NCE-403
Paper ID : 100411
Roll No.
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B.TECH.
Theory Examination (Semester-IV) 2015-16
HYDRAULICS & HYDRAULIC MACHINES
Time: 3 Hours
Max. Marks: 100
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Section-A
Attempt all parts. All parts carry equal marks.
Q.1. Write answer of each part in short. (2×10=20)
- Define open channel flow with example.
- Describe specific energy?
- State the relation between Manning's constant and Chezy's constant
- Hydraulic jump is sometimes used as energy dissipator at the toe of the spillway of a dam. why?
- What is meant by Cavitations?
- Define celerity of the surge
- Give the range of specific speed values of Kaplan, Francis turbine and peltonwheels.
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Section-B
Q.2. Attempt any 5 questions from this section. (10×5=50)
- Classify the following open-channel flow situations:
(i) Uniform Flow in a open channel
(ii) Reaction turbine - A spillway discharges a flood flow at a rate of 7.75 m3/s per metre width. At the downstream horizontal apron the depth of flow was found to be 0.50 m. What tail water depth is needed to form a hydraulic jump? If a jump is formed, find its (a) type, (b) length, (c) head loss, (d) energy loss as a percentage of the initial energy, and (e) profile.
- Derive an expression for the discharge through a channel by Chezy's Formula.
- The width of a horizontal rectangular channel is reduced from 3.5 m to 2.5 m and the floor is raised by 0.25 m in elevation at a given section. At the upstream section, the depth of flow is 2.0 m and the kinetic energy correction factor a is 1.15. If the drop in the water surface elevation at the contraction is 0.20 m, calculate the discharge if (a) the energy loss is neglected, and (b) the energy loss is one-tenth of the upstream velocity head. [The kinetic energy correction factor at the contracted section may be assumed to be unity].
- What is critical depth in open-channel flow? For a given average flow velocity, how is it determined?
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Section-C
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Note: Attempt any 2 questions from this section. (15x2=30)
Q.3. (a) Draw neat sketches of various shapes of draft tubes. (5)
Q.4. (a) A compound channel is symmetrical in cross section and has the following geometric properties. Main channel: Trapezoidal cross section, Bottom width = 15.0 m. Side slopes = 1.5 H : IV, Bank full depth = 3.0 m, Manning's coefficient = 0.03, Longitudinal slope = 0.0009 Flood plains: Width = 75 m, Side slope - 1.5 H : IV, Manning's coefficient = 0.05, Longitudinal slope = 0.0009. Compute the uniform flow discharge for a flow with total depth of 4.2 m by using DCM with either (i) diagonal interface, or (ii) vertical interface procedures. (12)
(b) A triangular channel with an apex angle of 75° carries a flow of 1.2 m³/s at a depth of 0.80 m. If the bed slope is 0.009, find the roughness coefficient of the channel. (03)
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Diameter of the impeller (outside diameter)
(ii) Width of the impeller at outlet. (09)
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