A Firstranker's choice
--- Content provided by FirstRanker.com ---
B.Tech. Third Semester (Chemical Engineering) (CGS)
10987 : Process Calculations : 3CHO05/3PP05/3CT 05
Pages: 3 | AW -2998
Time : Three Hours - Max. Marks : 80
Notes : All question carry marks as indicated.
--- Content provided by FirstRanker.com ---
Answer three question from Section A and three question from Section B.
Due credit will be given to neatness and adequate dimensions.
Assume suitable data wherever necessary.
Diagrams and chemical equations should be given wherever necessary.
Illustrate your answer necessary with the help of neat sketches.
--- Content provided by FirstRanker.com ---
Discuss the reaction, mechanism wherever necessary.
Use of cell phone is not allowed in the exam.
Use of pen Blue/Black ink/refill only for writing the answer book.
SECTION - A
-
a) A chemist is interested in preparing 500 ml of 1 normal, 1 molar and 1 molal solution of H2S04. Assuming the density of H2SO4 Solution to be 1.075 g/cm?, calculate the quantities of H2S04 to be taken to prepare these solutions. (7)
--- Content provided by FirstRanker.com ---
b) Spent acid from fertilizer plant has the following composition by weight : H2S04 = 20%, NHsHSO4 = 45%, H20 = 30%, and organic compounds = 5%. Find the total acid content of the spent acid in terms of H2SO4 after adding the acid content chemically bound in ammonium hydrogen sulphate. (7)
OR
-
a) A sample of a gas having volume of 0.5 m³ is compressed in such a manner so that pressure is increased by 60%. The operation is done for a fixed mass of a gas at constant temperature. Calculate the final volume of the gas. (7)
b) A gaseous mixture has the following composition by volume : CO2 = 8%, CO = 14%, 02 = 6%, H20 = 5%, CH4 = 1% and N2 = 66%, Calculate
--- Content provided by FirstRanker.com ---
- Average molecular weight of gas mixture.
- Density of gas mixture at 303 K and 101.325 kPa. (7)
-
The waste acid from a nitrating process containing 20% HNO3, 55% H2SO4 and 25% H.O by weight is to be concentrated by addition of conc. H2SO4 acid containing 95% H2S04 and conc. HNO3 acid containing 90% HNO3 to get desired mixed acid containing 26% HNO3 and 60% H2S04. Calculate the quantities of waste and concentrated acids required for 1000 kg of desired mixed acid. (13)
OR
--- Content provided by FirstRanker.com ---
-
a) The ground nut seeds containing 45% oil and 45% solids are fed to expeller the cake coming out of expeller is found to contain 80% solids and 5% oil. Find the percentage recovery of oil. (7)
b) A feed to a continuous fractionating column analyses by weight 20% benzene and 80% toluene. The analysis of the distillate shows 52 weight % benzene and 5 weight % benzene was found in the bottom product. Calculate the amount of distillate and bottom product per 1000 kg of feed per hour. Also calculate the % recovery of benzene. (6)
-
In production of chlorine gas by oxidation of hydrochloric acid gas, air is used 30% in excess of that theoretically required. Based on 4 Kmol HCI, calculate
--- Content provided by FirstRanker.com ---
- the weight ratio of air to hydrochloric acid gas in feed.
- If oxidation is 80% complete, find the composition of product stream on mole basis. (13)
OR
-
Ethylene oxide is prepared by oxidation of ethylene. 100K mole of ethylene and 100K mole of O2 are charged to a reactor. The percent conversion of ethylene is 85 and percent yield of C2H40 is 94.12, Calculate the composition of product stream leaving the reactor. The reaction taking place are C2H4 + ½O2 —>C2H40 C2H4 +3O2 —>2C02 +2H20 (13)
--- Content provided by FirstRanker.com ---
SECTION - B
-
The gas having the following composition is at temperature of 775 K : SO2 =7.09%, 02 = 10.55%, SO3 = 0.45% and N2 = 81.91%. Calculate the heat content of 1 Kmol gas mixture over 298K using the heat capacity data given below : (‘; =a+bT +cT² +dT° kJ/(Kmol.K) (14)
Gas a bx10³ cx106 dx10? SO2 24.7706 62.948 -44.2582 11.122 O2 26.0257 11.7551 -2.3426 0.05623 SO3 22.0376 121.624 -91.8673 24.3691 N2 29.5909 -5.41 13.1829 -4.968 -
A stream flowing at a rate of 15000 mol/hr containing 25 mole % N2 and 75 mole % H2 is to be heated from 298 K to 473 K. Calculate the heat that must be transferred using Cp data given below : Cp=a+bT+cT² +dT° kI/(KmolK) (8)
--- Content provided by FirstRanker.com ---
Gas a bx10³ cx106 dx10? N2 29.5909 -5.41 13.1829 -4.968 H2 28.6105 1.0194 -0.1476 0.769 OR
-
In a liquid phase heating system, a thermic fluid enters an indirect fired heater at a temperature of 453 K and leaves the heater at a temperature of 533 K. Calculate the heat to be supplied in the heater per kg of the liquid heated. Data : The heat capacity of the fluid is given by C=1.436+2.18x 10?³T kJ/ (kg.K) where T is in K. (13)
-
Obtain an empirical equation for calculating the heat of reaction at any temperature T in K for the reaction : CO(g) +2H2(g) ——> CH3OH(g) Data: ?HR =-90.41 kJ /mol Cp =a+bT+cT² +dT> kJ/(KmolK) (13)
--- Content provided by FirstRanker.com ---
Component a bx10³ cx106 dx10? CO(g) 29.0277 -2.8165 11.6437 -4.7063 H2(g) 28.6105 1.0194 -0.1476 0.769 CH3OH 21.137 70.843 -28.497 25.86 OR
-
a) Discuss in brief the concept of adiabatic process and adiabatic flame temperature. (6)
b) Calculate the standard heat of reaction of the following reaction : C5H12(l) +8 O2(g) —>5 CO2(g) + 6H2O(L) Data :
Component ?Hf kJ/mol at 298 K C5H12(l) -173.49 CO2(g) -393.51 H2O(l) -285.83 (7)
--- Content provided by FirstRanker.com ---
-
The ultimate analysis of a residual fuel oil sample is given below : C =88.4%, H=9.4% and S = 2.2% by weight. It is used as a fuel in a power generating boiler with 25% excess air. Calculate :
- The theoretical dry air requirement
- The actual dry air supplied and
- The orsat analysis of flue gases. (13)
--- Content provided by FirstRanker.com ---
OR
-
a) What do you mean by calorific value ? Discuss in brief the concept of Net Calorific Value (NCV) and Gross Calorific Value (GCV). (6)
b) A sample of fuel oil has C/H ratio 9.33 (by weight) and contains 1.3% sulphur (weight basis). The net calorific value of the fuel oil is 39685 kJ/kg at 298 K. Calculate the gross calorific value using latent heat of water at 298 K. Data : Latent heat of water vapour at 298 K = 2442.5 kJ/kg. (7)
--- Content provided by FirstRanker.com ---
This download link is referred from the post: SGBAU B.Tech Last 10 Years 2010-2020 Question Papers || Sant Gadge Baba Amravati university
--- Content provided by FirstRanker.com ---