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Delhi University Entrance Test (DUET) 2020 Previous Year Question Paper With Answer Key

This post was last modified on 27 December 2020

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Topic:- BIOCHEM MSC S2

What would be the effect on the net reaction catalyzed by glyceraldehyde 3-phosphate dehydrogenase if phosphate was replaced by arsenate? [Question ID = 2609]
1. Rate of reaction will increase [Option ID = 10430]
2. Rate will be decreased [Option ID = 10431]
3. No effect on reaction rate [Option ID = 10432]
4. Uncoupling of phosphorylation [Option ID = 10433]
Correct Answer :-
- Uncoupling of phosphorylation [Option ID = 10433]
Cellular membranes are self sealing in nature- if they are punctured or disrupted mechanically they quickly and automatically reseal. What properties of such sealing are responsible for this feature? [Question ID = 2610]
1. hydrophobic effect of membrane lipids [Option ID = 10434]
2. hydrophilic effect of membrane lipids [Option ID = 10435]
3. charge-charge interaction among lipids [Option ID = 10436]
4. protein-lipid interactions [Option ID = 10437]
Correct Answer :-
- hydrophobic effect of membrane lipids [Option ID = 10434]

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What type of chemical reaction is involved in conversion of isocitrate to a-ketoglutarate ? [Question ID = 2611]
1. Caboxylation [Option ID = 10438]
2. Oxidative decarboxylation [Option ID = 10439]
3. Reducing decarboxylation [Option ID = 10440]
4. Oxido-reduction [Option ID = 10441]
Correct Answer :-
- Oxidative decarboxylation [Option ID = 10439]
Individuals can have relatively high levels of pyruvate in their blood due to: [Question ID = 2612]
1. Vitamin B deficiency [Option ID = 10442]
2. Vitamin D deficiency [Option ID = 10443]
3. Thiamine deficiency [Option ID = 10444]
4. Alcohol intake [Option ID = 10445]
Correct Answer :-
- Thiamine deficiency [Option ID = 10444]
Mammalian liver can carry out gluconeogenisis using starting material known as: [Question ID = 2613]
1. Oxaloacetate [Option ID = 10446]
2. Acetyl-CoA [Option ID = 10447]
3. Citric acid [Option ID = 10448]
4. Aspartate [Option ID = 10449]
Correct Answer :-
- Oxaloacetate [Option ID = 10446]
Maple syrup urine disease is due to a metabolic defect in the pathway of degradation of : [Question ID = 2614]
1. Branched chain fatty acids [Option ID = 10450]
2. Cholesterol [Option ID = 10451]
3. Nucleotide [Option ID = 10452]
4. Branched chain amino acids [Option ID = 10453]
Correct Answer :-
- Branched chain amino acids [Option ID = 10453]
The specificity or stringency of a PCR reaction can be controlled by altering the reaction [Question ID = 2615]
1. volume [Option ID = 10454]
2. target sequence [Option ID = 10455]
3. temperature and salt concentration [Option ID = 10456]
4. template and salt concentration [Option ID = 10457]
Correct Answer :-
- temperature and salt concentration [Option ID = 10456]

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Principle regulation point in the biosynthesis of fatty acids is: [Question ID = 2616]
1. Acetyl-CoA carboxylase [Option ID = 10458]
2. B Ketoacyl-ACP synthase [Option ID = 10459]
3. Citrate dehydrogenase [Option ID = 10460]
4. B Lactamase [Option ID = 10461]
Correct Answer :-
- Acetyl-CoA carboxylase [Option ID = 10458]
Denaturation of a protein or nucleic acid can be studied by: [Question ID = 2617]
1. SDS-PAGE [Option ID = 10462]
2. Isoelectric focusing [Option ID = 10463]
3. Spectrophotometry [Option ID = 10464]
4. Gel filtration [Option ID = 10465]
Correct Answer :-
- Spectrophotometry [Option ID = 10464]
Folding of a protein is primarily governed by: [Question ID = 2618]
1. Ionic strength of solution [Option ID = 10466]
2. Presence of branched chain amino acids [Option ID = 10467]
3. Primary structure of a protein [Option ID = 10468]
4. Presence of hydrophobic amino acids [Option ID = 10469]
Correct Answer :-
- Primary structure of a protein [Option ID = 10468]
The biochemical products obtained after hydrolysis of glycolipids are: [Question ID = 2619]
1. Sugar, fatty acids, phosphoric acid [Option ID = 10470]
2. Sugar, fatty acids, nitrogen base [Option ID = 10471]
3. Sugar, fatty acid, glycerol [Option ID = 10472]
4. Sugar, fatty acid, sphingosine [Option ID = 10473]
Correct Answer :-
- Sugar, fatty acid, glycerol [Option ID = 10472]
D-glucose and D-mannose are: [Question ID = 2620]
1. Anomers [Option ID = 10474]
2. Epimers [Option ID = 10475]
3. Optical isomers [Option ID = 10476]
4. Diastereomers [Option ID = 10477]
Correct Answer :-
- Epimers [Option ID = 10475]

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Collagen is rich in: [Question ID = 2621]
1. Glutamic acid and glycine [Option ID = 10478]
2. Glycine and glutamine [Option ID = 10479]
3. Glycine and proline [Option ID = 10480]
4. Glycine and alanine [Option ID = 10481]
Correct Answer :-
- Glycine and proline [Option ID = 10480]
The following amino acid is least likely to be found in a a-helix structure: [Question ID = 2622]
1. Alanine [Option ID = 10482]
2. Cystine [Option ID = 10483]
3. Histidine [Option ID = 10484]
4. Proline [Option ID = 10485]
Correct Answer :-
- Proline [Option ID = 10485]
If pKa of an acid is 6.0, what proportion of the acid is ionized at pH 7.0? [Question ID = 2623]
1. 3.0 [Option ID = 10486]
2. 11.0 [Option ID = 10487]
3. 10.0 [Option ID = 10488]
4. 12.0 [Option ID = 10489]
Correct Answer :-
- 12.0 [Option ID = 10489]
A HCl solution of 1 mM was diluted to 10⁶. What would be the pH of the resulting solution? [Question ID = 2624]
1. 5.0 [Option ID = 10490]
2. 7.0 [Option ID = 10491]
3. 6.0 [Option ID = 10492]
4. 2.0 [Option ID = 10493]
Correct Answer :-
- 7.0 [Option ID = 10491]
The ligand used for affinity chromatography of RNA containing poly(A) sequence is: [Question ID = 2625]
1. Avidin [Option ID = 10494]
2. 5' AMP [Option ID = 10495]
3. Oligo dT [Option ID = 10496]
4. Lysine [Option ID = 10497]
Correct Answer :-
- Oligo dT [Option ID = 10496]

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Signal hypothesis for protein trafficking was proposed by: [Question ID = 2626]
1. Tom Rapoport [Option ID = 10498]
2. Paul Nurse [Option ID = 10499]
3. Timothy Hunt [Option ID = 10500]
4. Gunter Blobel [Option ID = 10501]
Correct Answer :-
- Gunter Blobel [Option ID = 10501]
In SDS-PAGE, the migration of protein is effected by [Question ID = 2627]
1. Charge of the protein [Option ID = 10502]
2. Size of the protein [Option ID = 10503]
3. Both charge and size of the protein [Option ID = 10504]
4. Number of cysteine residues in protein [Option ID = 10505]
Correct Answer :-
- Size of the protein [Option ID = 10503]
Glycerol is added to protein samples before loading them on the PAGE. What is the role of glycerol- [Question ID = 2628]
1. Provide stability to protein [Option ID = 10506]
2. Helps to bind SDS to the protein [Option ID = 10507]
3. Provide density to the protein sample [Option ID = 10508]
4. Helps in denaturing the disulphide bonds [Option ID = 10509]
Correct Answer :-
- Provide density to the protein sample [Option ID = 10508]
What is the effect of urea and formamide on DNA [Question ID = 2629]
1. Decrease the Tm of the DNA [Option ID = 10510]
2. Increase the Tm of the DNA [Option ID = 10511]
3. Helps in reannealing of the DNA [Option ID = 10512]
4. Stabilized DNA structure [Option ID = 10513]
Correct Answer :-
- Decrease the Tm of the DNA [Option ID = 10510]
A low auxin: cytokinin ratio leads to - [Question ID = 2630]
1. Shoot formation [Option ID = 10514]
2. Root formation [Option ID = 10515]
3. Fruit formation [Option ID = 10516]
4. Increased cell division [Option ID = 10517]
Correct Answer :-
- Shoot formation [Option ID = 10514]

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Megaloblastic anemia is caused due to deficiency of [Question ID = 2631]
1. Cobalamin [Option ID = 10518]
2. Pyridoxine [Option ID = 10519]
3. Folic acid [Option ID = 10520]
4. Niacin [Option ID = 10521]
Correct Answer :-
- Folic acid [Option ID = 10520]
Lineweaver-Burk plot is also known as [Question ID = 2632]
1. Hanes-Woolf plot [Option ID = 10522]
2. Double reciprocal plot [Option ID = 10523]
3. Eadie-Hofstee plot [Option ID = 10524]
4. Steady-state equation [Option ID = 10525]
Correct Answer :-
- Double reciprocal plot [Option ID = 10523]
Which of the following can be used to construct a linkage map of the Hfr chromosome? [Question ID = 2633]
1. frequency of recombination [Option ID = 10526]
2. time of entry [Option ID = 10527]
3. locus of mutation [Option ID = 10528]
4. transfer of F factor [Option ID = 10529]
Correct Answer :-
- time of entry [Option ID = 10527]
Which of the following conditions decreases the level of denitrification? [Question ID = 2634]
1. Abundance of organic matter [Option ID = 10530]
2. Elevated temperatures [Option ID = 10531]
3. Availability of oxygen [Option ID = 10532]
4. Acidic pH [Option ID = 10533]
Correct Answer :-
- Acidic pH [Option ID = 10533]
Name the class of immunoglobulin which takes part in hypersensitivity reaction? [Question ID = 2635]
1. IgG [Option ID = 10534]
2. IgE [Option ID = 10535]
3. IgA [Option ID = 10536]
4. IgM [Option ID = 10537]
Correct Answer :-
- IgE [Option ID = 10535]

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In Phase contrast microscopy, the rate at which light passes through objects is [Question ID = 2636]
1. Inversely proportional to their refractive indices [Option ID = 10538]
2. Constant [Option ID = 10539]
3. Directly proportional to their refractive indices [Option ID = 10540]
4. Exponentially related to their refractive indices [Option ID = 10541]
Correct Answer :-
- Inversely proportional to their refractive indices [Option ID = 10538]
The biosynthesis of proline takes place from [Question ID = 2637]
1. aspartic acid [Option ID = 10542]
2. glutamic acid [Option ID = 10543]
3. pyruvic acid [Option ID = 10544]
4. alpha-keto glutaric acid [Option ID = 10545]
Correct Answer :-
- glutamic acid [Option ID = 10543]
The density of a solution prepared by dissolving 120 g of urea (mol.mass = 60) in 1000 g of water is 1.15 g/mL. The molarity of this solution is: [Question ID = 2638]
1. 1.02 M [Option ID = 10546]
2. 2.05 M [Option ID = 10547]
3. 0.50 M [Option ID = 10548]
4. 1.78 M [Option ID = 10549]
Correct Answer :-
- 2.05 M [Option ID = 10547]
The third strand of triple helix is paired in which scheme? [Question ID = 2639]
1. Intermolecular base pair scheme [Option ID = 10550]
2. Hoogsteen base pair scheme [Option ID = 10551]
3. Intramolecular base pair scheme [Option ID = 10552]
4. G-quartet scheme [Option ID = 10553]
Correct Answer :-
- Hoogsteen base pair scheme [Option ID = 10551]
The first three bases of the 6-base recognition cleavage site of HindIll are AAG. What is the complete sequence of this 6 bp site? [Question ID = 2640]
1. AAGAAG [Option ID = 10554]
2. AAGCTT [Option ID = 10555]
3. AAGGAA [Option ID = 10556]
4. AAGCUU [Option ID = 10557]
Correct Answer :-
- AAGCTT [Option ID = 10555]

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What leads to the activation of protein kinase C? [Question ID = 2641]
1. Release of intracellular Ca⁺² + diacylglycerol [Option ID = 10558]
2. Release of intracellular Mg⁺² + diacylglycerol [Option ID = 10559]
3. Release of intracellular Ca⁺² + glycerol [Option ID = 10560]
4. Release of intracellular Ca⁺² + triacylglycerol [Option ID = 10561]
Correct Answer :-
- Release of intracellular Ca⁺² + diacylglycerol [Option ID = 10558]
Trans bilayer diffusion is also called [Question ID = 2642]
1. Facilitated diffusion [Option ID = 10562]
2. Lateral diffusion [Option ID = 10563]
3. Flip flop [Option ID = 10564]
4. Simple diffusion [Option ID = 10565]
Correct Answer :-
- Flip flop [Option ID = 10564]
The first step in the payoff phase of glycolysis is [Question ID = 2643]
1. Reduction of 1, 3-bisphosphoglycerate to glyceraldehyde 3-phosphate [Option ID = 10566]
2. Oxidation of glyceraldehyde 3-phosphate to 1, 3-bisphosphoglycerate [Option ID = 10567]
3. Reversible conversion of dihydroxyacetone phosphate to glyceraldehyde 3-phosphate [Option ID = 10568]
4. Irreversible conversion of dihydroxyacetone phosphate to glyceraldehyde 3-phosphate [Option ID = 10569]
Correct Answer :-
- Oxidation of glyceraldehyde 3-phosphate to 1, 3-bisphosphoglycerate [Option ID = 10567]
What region of antibody binds to protein antigen? [Question ID = 2644]
1. Fc region [Option ID = 10570]
2. Heavy chain within the Fc region [Option ID = 10571]
3. Light chain within the Fab region [Option ID = 10572]
4. Light chain within the Fc region [Option ID = 10573]
Correct Answer :-
- Heavy chain within the Fc region [Option ID = 10570]
If the oxidative phosphorylation was uncoupled in the mitochondria then there is a/an [Question ID = 2645]
1. Decreased concentration of ADP in the mitochondria [Option ID = 10574]
2. Decreased oxidative rate [Option ID = 10575]
3. Increased inorganic phosphate in the mitochondria [Option ID = 10576]
4. Decreased production of heat [Option ID = 10577]
Correct Answer :-
- Increased inorganic phosphate in the mitochondria [Option ID = 10576]

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The enzyme responsible for the removal of supercoiling in replicating DNA ahead of the replication fork is [Question ID = 2646]
1. Topoisomerase [Option ID = 10578]
2. Primase [Option ID = 10579]
3. DNA polymerase [Option ID = 10580]
4. Helicase [Option ID = 10581]
Correct Answer :-
- Topoisomerase [Option ID = 10578]
Which of the following are not DNA viruses? [Question ID = 2647]
1. Hepatitis B virus [Option ID = 10582]
2. Influenza A virus [Option ID = 10583]
3. CMV virus [Option ID = 10584]
4. Parvovirus [Option ID = 10585]
Correct Answer :-
- Influenza A virus [Option ID = 10583]
Formation of one molecule of glucose from pyruvate requires [Question ID = 2648]
1. 4 ATP, 2 GTP and 2 NADH [Option ID = 10586]
2. 3 ATP, 2 GTP and 2 NADH [Option ID = 10587]
3. 4 ATP, 1 GTP and 2 NADH [Option ID = 10588]
4. 2 ATP, 2 GTP and 2 NADH [Option ID = 10589]
Correct Answer :-
- 4 ATP, 2 GTP and 2 NADH [Option ID = 10586]
Cyanogen bromide is used for cleavage of proteins. The target site for cleavage is: [Question ID = 2649]
1. C-terminal end of Asparagine residue [Option ID = 10590]
2. C-terminal end of Methionine residue [Option ID = 10591]
3. C-terminal end of Glycine residue [Option ID = 10592]
4. C-terminal end of Proline residue [Option ID = 10593]
Correct Answer :-
- C-terminal end of Methionine residue [Option ID = 10591]
Who won the Noble prize in medicine in 2018 for their discovery of cancer therapy by inhibition of negative immune regulation? [Question ID = 2650]
1. James P. Allison, Tasuku Honjo [Option ID = 10594]
2. Michael W. Young, Michael Rosbash, Jeffrey C. Hall [Option ID = 10595]
3. William G. Kaelin, Gregg L. Semenza, Peter J. Ratcliffe [Option ID = 10596]
4. Shinya Yamanaka, John Gurdon [Option ID = 10597]
Correct Answer :-
- James P. Allison, Tasuku Honjo [Option ID = 10594]

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The biological role of restriction enzymes in bacteria is to:- [Question ID = 2651]
1. repair DNA [Option ID = 10598]
2. induce DNA crossover [Option ID = 10599]
3. cleave foreign DNA [Option ID = 10600]
4. recombine DNA [Option ID = 10601]
Correct Answer :-
- cleave foreign DNA [Option ID = 10600]
Which of the following DNA sequences contains a 4-8 base palindromic site? (Note: Only one strand is shown.) [Question ID = 2652]
1. CAGTCC [Option ID = 10602]
2. GCATATGC [Option ID = 10603]
3. CGATTAGC [Option ID = 10604]
4. GAGAGAGA [Option ID = 10605]
Correct Answer :-
- GCATATGC [Option ID = 10603]
Which of the following components is not a constituent of a typical A-tailing reaction? [Question ID = 2653]
1. Klenow exo- [Option ID = 10606]
2. ATP [Option ID = 10607]
3. Taq DNA polymerase [Option ID = 10608]
4. Blunt end DNA [Option ID = 10609]
Correct Answer :-
- ATP [Option ID = 10607]
Presence of salt during gel filtration helps to [Question ID = 2654]
1. Allow separation of proteins of same molecular weight [Option ID = 10610]
2. Allow separation of proteins on basis of pI along with molecular weight [Option ID = 10611]
3. Reduce non-specific interaction of proteins with gel matrix [Option ID = 10612]
4. Reduce the proteolytic degradation of proteins during purification [Option ID = 10613]
Correct Answer :-
- Reduce non-specific interaction of proteins with gel matrix [Option ID = 10612]
HAT medium used for hybridoma production contains [Question ID = 2655]
1. Thymidylate synthase [Option ID = 10614]
2. Thymidine kinase [Option ID = 10615]
3. Thymidine [Option ID = 10616]
4. Thiamine [Option ID = 10617]
Correct Answer :-
- Thymidine [Option ID = 10616]

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Which of the following class of antibodies are expected to be immuno-precipitated predominantly using anti-J chain antibodies ? [Question ID = 2656]
1. IgG [Option ID = 10618]
2. IgM [Option ID = 10619]
3. IgD [Option ID = 10620]
4. IgE [Option ID = 10621]
Correct Answer :-
- IgM [Option ID = 10619]
Which of the following antibodies is most efficient in causing agglutination? [Question ID = 2657]
1. IgM [Option ID = 10622]
2. IgD [Option ID = 10623]
3. IgG [Option ID = 10624]
4. IgE [Option ID = 10625]
Correct Answer :-
- IgM [Option ID = 10622]
An unknown bacteriophage has a base composition of 23% A, 36% T, 21% G, and 20% C. Its genome is likely to be: [Question ID = 2658]
1. Single stranded RNA [Option ID = 10626]
2. Single stranded DNA [Option ID = 10627]
3. Double stranded RNA [Option ID = 10628]
4. Double stranded DNA [Option ID = 10629]
Correct Answer :-
- Single stranded DNA [Option ID = 10627]
During the growth of mammalian cells, the growth media was supplemented with radioactive amino acids. Which of the following macromolecules is likely to be radiolabeled? [Question ID = 2659]
1. Proteins [Option ID = 10630]
2. DNA [Option ID = 10631]
3. RNA [Option ID = 10632]
4. Glycolipids [Option ID = 10633]
Correct Answer :-
- Proteins [Option ID = 10630]
An Indian student applied for post doctorate fellowship in Singapore and was asked to undergo test for Tuberculosis. He went to AIIMS, New Delhi for testing. The Tuberculin skin test (1st test) turned out to be positive, however, culture-based confirmation test (2nd test) revealed that he was negative for tuberculosis. What is the most likely reason for this observation? [Question ID = 2660]
1. The student had autoimmune antibodies [Option ID = 10634]
2. The student was vaccinated with BCG [Option ID = 10635]
3. The 1st test was not performed correctly [Option ID = 10636]
4. The 2nd test was not performed correctly [Option ID = 10637]
Correct Answer :-
- The
  This download link is referred from the post: DUET Last 10 Years 2011-2021 Question Papers With Answer Key || Delhi University Entrance Test conducted by the NTA
  --- Content provided by FirstRanker.com ---

This post was last modified on 27 December 2020

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