Download GTU (Gujarat Technological University) BE/BTech (Bachelor of Engineering / Bachelor of Technology) 2019 Summer 3rd Sem New 2130601 Surveying Previous Question Paper
Seat No.: ________ Enrolment No.___________
GUJARAT TECHNOLOGICAL UNIVERSITY
BE - SEMESTER ?III (NEW) EXAMINATION ? SUMMER 2019
Subject Code: 2130601 Date: 04/06/2019
Subject Name:Surveying
Time: 02:30 PM TO 05:00 PM Total Marks: 70
Instructions:
1. Attempt all questions.
2. Make suitable assumptions wherever necessary.
3. Figures to the right indicate full marks.
Q.1 (a) State the principle of plane tabling 03
(b) Which are the methods of plane tabling? Explain any two in detail.
04
(c) ABCD is a closed traverse in which the bearing of DA has not been observed.
The rest of the field record is as follows: Find the bearing of line DA
Line Length Bearing
AB 235.10 338? 20'
BC 317.40 82? 22'
CD 215.00 167? 00'
DA 285.21 ?
07
Q.2 (a) Enumerate the method to find RL of instrument axis when base of the object is
accessible
03
(b) Which are the methods of measuring horizontal angles? Briefly describe
repetition method
04
(c) Explain the temporary adjustments of theodolite 07
OR
(c) Which are the methods of traversing? Explain fast angle method and loose needle
method in detail
07
Q.3 (a) What is basic principle of trigonometric levelling and the difference between
plane and geodetic methods
03
(b) A theodolite was set up at a distance of 140 m from tower. The angle of elevation
to the top of the parapet was 11? 8' while the angle of depression to the foot of the
wall was 2? 12'. The staff reading on the BM of RL 60.25 with telescope
horizontal was 0.880. Find the height of the tower and the RL of the top of the
parapet
04
(c) Derive the expression for computing horizontal distance and elevation in
trigonometric levelling while base of the object is inaccessible and instrument
stations are in same vertical plane with the elevated object for the instrument axes
at (i) same level and (ii) different levels
07
OR
Q.3 (a) Explain horizontal curve 03
(b) Two straights intersect at chainage 3000 m and the angle of intersection is 120?.
If the radius of the simple curve to be introduced is 600 m, find the following:
(I) Tangent distance
(ii) Chainage of the point of commencement
(iii) Length of the long chord
04
(c) Draw the sketch explaining elements of simple circular curve. Define: Point of
intersection, angle of deflection, point of curvature, tangent distance, long chord,
mid ordinate, external distance
07
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Seat No.: ________ Enrolment No.___________
GUJARAT TECHNOLOGICAL UNIVERSITY
BE - SEMESTER ?III (NEW) EXAMINATION ? SUMMER 2019
Subject Code: 2130601 Date: 04/06/2019
Subject Name:Surveying
Time: 02:30 PM TO 05:00 PM Total Marks: 70
Instructions:
1. Attempt all questions.
2. Make suitable assumptions wherever necessary.
3. Figures to the right indicate full marks.
Q.1 (a) State the principle of plane tabling 03
(b) Which are the methods of plane tabling? Explain any two in detail.
04
(c) ABCD is a closed traverse in which the bearing of DA has not been observed.
The rest of the field record is as follows: Find the bearing of line DA
Line Length Bearing
AB 235.10 338? 20'
BC 317.40 82? 22'
CD 215.00 167? 00'
DA 285.21 ?
07
Q.2 (a) Enumerate the method to find RL of instrument axis when base of the object is
accessible
03
(b) Which are the methods of measuring horizontal angles? Briefly describe
repetition method
04
(c) Explain the temporary adjustments of theodolite 07
OR
(c) Which are the methods of traversing? Explain fast angle method and loose needle
method in detail
07
Q.3 (a) What is basic principle of trigonometric levelling and the difference between
plane and geodetic methods
03
(b) A theodolite was set up at a distance of 140 m from tower. The angle of elevation
to the top of the parapet was 11? 8' while the angle of depression to the foot of the
wall was 2? 12'. The staff reading on the BM of RL 60.25 with telescope
horizontal was 0.880. Find the height of the tower and the RL of the top of the
parapet
04
(c) Derive the expression for computing horizontal distance and elevation in
trigonometric levelling while base of the object is inaccessible and instrument
stations are in same vertical plane with the elevated object for the instrument axes
at (i) same level and (ii) different levels
07
OR
Q.3 (a) Explain horizontal curve 03
(b) Two straights intersect at chainage 3000 m and the angle of intersection is 120?.
If the radius of the simple curve to be introduced is 600 m, find the following:
(I) Tangent distance
(ii) Chainage of the point of commencement
(iii) Length of the long chord
04
(c) Draw the sketch explaining elements of simple circular curve. Define: Point of
intersection, angle of deflection, point of curvature, tangent distance, long chord,
mid ordinate, external distance
07
2
Q.4 (a) What is transition curve? State the requirements of a transition curve 03
(b) How would you find out weather the vertical curve will have convexity upwards
or downwards if the gradients on the two sides of the apex are given?
04
(c) The following offsets were taken at 10 m intervals from a survey line to an
irregular boundary line.
2.50,4.40,6.60,5.50,7.40,8.70,7.80,6.50,4.30,3.20
calculate the area enclosed between the survey line, the irregular boundary line
and the first and last offsets by
(i) The trapezoidal Rule
(ii) Simpson's Rule
07
OR
Q.4 (a) The area of irregular figure was measured with a planimeter having the anchor
point outside the figure. The initial and final readings were 5.835 and 9.354 m
respectively. The zero mark of the dial didn't passed index mark during the
measurement. The tracing arm was get to the natural scale ( M = 100 square cm)
. The scale of the map was 1 cm = 10 m. Find the area of the figure
03
(b) Which are the methods of measurement of area by offset from baseline? Explain
mid ordinate and average ordinate rule.
04
(c) Find the area of the closed traverse having the following data, by the coordinate
method.
Line Latitude Departure
PQ +215.50 +110.50
QR -235.00 +220.00
RS -160.50 -120.50
SP +180.00 -210.00
07
Q.5 (a) The area enclosed by the contours in a reservoir are as follows:
The top water level is 195 m and the lowest point in the reservoir is 175 m. Find
the volume of water ( reservoir capacity) between the contours 175 m and 195 m
by
(I) The trapezoidal formula and
(ii) The prismoidal formula
Contour (m) 175 180 185 190 195
Area (m2) 460 750 2500 3500 3950
03
(b) Explain the method of finding volume by prismoidal formula 04
(c) What is planimeter? Explain the components and use of it 07
OR
Q.5 (a) Describe horizontal control in Hydrography 03
(b) Which are the instruments used for taking soundings? Explain Shore signals and
buoys in detail
04
(c) Write a short note on setting out a building 07
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This post was last modified on 20 February 2020