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I-MBBS
(This paper consists of 2 pages)
First M.B.B.S. (Main) Examination (New Scheme)
February - 2021
Biochemistry
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Paper- II
Time: Three Hours
Maximum Marks: 100
Attempt all questions in both sections
(Use separate answer book for each section)
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Section-A
- Fill in the blanks: 6 x 1 = 06
- SDA value for proteins is __________
- Blood Urea Nitrogen = Blood Urea X __________
- The jumping genes are also called __________
- The guardian of the genome is __________
- In Eukaryotes the mRNA during transcription is synthesized by enzyme __________
- The names of two light chains of Ig are __________ and __________
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- Choose the correct option in the following multiple choice questions: 4 x 1 = 04
- Western blotting techniques is for detection of:
- Protein
- RNA
- DNA
- All
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- Tumour marker used for the diagnosis and management of ovarian cancer:
- TPA
- PSA
- CA-125
- VMA
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- Xeroderma Pigmentosum occurs due to defect in:
- Base excision repair
- Double strand break repair
- Nucleotide excision repair
- Mismatch repair
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- Monoclonal antibodies are prepared by cloning:
- Myeloma cells
- Hybridoma cells
- T-lymphocytes
- B-lymphocytes
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- Western blotting techniques is for detection of:
- Clinical Case Study: A two day old baby on examination was found to be icteric. Laboratory findings shows serum bilirubin was 12.8 mg/dL: 5 x 3 = 15
- What is the probable diagnosis?
- What are the precursors of bilirubin and what are different types of bilirubin?
- Which type of bilirubin is high In this disease?
- What can be the enzyme defect in this disease?
- How is the above disease treated?
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- Write short notes on (Any five): 5 x 2 = 10
- Protein-Energy malnutrition
- Reactive Oxygen species
- Disorders associated with Collagen
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- Applications of PLK
- MHC
- Clearance test
- Explain briefly (Any three): 3 x 5 = 15
- Lac Operon
- BMR
- Post transcriptional modification
- Cytochrome P-450 medicated biotransformation
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Section-B
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- Give an account with illustrations on Translation in prokaryotes with its inhibitors. Add a note on post-translational modifications. 20
- Explain Why (Any five): 5 x 2 = 10
- Immunity is both a boon and evil.
- Serum creatinine is more sensitive parameter than urea for assessing renal functions.
- Why restriction Endonucleases are called molecular scissors.
- Folate antimetabolites are used as anti-cancer agents.
- Vegetarian diet is helpful in controlling cholesterol.
- Genetic code is degenerate.
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- Explain briefly (Any four): 4 x 5 = 20
- Anti oxidant enzymes.
- Tumour markers.
- Structure of immunoglobulins.
- Human genome project.
- Mutations.
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This download link is referred from the post: RUHS MBBS 2nd Year 2013-2025 Last 12 Years Previous Question Papers || Rajasthan University for Health Sciences
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