Firstranker's choice
DU MSc Genetics
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Topic:- DU_J19_MSC_GENETICS
- Two siblings who inherit 50% of the genome from the mother and 50% from the father show lot of phenotypic differences. Which one of the following events during gametogenesis of the parents will maximally contribute to this difference? [Question ID = 2609]
- Independent assortment [Option ID = 10435]
- Recombination [Option ID = 10434]
- Mutation [Option ID = 10433]
- Environment [Option ID = 10436]
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Correct Answer :-
Mutation [Option ID = 10433]
- Which anti-cancerous drug is obtained from Catharanthus roseus? [Question ID = 2665]
- Serpentine [Option ID = 10659]
- Colchicine [Option ID = 10660]
- Taxol [Option ID = 10657]
- Vincristine [Option ID = 10658]
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Correct Answer :-
Taxol [Option ID = 10657]
- Which of the following statements about C3 and C4 cycle is INCORRECT: [Question ID = 2667]
- Both C3 and C4 cycle uses Rubisco for final CO2 incorporation into sugar [Option ID = 10666]
- Both are pathways of dark reaction of photosynthesis [Option ID = 10665]
- C4 plants have stomata closed during the day and open only at night [Option ID = 10668]
- C4 plants use PEP carboxylase for uptake of CO2 and C3 plants use Rubisco [Option ID = 10667]
Correct Answer :-
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Both are pathways of dark reaction of photosynthesis [Option ID = 10665]
- Which of the following proteins is NOT involved in the process of translation? [Question ID = 2670]
- Ribosomal RNA [Option ID = 10677]
- Elongation factors [Option ID = 10680]
- Aminoacyl tRNA synthetase [Option ID = 10678]
- Initiation factors [Option ID = 10679]
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Correct Answer :-
Ribosomal RNA [Option ID = 10677]
- Which one of the following statements about nitrogen fixation is correct? [Question ID = 2668]
- Plants convert atmospheric nitrogen to ammonia [Option ID = 10669]
- Mutant strains of rhizobium are able to secrete excess protein into the soil [Option ID = 10670]
- The enzyme nitrogenase reduces N2 to form ammonia [Option ID = 10671]
- Ammonia is converted to N2, which is the form of nitrogen most easily absorbed by plants [Option ID = 10672]
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Correct Answer :-
Plants convert atmospheric nitrogen to ammonia [Option ID = 10669]
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- Which one of the following genetic disorders manifests due to defects in nucleotide excision repair? [Question ID = 2661]
- Lynch syndrome [Option ID = 10643]
- Hereditary nonpolyposis colorectal cancer (HNPCC) [Option ID = 10641]
- Xeroderma pigmentosum (XP) [Option ID = 10642]
- Diabetes [Option ID = 10644]
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Correct Answer :-
Hereditary nonpolyposis colorectal cancer (HNPCC) [Option ID = 10641]
- A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 2696]
- The enzyme is an 8-base cutter [Option ID = 10783]
- The enzyme is a 6-base cutter [Option ID = 10782]
- The enzyme is a 4-base cutter [Option ID = 10781]
- This was a partial digest [Option ID = 10784]
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Correct Answer :-
The enzyme is a 4-base cutter [Option ID = 10781]
- An individual has the genotype Aa Bb cc dd Ee. What frequency of gametes will have the genotype abcde? [Question ID = 2617]
- 1/16 [Option ID = 10467]
- 1/8 [Option ID = 10466]
- 1/4 [Option ID = 10465]
- 1/32 [Option ID = 10468]
Correct Answer :-
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1/4 [Option ID = 10465]
- An individual has the genotype Aa Bb. The two genes are linked in cis and are 5cM apart. What percentage of gametes will have the genotype ab? [Question ID = 2618]
- 5 [Option ID = 10470]
- 47.5 [Option ID = 10471]
- 95 [Option ID = 10472]
- 2.5 [Option ID = 10469]
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Correct Answer :-
2.5 [Option ID = 10469]
- A group of blastomeres of the amphibian blastula that can induce gastrulation when placed at an ectopic site is called as: [Question ID = 2657]
- Spemann's organizer [Option ID = 10627]
- Hensen's node [Option ID = 10625]
- Henle's loop [Option ID = 10626]
- Zone of polarizing activity [Option ID = 10628]
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Correct Answer :-
Hensen's node [Option ID = 10625]
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- A group that includes a common ancestor and some descendants is called: [Question ID = 2672]
- allopatric [Option ID = 10688]
- monophyletic [Option ID = 10685]
- polyphyletic [Option ID = 10687]
- paraphyletic [Option ID = 10686]
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Correct Answer :-
monophyletic [Option ID = 10685]
- If half-life of a radioactive material is 15 minutes, how much of a 1mCi sample would be left after 45 minutes? [Question ID = 2647]
- 0.50mCi [Option ID = 10585]
- 0.0625 mCi [Option ID = 10588]
- 0.125mCi [Option ID = 10587]
- 0.250 mCi [Option ID = 10586]
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Correct Answer :-
0.50mCi [Option ID = 10585]
- Regarding protein structure, which, if any, of the following statements is INCORRECT? [Question ID = 2662]
- The structure of an alpha-helix is determined by hydrogen bonding between chemical groups on the side chains. [Option ID = 10648]
- The primary structure is the linear sequence of amino acids. [Option ID = 10645]
- The secondary structure is the path followed by the polypeptide backbone over its length. [Option ID = 10646]
- The secondary structure of every protein contains an alpha-helix. [Option ID = 10647]
Correct Answer :-
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The primary structure is the linear sequence of amino acids. [Option ID = 10645]
- The gene which is suppressed by another non-allelic gene through interaction is known as [Question ID = 2624]
- Homologs [Option ID = 10495]
- Epistatic [Option ID = 10493]
- Pleotropic [Option ID = 10496]
- Hypostatic [Option ID = 10494]
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Correct Answer :-
Epistatic [Option ID = 10493]
- The genetic map for three genes A, B and C is as follows: A-B = 10 map units, B-C = 5 map units and A-C = 15 map units. In an individual of genotype AbC/aBc, the percentage of gametes expected to be ABC is (assume no interference) [Question ID = 2610]
- 0.25 [Option ID = 10437]
- 0.5 [Option ID = 10438]
- 2.5 [Option ID = 10439]
- 5 [Option ID = 10440]
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Correct Answer :-
0.25 [Option ID = 10437]
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- A grasshopper population is being assessed by capture-mark-recapture method. On the first day, 100 grasshoppers were captured from a given area in 1 hour time, marked and released. On the next day during recapture 10 marked and 90 unmarked grasshoppers could be found in the same time period and same area. What is the estimated population of grasshopper in this area? [Question ID = 2630]
- 80 [Option ID = 10517]
- 100 [Option ID = 10518]
- 10000 [Option ID = 10520]
- 1000 [Option ID = 10519]
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Correct Answer :-
80 [Option ID = 10517]
- A group of plants is kept under 12hr light /12 hr dark regimen and it flowers. Another group of plants is kept under similar conditions but given a flash of light during the night period. The plants fail to flower. From these observations we can conclude that the plant is [Question ID = 2695]
- Long day plants [Option ID = 10777]
- Day neutral plants [Option ID = 10779]
- Short day plants [Option ID = 10778]
- Medium day plants [Option ID = 10780]
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Correct Answer :-
Long day plants [Option ID = 10777]
- During splicing the spliceosome complex does not recognize which of the following sites? [Question ID = 2683]
- Branch point [Option ID = 10730]
- Acceptor [Option ID = 10731]
- G-rich site [Option ID = 10732]
- Donor [Option ID = 10729]
Correct Answer :-
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Donor [Option ID = 10729]
- During meiosisI, formation of a ring involving four chromosomes is often an indication of [Question ID = 2635]
- pericentric inversion [Option ID = 10538]
- paracentric inversion [Option ID = 10537]
- tetraploidy [Option ID = 10539]
- reciprocal translocation [Option ID = 10540]
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Correct Answer :-
paracentric inversion [Option ID = 10537]
- The lactose operon in E. coli is an example of: [Question ID = 2699]
- repressible operon with negative regulation only [Option ID = 10793]
- repressible operon with both negative and positive regulation [Option ID = 10795]
- inducible operon with negative regulation only [Option ID = 10794]
- inducible operon with both negative and positive regulation [Option ID = 10796]
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Correct Answer :-
repressible operon with negative regulation only [Option ID = 10793]
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- The most widely accepted theory for the transport of carbohydrates in higher plants is [Question ID = 2674]
- Mass flow theory [Option ID = 10694]
- Osmotic theory [Option ID = 10693]
- Root pressure theory [Option ID = 10695]
- Imbibition theory [Option ID = 10696]
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Correct Answer :-
Osmotic theory [Option ID = 10693]
- Plants dissipate excess excitation energy as heat so as to protect from photo-oxidative damage. The mechanisms known as: [Question ID = 2688]
- Photo-inhibition [Option ID = 10750]
- Non- photochemical quenching [Option ID = 10752]
- Photo chemical quenching [Option ID = 10751]
- Warburg effect [Option ID = 10749]
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Correct Answer :-
Warburg effect [Option ID = 10749]
- With reference to lac operon which of the following merodiploids will show a constitutive expression of ß-galactosidase? [Question ID = 2620]
- I¯OCZ+Y¯ / F' I+O+Z¯Y+ [Option ID = 10478]
- I¯OCZ®Y¯/ F' I+O+Z+Y+ [Option ID = 10480]
- I¯O+Z+Y¯ / F' I+OCZ¯Y+ [Option ID = 10479]
- I¯O+Z+Y¯ / F' I+ O+Z¯Y+ [Option ID = 10477]
Correct Answer :-
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I¯O+Z+Y¯ / F' I+ O+Z¯Y+ [Option ID = 10477]
- How many consensus sequences for splicing are found in an exon? [Question ID = 2686]
- 2 [Option ID = 10743]
- 0 [Option ID = 10741]
- 1 [Option ID = 10742]
- 3 [Option ID = 10744]
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Correct Answer :-
0 [Option ID = 10741]
- How many copies of an allele is likely to be found in a bacterial genome? [Question ID = 2616]
- 2 or more [Option ID = 10463]
- 2 [Option ID = 10462]
- Cannot be predicted as it will depend upon the size of the gene [Option ID = 10464]
- 1 [Option ID = 10461]
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Correct Answer :-
1 [Option ID = 10461]
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- How many membranes will a small molecule diffusing from the cytosol of one mammalian cell to the mitochondrial matrix of the adjoining cell transverse? [Question ID = 2701]
- Two [Option ID = 10801]
- Three [Option ID = 10802]
- Four [Option ID = 10803]
- Five [Option ID = 10804]
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Correct Answer :-
Two [Option ID = 10801]
- The process of replication is: [Question ID = 2606]
- Discontinuous only [Option ID = 10422]
- Semi-conservative and discontinuous [Option ID = 10424]
- Semi-conservative and continuous [Option ID = 10423]
- Semi conservative only [Option ID = 10421]
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Correct Answer :-
Semi conservative only [Option ID = 10421]
- Digestion of a 5kb linear DNA fragment with Eco RI generates two fragments of 2 kb and 3 kb, while digestion of the same molecule with Hind III yields three fragments of 0.7 kb, 3.5 kb and 0.8 kb. When the same DNA is digested with both the enzymes, it yields fragments of 0.7 kb, 1.3 kb, 2.2 kb and 0.8 kb. The right sequence of restriction sites in the DNA fragment is [Question ID = 2648]
- Two Hind III sites followed by only one Eco RI site [Option ID = 10591]
- One Eco RI site in between two Hind III sites [Option ID = 10589]
- One Eco RI site followed by two Hind III sites. [Option ID = 10592]
- One Hind III site in between two Eco RI sites [Option ID = 10590]
Correct Answer :-
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One Eco RI site in between two Hind III sites [Option ID = 10589]
- Zygotic meiosis is a characteristic feature of [Question ID = 2638]
- Gymnosperms [Option ID = 10552]
- Bryophytes [Option ID = 10550]
- Algae [Option ID = 10549]
- Pteridophytes [Option ID = 10551]
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Correct Answer :-
Algae [Option ID = 10549]
- An unknown bacteriophage has a base composition of 23 % G, 36 % C, 21% A, and 20% T. Its genome is likely to be: [Question ID = 2605]
- Double stranded RNA [Option ID = 10418]
- Double stranded DNA [Option ID = 10417]
- Single stranded DNA [Option ID = 10419]
- Single stranded RNA [Option ID = 10420]
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Correct Answer :-
Double stranded DNA [Option ID = 10417]
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- Amensalism is a kind of interaction between two species in which [Question ID = 2604]
- both species have detrimental effect [Option ID = 10415]
- both species have beneficial effect [Option ID = 10416]
- one has the beneficial effect while the other is not affected [Option ID = 10413]
- one has the detrimental effect and the other is not affected [Option ID = 10414]
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Correct Answer :-
one has the beneficial effect while the other is not affected [Option ID = 10413]
- Targeted suppression of gene expression can be achieved through: [Question ID = 2679]
- T-DNA mutagenesis [Option ID = 10714]
- RNA interference [Option ID = 10713]
- Transposon mutagenesis [Option ID = 10715]
- Ethyl methanesulphonate [Option ID = 10716]
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Correct Answer :-
RNA interference [Option ID = 10713]
- Deviation in Hardy-Weinberg equilibrium in a population would be caused by: [Question ID = 2697]
- Random mating [Option ID = 10788]
- Founder effect [Option ID = 10787]
- Lack of selection [Option ID = 10785]
- Large population size [Option ID = 10786]
Correct Answer :-
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Lack of selection [Option ID = 10785]
- Übisch bodies are: [Question ID = 2639]
- callose rich vesicles which get impregnated in the cavities of exine. [Option ID = 10556]
- membrane bound lipoidal bodies that contribute to exine formation. [Option ID = 10553]
- membrane bound proteinaceous bodies that confer recognition reaction. [Option ID = 10555]
- polysaccharidic granules that give species specific exine pattern. [Option ID = 10554]
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Correct Answer :-
membrane bound lipoidal bodies that contribute to exine formation. [Option ID = 10553]
- A chromosomal aberration leads to a change in the order of genes in a genetic map but does not alter its linkage group. This could be due to [Question ID = 2629]
- Translocation [Option ID = 10513]
- Recombination [Option ID = 10514]
- Transposition [Option ID = 10515]
- Inversion [Option ID = 10516]
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Correct Answer :-
Translocation [Option ID = 10513]
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- Contact dermatitis is an example of [Question ID = 2641]
- Cell- mediated hypersensitivity [Option ID = 10563]
- Anaphylaxis hypersensitivity [Option ID = 10562]
- Immune complex hypersensitivity [Option ID = 10564]
- Cytotoxic hypersensitivity [Option ID = 10561]
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Correct Answer :-
Cytotoxic hypersensitivity [Option ID = 10561]
- To make a 1L solution of 0.1N MgCl2 from a 10N stock solution of MgCl2, the volume of H2O and 10N MgCl2 that is needed to be mixed will be: [Question ID = 2700]
- 800ml H2O + 200ml MgCl2 [Option ID = 10799]
- 999ml H2O + 1ml MgCl2 [Option ID = 10798]
- 900ml H2O + 100ml MgCl2 [Option ID = 10797]
- 990ml H2O + 10ml MgCl2 [Option ID = 10800]
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Correct Answer :-
900ml H2O + 100ml MgCl2 [Option ID = 10797]
- Value of which of the following parameter is ZERO when the cell is fully turgid? [Question ID = 2660]
- Turgor pressure [Option ID = 10637]
- Wall pressure [Option ID = 10638]
- Osmotic pressure [Option ID = 10639]
- Diffusion pressure deficit [Option ID = 10640]
Correct Answer :-
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Turgor pressure [Option ID = 10637]
- In order to purify a protein from a given cell extract, which of the following techniques would give maximum purity? [Question ID = 2646]
- Affinity chromatography [Option ID = 10582]
- Anion exchange [Option ID = 10584]
- Cation exchange [Option ID = 10583]
- Gel filtration [Option ID = 10581]
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Correct Answer :-
Gel filtration [Option ID = 10581]
- In order to produce a karyotype, dividing cells are treated with colchicine to: [Question ID = 2632]
- osmotically weaken the nuclear membrane [Option ID = 10527]
- halt cell division at metaphase [Option ID = 10528]
- produce characteristic banding patterns [Option ID = 10526]
- increase condensation of chromosomes [Option ID = 10525]
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Correct Answer :-
increase condensation of chromosomes [Option ID = 10525]
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- Transcription is said to proceed in 5' to 3' direction because: [Question ID = 2637]
- The RNA polymerase attaches itself to the 5' end of the DNA and moves towards the 3' end [Option ID = 10547]
- the incoming rNTP is added onto the free phosphate group at the 3' position of the sugar in the nascent transcript [Option ID = 10548]
- the incoming rNTP is added onto the free OH group at the 5' position of the sugar in the nascent transcript [Option ID = 10545]
- the incoming rNTP is added onto the free OH group at the 3' position of the sugar in the nascent transcript [Option ID = 10546]
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Correct Answer :-
the incoming rNTP is added onto the free OH group at the 5' position of the sugar in the nascent transcript [Option ID = 10545]
- Which type of chemical mutagen are incorporated into the genome by DNA polymerase during replication? [Question ID = 2621]
- Deaminating agents [Option ID = 10483]
- Alkylating agents [Option ID = 10481]
- Intercalating agents [Option ID = 10484]
- Base analogs [Option ID = 10482]
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Correct Answer :-
Alkylating agents [Option ID = 10481]
- Which type of restriction enzymes does not require ATP? [Question ID = 2677]
- Type II [Option ID = 10706]
- Type III [Option ID = 10707]
- Type IV [Option ID = 10708]
- Type I [Option ID = 10705]
Correct Answer :-
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Type I [Option ID = 10705]
- Antigen recognition by an antibody depends on: [Question ID = 2640]
- N-terminal of both heavy and light chain [Option ID = 10560]
- N-terminus of light chain [Option ID = 10559]
- C-terminal of both heavy and light chain [Option ID = 10558]
- C-terminal of heavy chain [Option ID = 10557]
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Correct Answer :-
C-terminal of heavy chain [Option ID = 10557]
- If inheritance of a disease to the next generation is only possible through females, the probable mode of inheritance is: [Question ID = 2627]
- Autosomal [Option ID = 10508]
- Cytoplasmic [Option ID = 10507]
- Mendelian [Option ID = 10505]
- Sex-linked [Option ID = 10506]
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Correct Answer :-
Mendelian [Option ID = 10505]
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- A mutational event inserts bases at the start of the coding sequence of a gene. The highest chance of the altered protein being functional when the number of base(s) inserted is: [Question ID = 2682]
- 1 [Option ID = 10725]
- 4 [Option ID = 10728]
- 2 [Option ID = 10726]
- 3 [Option ID = 10727]
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Correct Answer :-
1 [Option ID = 10725]
- In which of the following cases a heterozygote can be easily distinguished from a homozygote? [Question ID = 2615]
- Recessive epistasis as well as in case of complementary genes [Option ID = 10460]
- Recessive epistasis only [Option ID = 10459]
- Incomplete dominance only [Option ID = 10457]
- Incompletedominance as well as co-dominance [Option ID = 10458]
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Correct Answer :-
Incomplete dominance only [Option ID = 10457]
- Migration of individual cells from the surface into the embryo's interior is termed as [Question ID = 2644]
- Ingression. [Option ID = 10573]
- Delamination. [Option ID = 10576]
- Involution. [Option ID = 10574]
- Invagination. [Option ID = 10575]
Correct Answer :-
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Ingression. [Option ID = 10573]
- A cross is made between a pure breeding plant with red coloured flowers and a pure breeding plant with white coloured flowers. Such a cross is called as a: [Question ID = 2631]
- dihybrid cross [Option ID = 10523]
- back cross [Option ID = 10524]
- test cross [Option ID = 10521]
- monohybrid cross [Option ID = 10522]
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Correct Answer :-
test cross [Option ID = 10521]
- If an mRNA has AUGACCUAACAU sequence, what will be the sequence of the template? [Question ID = 2693]
- ATGTTAGGTCAT [Option ID = 10770]
- TACAATCCAGTA [Option ID = 10772]
- TACTGGATTGTA [Option ID = 10771]
- ATGACCTAACAT [Option ID = 10769]
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Correct Answer :-
ATGACCTAACAT [Option ID = 10769]
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- You have a protein which has the same conformation independent of acidic or basic pH. You separate it on a 10cm long Native PAGE which has been made in buffer with pH 4.5 and you find the protein band to have migrated to 8cm after applying 20mA current for 3hrs. You then separate the protein on a 10cm Native PAGE made with buffer of pH 11 for 3hrs by applying a current of 20mA. How far would the protein band run? [Question ID = 2651]
- 9 cm [Option ID = 10603]
- 4 cm [Option ID = 10601]
- 10 cm [Option ID = 10604]
- 8cm [Option ID = 10602]
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Correct Answer :-
4 cm [Option ID = 10601]
- Peter Mitchell's chemiosmotic hypothesis used inside out submitochondrial vesicles. In an effort to replicate his experiments, you prepare similar vesicles and assay for ATP production. However, you observe that very little ATP is produced in the presence of ADP, O2 and physiological buffer at pH 7. You have already checked for presence of Pi in the buffer. Which of the following will you do next to increase your ATP production? [Question ID = 2669]
- Decrease the pH of the external buffer compared to the inside of vesicles [Option ID = 10673]
- Increase the pH of the external buffer compared to the inside of vesicles [Option ID = 10675]
- Add more ADP into the vesicles [Option ID = 10676]
- Add more ADP to the external buffer [Option ID = 10674]
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Correct Answer :-
Decrease the pH of the external buffer compared to the inside of vesicles [Option ID = 10673]
- Eukaryotic cells and their organelles are disrupted by sonication. Soluble and insoluble components are separated by centirifugation. Protein X is found in the insoluble fraction following centrifugation. The insoluble fraction is treated with 0.5 M NaCl and centrifugation is repeated. Protein X is now found in the soluble fraction. Protein X would be best described as [Question ID = 2666]
- a soluble cytoplasmic protein [Option ID = 10663]
- a soluble nuclear protein [Option ID = 10664]
- an integral membrane protein in an organelle [Option ID = 10661]
- a peripheral membrane protein [Option ID = 10662]
Correct Answer :-
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a soluble cytoplasmic protein [Option ID = 10663]
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