GUJARAT TECHNOLOGICAL UNIVERSITY
BE - SEMESTER-IV (NEW) EXAMINATION - WINTER 2018
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Subject Code:2141407
Subject Name:Food Drying & Dehydration
Time: 02:30 PM TO 05:00 PM
Instructions:
- Attempt all questions.
- Make suitable assumptions wherever necessary.
- Figures to the right indicate full marks.
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Q1
- What is equilibrium moisture content? Write its significance also. (03)
- Differentiate between direct and indirect dryer. List out the characteristics and properties of various types of dry powders and particulate. (04)
- Describe the drying rates periods for agricultural products. Derive equation for constant rate drying. (07)
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OR
- List out all the unique features of drying. (03)
- Discuss Parallel, Series and Krisher models to predict thermal conductivity. (04)
- The initial moisture content of a food product is 70% (wet basis), and the critical moisture content is 25% (wet basis). If the constant drying rate is 0.1 kg H20/(m?s), compute the time required for the product to begin the falling rate drying period. The product has a cube shape with 5-cm sides, and the initial product density is 900 kg/m?. (07)
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Q2
- Draw the following generalised curve for the agricultural materials:
- Drying curve
- Drying rate curve
- Water activity stability diagram
- Moisture content and bed depth for different inlet temperature
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- Compute the equilibrium moisture content for popcorn at 20°C and 50% relative humidity. Given that constant ¢ = 6.5 x 10 and n=1.8 (04)
- What is moisture sorption curve? Describe the phenomena of hysteresis. (07)
OR
- Define wet and dry basis moisture content and write the expression to convert wet basis to dry basis moisture content. (03)
- 500 kg of paddy at 22 % moisture content (wb) is dried tol4 % moisture content (wb) for milling. Calculate the amount of moisture removed in drying (04)
- Discuss in brief the features of solar drying. (07)
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Q3
- Give a detail classification of dryers used in food industry. (03)
- A food containing 80% water is to be dried at 100°C down to moisture content of 10%. If the initial temperature of the food is 21°C, calculate the quantity of heat energy required per unit weight of the original material, for drying under atmospheric pressure. The latent heat of vaporization of water at 100°C and at standard atmospheric pressure is 2257 kJ kg™!. The specific heat capacity of the food is 3.8 kJ kg™! °C! and of water is 4.186 kJ kg! °C"L. Find also the energy requirement/kg water removed. (04)
- Discuss the advantage of osmotic dehydration. (07)
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OR
- What are features of fluidized bed dryer? (03)
- Describe the principle for selection of dryer in food industry. (04)
- Explain the construction, working and application of following:
- Freeze Dryer
- Spray Dryer
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Q4
- A cabinet dryer is being used to dry a food product from 70 % moisture content (w.b.) to 6% moisture content (w.b.). The drying air enters the system at 54 °C and 10% RH and leaves at 30 °C and 70% RH. The product temperature is 25 °C throughout. Calculate the quantity of air required for drying on the basis of 1 kg of product solid. Given absolute humidity of air at 30 °C & 70% RH=0.0186 kg H>O/kg dry air 54 9C & 10% RH=0.0094 kg H>O/kg dry air (07)
OR
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- Explain the concept of hybrid drying. (03)
- What is heat pump dryer? Explain its'working. (04)
- Describe the construction and features of super heated steam drying? (07)
Q5
- Define thin layer and deep bed drying. (03)
- Describe the physical properties of dried foods. (04)
- Write short notes on:
- Water activity
- Rehydration ratio
- Shrinkage during drying
- Heat utilization factor
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Date:12/12/2018
Total Marks: 70
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