Answer :-

    The wave is polarized along the y-direction [Option ID = 89959]

  3. --- Content provided by FirstRanker.com ---

  4. If a voltage of 6 V is applied across a 2 cm long semiconductor bar the average drift velocity is 104 cm/s. The electron mobility is

    [Question ID = 52516]

    1. 3×104cm²/V-s [Option ID = 90056]
    2. 3333 cm²/V-s [Option ID = 90057]
    3. 4396 cm²/V-s [Option ID = 90059]
    4. --- Content provided by FirstRanker.com ---

    5. 6x104cm²/V-S [Option ID = 90058]

    Correct Answer :-

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    1. 3333 cm²/V-S [Option ID = 90057]
    2. --- Content provided by FirstRanker.com ---

  1. The attenuation in an optical fiber at 1550 nm is 0.2 dB/km. If 160 µW power is launched into the fiber at 1550 nm, estimate the power in the fiber after 30 km.

    [Question ID = 52505]

    1. 45 μW [Option ID = 90013]
    2. 40 μW [Option ID = 90015]
    3. --- Content provided by FirstRanker.com ---

    4. 15 μW [Option ID = 90014]
    5. 80 µW [Option ID = 90012]

    Correct Answer :-

    40 μW [Option ID = 90015]

  2. --- Content provided by FirstRanker.com ---

  3. A course WDM optical communication system uses the two wavelengths λ1 = 1300 nm and λ2 = 1500 nm. The frequency difference between the two channels

    [Question ID = 52508]

    1. 209 THz [Option ID = 90027]
    2. 30.8 GHz [Option ID = 90024]
    3. 30.8 THz [Option ID = 90025]
    4. --- Content provided by FirstRanker.com ---

    5. 900 GHz [Option ID = 90026]

    Correct Answer :-

    30.8 THz [Option ID = 90025]

  4. If the Euler method is used to solve the initial value problem dy/dx = -y with y(0) = 1.0 with step size h = 0.01, the value of y(0.02) is obtained as

    --- Content provided by FirstRanker.com ---

    [Question ID = 52485]

    1. 0.5201 [Option ID = 89934]
    2. 0.7210 [Option ID = 89933]
    3. 0.9801 [Option ID = 89935]
    4. 0.62 [Option ID = 89932]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    0.9801 [Option ID = 89935]

  5. An isolator has a insertion loss of 1 dB over the operating bandwidth. What is the output power, if the input power is 10 mW?

  6. --- Content provided by FirstRanker.com ---

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    1. 5.0 mW [Option ID = 89948]
    2. 12.0 µW [Option ID = 89950]
    3. 7.94 mW [Option ID = 89949]
    4. 2.5 mW [Option ID = 89951]
    5. --- Content provided by FirstRanker.com ---

    Correct Answer :-

    7.94 mW [Option ID = 89949]

  1. For an short-circuited

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    This download link is referred from the post: DUET Last 10 Years 2011-2021 Question Papers With Answer Key || Delhi University Entrance Test conducted by the NTA