1)
2)
3)
4)
5)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
1)
2)
3)
4)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
7)
8)
9)
10)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
1)
2)
3)
4)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
7)
8)
9)
10)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
14)
15)
16)
17)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
1)
2)
3)
4)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
7)
8)
9)
10)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
14)
15)
16)
17)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
20)
21)
22)
23)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
ii. Requires minimal space to cultivate
iii. Genome has been sequenced [Question ID = 52745]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
Correct Answer :-
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
RNA interference. [Option ID = 91129]
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
D-lysine [Option ID = 91126]
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
FirstRanker.com - FirstRanker's Choice
1)
2)
3)
5)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
1. AT to GC [Option ID = 91074]
7)
8)
9)
11)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
Correct Answer :-
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
13)
14)
15)
16)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
19)
20)
21)
22)
24)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
i. Short life cycle
ii. Requires minimal space to cultivate
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
4. Interphase [Option ID = 91059]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
1. equal to that of the G1 cell [Option ID = 91024]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
above?
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
4. [Option ID = 90948]
Correct Answer :-
FirstRanker.com - FirstRanker's Choice
1)
3)
4)
5)
6)
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
7)
9)
10)
11)
12)
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
Correct Answer :-
AT to GC [Option ID = 91074]
site of accumulation when a 5min [
3
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
4. four [Option ID = 91070]
Correct Answer :-
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
Correct Answer :-
24 [Option ID = 91049]
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
Correct Answer :-
thermostability [Option ID = 91105]
13)
14)
16)
17)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
4. Peptide. [Option ID = 91108]
Correct Answer :-
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
19)
20)
22)
23)
24)
25)
i. Short life cycle
iii. Genome has been sequenced [Question ID = 52745]
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
4. (ii) only [Option ID = 90973]
Correct Answer :-
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
Correct Answer :-
RNA interference. [Option ID = 91129]
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
4. Interphase [Option ID = 91059]
Correct Answer :-
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
Correct Answer :-
D-lysine [Option ID = 91126]
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
1. equal to that of the G1 cell [Option ID = 91024]
26)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
4. 160 [Option ID = 91045]
Correct Answer :-
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
above?
[Question ID = 52739]
2. [Option ID = 90951]
3. [Option ID = 90950]
4. [Option ID = 90948]
Correct Answer :-
29)
[Option ID = 90949]
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
a. DU
1
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Activity of genet in
Control cells Treated cells
DU
1
05 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
[Question ID = 52737]
1. [Option ID = 90943]
2. [Option ID = 90940]
3. [Option ID = 90942]
Correct Answer :-
[Option ID = 90941]
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
1)
2)
3)
4)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
7)
8)
9)
10)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
14)
15)
16)
17)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
20)
21)
22)
23)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
ii. Requires minimal space to cultivate
iii. Genome has been sequenced [Question ID = 52745]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
Correct Answer :-
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
RNA interference. [Option ID = 91129]
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
D-lysine [Option ID = 91126]
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
Correct Answer :-
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
3. [Option ID = 90950]
Correct Answer :-
28)
29)
[Option ID = 90949]
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
1
b. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Control cells Treated cells
Wild type 100 40
DU
1
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
iii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
1. [Option ID = 90943]
3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
[Option ID = 90941]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
32)
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
FirstRanker.com - FirstRanker's Choice
1)
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3)
5)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
1. AT to GC [Option ID = 91074]
7)
8)
9)
11)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
Correct Answer :-
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
13)
14)
15)
16)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
19)
20)
21)
22)
24)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
i. Short life cycle
ii. Requires minimal space to cultivate
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
4. Interphase [Option ID = 91059]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
1. equal to that of the G1 cell [Option ID = 91024]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
above?
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
4. [Option ID = 90948]
Correct Answer :-
28)
29)
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Activity of genet in
Control cells Treated cells
Wild type 100 40
DU
05 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
2. [Option ID = 90940]
3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
[Question ID = 52777]
33)
1. (i) (iv) and (v) [Option ID = 91103]
2. (i) (iii) and (v) [Option ID = 91102]
4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
(i) (iii) and (iv) [Option ID = 91100]
[Question ID = 52786]
2. [Option ID = 91138]
3. [Option ID = 91139]
FirstRanker.com - FirstRanker's Choice
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4)
5)
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Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
7)
9)
10)
11)
12)
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
Correct Answer :-
AT to GC [Option ID = 91074]
site of accumulation when a 5min [
3
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
4. four [Option ID = 91070]
Correct Answer :-
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
Correct Answer :-
24 [Option ID = 91049]
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
Correct Answer :-
thermostability [Option ID = 91105]
13)
14)
16)
17)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
4. Peptide. [Option ID = 91108]
Correct Answer :-
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
19)
20)
22)
23)
24)
25)
i. Short life cycle
iii. Genome has been sequenced [Question ID = 52745]
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
4. (ii) only [Option ID = 90973]
Correct Answer :-
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
Correct Answer :-
RNA interference. [Option ID = 91129]
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
4. Interphase [Option ID = 91059]
Correct Answer :-
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
Correct Answer :-
D-lysine [Option ID = 91126]
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
1. equal to that of the G1 cell [Option ID = 91024]
26)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
4. 160 [Option ID = 91045]
Correct Answer :-
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
above?
[Question ID = 52739]
2. [Option ID = 90951]
3. [Option ID = 90950]
4. [Option ID = 90948]
Correct Answer :-
29)
[Option ID = 90949]
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
a. DU
1
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Activity of genet in
Control cells Treated cells
DU
1
05 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
[Question ID = 52737]
1. [Option ID = 90943]
2. [Option ID = 90940]
3. [Option ID = 90942]
Correct Answer :-
[Option ID = 90941]
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
31)
32)
[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
[Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
[Question ID = 52777]
33)
2. (i) (iii) and (v) [Option ID = 91102]
3. (i) (iii) and (iv) [Option ID = 91100]
4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
[Question ID = 52786]
1. [Option ID = 91137]
2. [Option ID = 91138]
3. [Option ID = 91139]
35)
4. [Option ID = 91136]
Correct Answer :-
[Option ID = 91138]
1. [Option ID = 90945]
2. [Option ID = 90946]
3. [Option ID = 90947]
4. [Option ID = 90944]
[Option ID = 90945]
[Question ID = 52749]
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Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
7)
9)
10)
11)
12)
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
Correct Answer :-
AT to GC [Option ID = 91074]
site of accumulation when a 5min [
3
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
4. four [Option ID = 91070]
Correct Answer :-
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
Correct Answer :-
24 [Option ID = 91049]
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
Correct Answer :-
thermostability [Option ID = 91105]
13)
14)
16)
17)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
4. Peptide. [Option ID = 91108]
Correct Answer :-
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
19)
20)
22)
23)
24)
25)
i. Short life cycle
iii. Genome has been sequenced [Question ID = 52745]
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
4. (ii) only [Option ID = 90973]
Correct Answer :-
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
Correct Answer :-
RNA interference. [Option ID = 91129]
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
4. Interphase [Option ID = 91059]
Correct Answer :-
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
Correct Answer :-
D-lysine [Option ID = 91126]
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
1. equal to that of the G1 cell [Option ID = 91024]
26)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
4. 160 [Option ID = 91045]
Correct Answer :-
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
above?
[Question ID = 52739]
2. [Option ID = 90951]
3. [Option ID = 90950]
4. [Option ID = 90948]
Correct Answer :-
29)
[Option ID = 90949]
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
a. DU
1
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Activity of genet in
Control cells Treated cells
DU
1
05 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
[Question ID = 52737]
1. [Option ID = 90943]
2. [Option ID = 90940]
3. [Option ID = 90942]
Correct Answer :-
[Option ID = 90941]
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
31)
32)
[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
[Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
[Question ID = 52777]
33)
2. (i) (iii) and (v) [Option ID = 91102]
3. (i) (iii) and (iv) [Option ID = 91100]
4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
[Question ID = 52786]
1. [Option ID = 91137]
2. [Option ID = 91138]
3. [Option ID = 91139]
35)
4. [Option ID = 91136]
Correct Answer :-
[Option ID = 91138]
1. [Option ID = 90945]
2. [Option ID = 90946]
3. [Option ID = 90947]
4. [Option ID = 90944]
[Option ID = 90945]
[Question ID = 52749]
36)
37)
39)
40)
41)
1. One [Option ID = 90988]
3. Four [Option ID = 90991]
4. Two [Option ID = 90989]
Correct Answer :-
Two [Option ID = 90989]
1. 3 genotypes; 4 phenotypes [Option ID = 91020]
2. 3 genotypes; 3 phenotypes [Option ID = 91022]
3. 4 genotypes; 3 phenotypes [Option ID = 91023]
4. 4 genotypes; 4 phenotypes [Option ID = 91021]
4 genotypes; 3 phenotypes [Option ID = 91023]
Human beings carrying the dominant allele R can roll their tongue. In a population in which the frequency of this allele is 0.8, what is
the probability that a particular individual who can roll his/her tongue is homozygous?
[Question ID = 52776]
2. 0.96 [Option ID = 91098]
3. 0.66 [Option ID = 91099]
4. 0.64 [Option ID = 91096]
Correct Answer :-
A PCR reaction that continues for 30 cycles will produce approximately how many PCR products from a single template DNA
molecule? [Question ID = 52744]
1. ~ 1 billion [Option ID = 90971]
2. ~ 1 million [Option ID = 90970]
4. 64 [Option ID = 90968]
Correct Answer :-
~ 1 billion [Option ID = 90971]
In a cell undergoing meiosis, the number of copies of a gene at Metaphase I, Anaphase I and Metaphase II would be: [Question ID =
1. 4, 4, 4 [Option ID = 91012]
2. 4, 4, 2 [Option ID = 91014]
3. 2, 2, 4 [Option ID = 91015]
4. 2, 2, 2 [Option ID = 91013]
4, 4, 2 [Option ID = 91014]
Which of the following protein maintained at constant levels throughout the cell cycle and requires for cyclin to become catalytically
active? [Question ID = 52765]
1. Cyclins [Option ID = 91054]
3. Cyclin dependent kinases (Cdk) [Option ID = 91055]
4. Protein kinase [Option ID = 91053]
Correct Answer :-
Cyclin dependent kinases (Cdk) [Option ID = 91055]
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DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
1. AT to GC [Option ID = 91074]
7)
8)
9)
11)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
Correct Answer :-
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
13)
14)
15)
16)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
19)
20)
21)
22)
24)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
i. Short life cycle
ii. Requires minimal space to cultivate
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
4. Interphase [Option ID = 91059]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
1. equal to that of the G1 cell [Option ID = 91024]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
above?
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
4. [Option ID = 90948]
Correct Answer :-
28)
29)
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Activity of genet in
Control cells Treated cells
Wild type 100 40
DU
05 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
2. [Option ID = 90940]
3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
[Question ID = 52777]
33)
1. (i) (iv) and (v) [Option ID = 91103]
2. (i) (iii) and (v) [Option ID = 91102]
4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
(i) (iii) and (iv) [Option ID = 91100]
[Question ID = 52786]
2. [Option ID = 91138]
3. [Option ID = 91139]
34)
35)
Correct Answer :-
[Option ID = 91138]
[Question ID = 52738]
1. [Option ID = 90945]
3. [Option ID = 90947]
4. [Option ID = 90944]
Correct Answer :-
[Option ID = 90945]
36)
37)
38)
39)
41)
1. One [Option ID = 90988]
2. Three [Option ID = 90990]
3. Four [Option ID = 90991]
Correct Answer :-
Two [Option ID = 90989]
[Question ID = 52757]
1. 3 genotypes; 4 phenotypes [Option ID = 91020]
3. 4 genotypes; 3 phenotypes [Option ID = 91023]
4. 4 genotypes; 4 phenotypes [Option ID = 91021]
Correct Answer :-
4 genotypes; 3 phenotypes [Option ID = 91023]
the probability that a particular individual who can roll his/her tongue is homozygous?
[Question ID = 52776]
1. 0.32 [Option ID = 91097]
2. 0.96 [Option ID = 91098]
4. 0.64 [Option ID = 91096]
Correct Answer :-
0.66 [Option ID = 91099]
A PCR reaction that continues for 30 cycles will produce approximately how many PCR products from a single template DNA
1. ~ 1 billion [Option ID = 90971]
2. ~ 1 million [Option ID = 90970]
3. 128,000 [Option ID = 90969]
4. 64 [Option ID = 90968]
~ 1 billion [Option ID = 90971]
In a cell undergoing meiosis, the number of copies of a gene at Metaphase I, Anaphase I and Metaphase II would be: [Question ID =
52755]
1. 4, 4, 4 [Option ID = 91012]
3. 2, 2, 4 [Option ID = 91015]
4. 2, 2, 2 [Option ID = 91013]
Correct Answer :-
4, 4, 2 [Option ID = 91014]
active? [Question ID = 52765]
1. Cyclins [Option ID = 91054]
2. Acetyl transferase [Option ID = 91052]
3. Cyclin dependent kinases (Cdk) [Option ID = 91055]
Correct Answer :-
Cyclin dependent kinases (Cdk) [Option ID = 91055]
Which of the following is a bypass repair system: [Question ID = 52742]
42)
44)
45)
46)
47)
2. SOS repair [Option ID = 90962]
3. Nucleotide excision repair [Option ID = 90961]
4. Recombinational repair [Option ID = 90963]
Correct Answer :-
Which of the following amino acids are incorrectly grouped based on their side chain polarity properties? [Question ID = 52780]
1. Isoleucine, Leucine, Alanine [Option ID = 91115]
2. Methionine, Cysteine, Serine [Option ID = 91112]
3. Phenylalanine, Tyrosine, Tryptophan [Option ID = 91114]
Correct Answer :-
Which one of the following listed processes below starts from 3? to 5? direction? [Question ID = 52781]
1. Trans-splicing [Option ID = 91118]
2. mRNA editing [Option ID = 91119]
4. Polyadenylation [Option ID = 91116]
Correct Answer :-
mRNA editing [Option ID = 91119]
The translation of an mRNA encoding a secretory protein using a cell free translation system containing microsomes (ER) lacking
incubation. Which of the following outcome is the most likely? [Question ID = 52748]
1. The protein will be fully synthesized but not incorporated into microsomes. [Option ID = 90987]
2. The protein will be fully synthesized and incorporated into microsomes. [Option ID = 90985]
3. The protein will be fully synthesized and its signal sequence will be removed without being incorporated into microsomes [Option ID = 90986]
Correct Answer :-
Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]
Interference is a common phenomenon during crossing over in meiosis. With the increase in the frequency of double cross over, the
coefficient of coincidence will: [Question ID = 52760]
2. Decrease [Option ID = 91033]
3. Remain same [Option ID = 91034]
4. Increase [Option ID = 91032]
Correct Answer :-
The spatial distribution of mRNA in a cell can be detected by:
[Question ID = 52743]
1. Fluorescent in situ hybridization [Option ID = 90967]
2. Northern blot hybridization [Option ID = 90965]
4. Immunofluorescence [Option ID = 90964]
Correct Answer :-
Fluorescent in situ hybridization [Option ID = 90967]
The development of the antero-posterior axis of Drosophila is initiated when:
1. The terminal group protein Torso sets up the anterior and posterior poles of the embryo [Option ID = 91061]
2. The mother contributes and packages bicoid and nanos mRNA into the developing oocyte [Option ID = 91060]
3. The homeotic genes specify the fate of individual segments [Option ID = 91062]
4. The sperm enters the micropile at the anterior end, thus specifying the antero-posterior axis [Option ID = 91063]
1)
2)
3)
4)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
7)
8)
9)
10)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
14)
15)
16)
17)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
20)
21)
22)
23)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
ii. Requires minimal space to cultivate
iii. Genome has been sequenced [Question ID = 52745]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
Correct Answer :-
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
RNA interference. [Option ID = 91129]
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
D-lysine [Option ID = 91126]
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
Correct Answer :-
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
3. [Option ID = 90950]
Correct Answer :-
28)
29)
[Option ID = 90949]
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
1
b. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Control cells Treated cells
Wild type 100 40
DU
1
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
iii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
1. [Option ID = 90943]
3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
[Option ID = 90941]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
32)
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
33)
1. (i) (iv) and (v) [Option ID = 91103]
2. (i) (iii) and (v) [Option ID = 91102]
3. (i) (iii) and (iv) [Option ID = 91100]
Correct Answer :-
(i) (iii) and (iv) [Option ID = 91100]
[Question ID = 52786]
1. [Option ID = 91137]
3. [Option ID = 91139]
34)
35)
4. [Option ID = 91136]
[Option ID = 91138]
[Question ID = 52738]
1. [Option ID = 90945]
2. [Option ID = 90946]
4. [Option ID = 90944]
Correct Answer :-
[Option ID = 90945]
[Question ID = 52749]
37)
38)
39)
40)
1. One [Option ID = 90988]
2. Three [Option ID = 90990]
3. Four [Option ID = 90991]
4. Two [Option ID = 90989]
Two [Option ID = 90989]
[Question ID = 52757]
1. 3 genotypes; 4 phenotypes [Option ID = 91020]
2. 3 genotypes; 3 phenotypes [Option ID = 91022]
4. 4 genotypes; 4 phenotypes [Option ID = 91021]
Correct Answer :-
4 genotypes; 3 phenotypes [Option ID = 91023]
Human beings carrying the dominant allele R can roll their tongue. In a population in which the frequency of this allele is 0.8, what is
[Question ID = 52776]
1. 0.32 [Option ID = 91097]
2. 0.96 [Option ID = 91098]
3. 0.66 [Option ID = 91099]
Correct Answer :-
0.66 [Option ID = 91099]
A PCR reaction that continues for 30 cycles will produce approximately how many PCR products from a single template DNA
molecule? [Question ID = 52744]
2. ~ 1 million [Option ID = 90970]
3. 128,000 [Option ID = 90969]
4. 64 [Option ID = 90968]
Correct Answer :-
In a cell undergoing meiosis, the number of copies of a gene at Metaphase I, Anaphase I and Metaphase II would be: [Question ID =
52755]
1. 4, 4, 4 [Option ID = 91012]
2. 4, 4, 2 [Option ID = 91014]
4. 2, 2, 2 [Option ID = 91013]
Correct Answer :-
4, 4, 2 [Option ID = 91014]
Which of the following protein maintained at constant levels throughout the cell cycle and requires for cyclin to become catalytically
1. Cyclins [Option ID = 91054]
2. Acetyl transferase [Option ID = 91052]
3. Cyclin dependent kinases (Cdk) [Option ID = 91055]
4. Protein kinase [Option ID = 91053]
Cyclin dependent kinases (Cdk) [Option ID = 91055]
Which of the following is a bypass repair system: [Question ID = 52742]
42)
43)
45)
46)
47)
1. Base excision repair [Option ID = 90960]
3. Nucleotide excision repair [Option ID = 90961]
4. Recombinational repair [Option ID = 90963]
Correct Answer :-
SOS repair [Option ID = 90962]
1. Isoleucine, Leucine, Alanine [Option ID = 91115]
2. Methionine, Cysteine, Serine [Option ID = 91112]
3. Phenylalanine, Tyrosine, Tryptophan [Option ID = 91114]
4. Arginine, Lysine, Proline [Option ID = 91113]
Which one of the following listed processes below starts from 3? to 5? direction? [Question ID = 52781]
1. Trans-splicing [Option ID = 91118]
2. mRNA editing [Option ID = 91119]
3. Translation [Option ID = 91117]
Correct Answer :-
mRNA editing [Option ID = 91119]
The translation of an mRNA encoding a secretory protein using a cell free translation system containing microsomes (ER) lacking
signal recognition particles (SRP) is initiated. Shortly afterwards SRP molecules in presence of TX100 are added followed by further
1. The protein will be fully synthesized but not incorporated into microsomes. [Option ID = 90987]
2. The protein will be fully synthesized and incorporated into microsomes. [Option ID = 90985]
3. The protein will be fully synthesized and its signal sequence will be removed without being incorporated into microsomes [Option ID = 90986]
4. Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]
Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]
Interference is a common phenomenon during crossing over in meiosis. With the increase in the frequency of double cross over, the
coefficient of coincidence will: [Question ID = 52760]
1. No relationship between double cross over and coefficient of coincidence [Option ID = 91035]
3. Remain same [Option ID = 91034]
4. Increase [Option ID = 91032]
Correct Answer :-
Increase [Option ID = 91032]
[Question ID = 52743]
1. Fluorescent in situ hybridization [Option ID = 90967]
2. Northern blot hybridization [Option ID = 90965]
3. Dot blot hybridization [Option ID = 90966]
Correct Answer :-
Fluorescent in situ hybridization [Option ID = 90967]
The development of the antero-posterior axis of Drosophila is initiated when:
[Question ID = 52767]
2. The mother contributes and packages bicoid and nanos mRNA into the developing oocyte [Option ID = 91060]
3. The homeotic genes specify the fate of individual segments [Option ID = 91062]
4. The sperm enters the micropile at the anterior end, thus specifying the antero-posterior axis [Option ID = 91063]
48)
50)
Correct Answer :-
The mother contributes and packages bicoid and nanos mRNA into the developing oocyte [Option ID = 91060]
You want to express recombinant human insulin protein in E. coli. You are given a clone containing the pig insulin gene and human
a. cDNA library with cloned pig insulin gene
b. isolate mRNA from human pancreas
c. express recombinant human insulin in E. coli
d. using reverse transcriptase, make cDNA
f. clone cDNAs into expression vector to make library
[Question ID = 52772]
1. aecbdf [Option ID = 91080]
2. bdfaec [Option ID = 91083]
3. bdafec [Option ID = 91081]
Correct Answer :-
bdfaec [Option ID = 91083]
You have five yeast strains each having distinct temperature sensitive allele of YFG1 named ts1-ts5 for impaired growth at 42?C. In
the laboratory you identify a suppressor to ts1 named sup1 which restores growth at 42?C. Using pairwise crossing you combine ts2-ts5
describes sup1 function with respect to ts1?
[Question ID = 52750]
1. sup1 is a either a dosage or bypass suppressor of ts1 [Option ID = 90995]
2. sup1 is a bypass suppressor of ts1 [Option ID = 90994]
4. sup1 is an interaction suppressor of ts1 [Option ID = 90993]
Correct Answer :-
sup1 is an interaction suppressor of ts1 [Option ID = 90993]
You wish to amplify the region in BOLD CAPS below using PCR.
5'gagatcaggacttaGATTACAGATTACAGATTACAGATTACAggccaagtc3'
Select the correct set of 8bp primer pair:
[Question ID = 52771]
2. 5'AGGACTTA3' and 5'TGAACCGG3' [Option ID = 91079]
3. 5'AGGACTTA3' and 5'ACTTGGCC3' [Option ID = 91078]
4. 5'TAAGTCCT3' and 5'ACTTGGCC3' [Option ID = 91077]
Correct Answer :-
FirstRanker.com - FirstRanker's Choice
2)
3)
4)
5)
--- Content provided by FirstRanker.com ---
6)DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
--- Content provided by FirstRanker.com ---
2. have genes for the same characters at the same loci [Option ID = 91029]3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
--- Content provided by FirstRanker.com ---
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
--- Content provided by FirstRanker.com ---
4. Aa Bb Cc Dd [Option ID = 90955]Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
--- Content provided by FirstRanker.com ---
1. The enzyme is an 8-base cutter. [Option ID = 91086]2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
--- Content provided by FirstRanker.com ---
The enzyme is an 8-base cutter. [Option ID = 91086]Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
--- Content provided by FirstRanker.com ---
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
--- Content provided by FirstRanker.com ---
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
--- Content provided by FirstRanker.com ---
FirstRanker.com - FirstRanker's Choice1)
2)
3)
4)
--- Content provided by FirstRanker.com ---
5)6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
--- Content provided by FirstRanker.com ---
1. separate in meiosis II [Option ID = 91031]2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
--- Content provided by FirstRanker.com ---
have genes for the same characters at the same loci [Option ID = 91029]Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
--- Content provided by FirstRanker.com ---
3. Aa BB Cc Dd [Option ID = 90952]4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
--- Content provided by FirstRanker.com ---
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
--- Content provided by FirstRanker.com ---
Correct Answer :-The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
--- Content provided by FirstRanker.com ---
2. Yeast two hybrid assay [Option ID = 91039]3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
--- Content provided by FirstRanker.com ---
Cyclins facilitate progression cell cycle by: [Question ID = 52762]1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
--- Content provided by FirstRanker.com ---
Correct Answer :-Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
--- Content provided by FirstRanker.com ---
1. AT to GC [Option ID = 91074]7)
8)
9)
10)
--- Content provided by FirstRanker.com ---
11)12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
--- Content provided by FirstRanker.com ---
Correct Answer :-AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
--- Content provided by FirstRanker.com ---
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
--- Content provided by FirstRanker.com ---
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
--- Content provided by FirstRanker.com ---
1. two [Option ID = 91068]2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
--- Content provided by FirstRanker.com ---
eight [Option ID = 91071]How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
--- Content provided by FirstRanker.com ---
4. Mutations of pre-existing alleles [Option ID = 90957]Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
--- Content provided by FirstRanker.com ---
2. 48 [Option ID = 91051]3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
--- Content provided by FirstRanker.com ---
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
--- Content provided by FirstRanker.com ---
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
--- Content provided by FirstRanker.com ---
2. ability to use dNTPs as substrate [Option ID = 91104]3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
--- Content provided by FirstRanker.com ---
FirstRanker.com - FirstRanker's Choice1)
2)
3)
4)
--- Content provided by FirstRanker.com ---
5)6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
--- Content provided by FirstRanker.com ---
1. separate in meiosis II [Option ID = 91031]2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
--- Content provided by FirstRanker.com ---
have genes for the same characters at the same loci [Option ID = 91029]Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
--- Content provided by FirstRanker.com ---
3. Aa BB Cc Dd [Option ID = 90952]4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
--- Content provided by FirstRanker.com ---
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
--- Content provided by FirstRanker.com ---
Correct Answer :-The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
--- Content provided by FirstRanker.com ---
2. Yeast two hybrid assay [Option ID = 91039]3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
--- Content provided by FirstRanker.com ---
Cyclins facilitate progression cell cycle by: [Question ID = 52762]1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
--- Content provided by FirstRanker.com ---
Correct Answer :-Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
--- Content provided by FirstRanker.com ---
1. AT to GC [Option ID = 91074]7)
8)
9)
10)
--- Content provided by FirstRanker.com ---
11)12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
--- Content provided by FirstRanker.com ---
Correct Answer :-AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
--- Content provided by FirstRanker.com ---
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
--- Content provided by FirstRanker.com ---
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
--- Content provided by FirstRanker.com ---
1. two [Option ID = 91068]2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
--- Content provided by FirstRanker.com ---
eight [Option ID = 91071]How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
--- Content provided by FirstRanker.com ---
4. Mutations of pre-existing alleles [Option ID = 90957]Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
--- Content provided by FirstRanker.com ---
2. 48 [Option ID = 91051]3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
--- Content provided by FirstRanker.com ---
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
--- Content provided by FirstRanker.com ---
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
--- Content provided by FirstRanker.com ---
2. ability to use dNTPs as substrate [Option ID = 91104]3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
--- Content provided by FirstRanker.com ---
13)14)
15)
16)
17)
--- Content provided by FirstRanker.com ---
18)Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
--- Content provided by FirstRanker.com ---
4. acetylation of DNA in the euchromatin [Option ID = 91122]Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
--- Content provided by FirstRanker.com ---
1. Allow plasmid conjugation [Option ID = 91091]2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Screen for recombinant vectors with inserts [Option ID = 91090]You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
--- Content provided by FirstRanker.com ---
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
--- Content provided by FirstRanker.com ---
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them toone another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
--- Content provided by FirstRanker.com ---
3. dominant and lethal in the homozygous state [Option ID = 91066]4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
--- Content provided by FirstRanker.com ---
1. Insulin. [Option ID = 91111]2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Steroid hormones. [Option ID = 91109]In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
--- Content provided by FirstRanker.com ---
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
--- Content provided by FirstRanker.com ---
FirstRanker.com - FirstRanker's Choice1)
2)
3)
4)
--- Content provided by FirstRanker.com ---
5)6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
--- Content provided by FirstRanker.com ---
1. separate in meiosis II [Option ID = 91031]2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
--- Content provided by FirstRanker.com ---
have genes for the same characters at the same loci [Option ID = 91029]Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
--- Content provided by FirstRanker.com ---
3. Aa BB Cc Dd [Option ID = 90952]4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
--- Content provided by FirstRanker.com ---
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
--- Content provided by FirstRanker.com ---
Correct Answer :-The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
--- Content provided by FirstRanker.com ---
2. Yeast two hybrid assay [Option ID = 91039]3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
--- Content provided by FirstRanker.com ---
Cyclins facilitate progression cell cycle by: [Question ID = 52762]1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
--- Content provided by FirstRanker.com ---
Correct Answer :-Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
--- Content provided by FirstRanker.com ---
1. AT to GC [Option ID = 91074]7)
8)
9)
10)
--- Content provided by FirstRanker.com ---
11)12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
--- Content provided by FirstRanker.com ---
Correct Answer :-AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
--- Content provided by FirstRanker.com ---
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
--- Content provided by FirstRanker.com ---
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
--- Content provided by FirstRanker.com ---
1. two [Option ID = 91068]2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
--- Content provided by FirstRanker.com ---
eight [Option ID = 91071]How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
--- Content provided by FirstRanker.com ---
4. Mutations of pre-existing alleles [Option ID = 90957]Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
--- Content provided by FirstRanker.com ---
2. 48 [Option ID = 91051]3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
--- Content provided by FirstRanker.com ---
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
--- Content provided by FirstRanker.com ---
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
--- Content provided by FirstRanker.com ---
2. ability to use dNTPs as substrate [Option ID = 91104]3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
--- Content provided by FirstRanker.com ---
13)14)
15)
16)
17)
--- Content provided by FirstRanker.com ---
18)Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
--- Content provided by FirstRanker.com ---
4. acetylation of DNA in the euchromatin [Option ID = 91122]Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
--- Content provided by FirstRanker.com ---
1. Allow plasmid conjugation [Option ID = 91091]2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Screen for recombinant vectors with inserts [Option ID = 91090]You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
--- Content provided by FirstRanker.com ---
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
--- Content provided by FirstRanker.com ---
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them toone another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
--- Content provided by FirstRanker.com ---
3. dominant and lethal in the homozygous state [Option ID = 91066]4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
--- Content provided by FirstRanker.com ---
1. Insulin. [Option ID = 91111]2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Steroid hormones. [Option ID = 91109]In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
--- Content provided by FirstRanker.com ---
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
--- Content provided by FirstRanker.com ---
19)20)
21)
22)
23)
--- Content provided by FirstRanker.com ---
24)25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
--- Content provided by FirstRanker.com ---
i. Short life cycleii. Requires minimal space to cultivate
iii. Genome has been sequenced [Question ID = 52745]
--- Content provided by FirstRanker.com ---
1. (i) and (iii) only [Option ID = 90974]2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
Correct Answer :-
--- Content provided by FirstRanker.com ---
(i), (ii) and (iii) [Option ID = 90975]When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
--- Content provided by FirstRanker.com ---
4. specific sigma factors. [Option ID = 91133]Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
--- Content provided by FirstRanker.com ---
2. Proteasome. [Option ID = 91130]3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
RNA interference. [Option ID = 91129]
--- Content provided by FirstRanker.com ---
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from anerror during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
--- Content provided by FirstRanker.com ---
4. Interphase [Option ID = 91059]Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
--- Content provided by FirstRanker.com ---
2. Pyrrolysine [Option ID = 91127]3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
D-lysine [Option ID = 91126]
--- Content provided by FirstRanker.com ---
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of thefollowing? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
--- Content provided by FirstRanker.com ---
4. Isoelectric point [Option ID = 91000]Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
--- Content provided by FirstRanker.com ---
1. equal to that of the G1 cell [Option ID = 91024]FirstRanker.com - FirstRanker's Choice
1)
2)
3)
--- Content provided by FirstRanker.com ---
4)5)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
--- Content provided by FirstRanker.com ---
Pairs of homologous chromosomes: [Question ID = 52759]1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
--- Content provided by FirstRanker.com ---
Correct Answer :-have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
--- Content provided by FirstRanker.com ---
2. Aa BB CC DD [Option ID = 90953]3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
--- Content provided by FirstRanker.com ---
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is notknown. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
--- Content provided by FirstRanker.com ---
4. This was a partial digest. [Option ID = 91087]Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
--- Content provided by FirstRanker.com ---
1. Yeast three hybrid assay [Option ID = 91038]2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Yeast three hybrid assay [Option ID = 91038]Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
--- Content provided by FirstRanker.com ---
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
--- Content provided by FirstRanker.com ---
[Question ID = 52770]1. AT to GC [Option ID = 91074]
7)
8)
9)
--- Content provided by FirstRanker.com ---
10)11)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
--- Content provided by FirstRanker.com ---
4. GC to AT [Option ID = 91073]Correct Answer :-
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
--- Content provided by FirstRanker.com ---
3H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
--- Content provided by FirstRanker.com ---
91095]3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
--- Content provided by FirstRanker.com ---
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]1. two [Option ID = 91068]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
--- Content provided by FirstRanker.com ---
Correct Answer :-eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
--- Content provided by FirstRanker.com ---
3. Chromosomal aberrations [Option ID = 90959]4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
--- Content provided by FirstRanker.com ---
1. 24 [Option ID = 91049]2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
--- Content provided by FirstRanker.com ---
24 [Option ID = 91049]Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
--- Content provided by FirstRanker.com ---
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
--- Content provided by FirstRanker.com ---
1. ability to use RNA as a template [Option ID = 91107]2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
--- Content provided by FirstRanker.com ---
thermostability [Option ID = 91105]13)
14)
15)
16)
--- Content provided by FirstRanker.com ---
17)18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
--- Content provided by FirstRanker.com ---
3. acetylation of histones in the euchromatin [Option ID = 91120]4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
--- Content provided by FirstRanker.com ---
purpose of including this gene in the vector? [Question ID = 52774]1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
--- Content provided by FirstRanker.com ---
Correct Answer :-Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
--- Content provided by FirstRanker.com ---
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
--- Content provided by FirstRanker.com ---
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
--- Content provided by FirstRanker.com ---
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
--- Content provided by FirstRanker.com ---
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
--- Content provided by FirstRanker.com ---
Correct Answer :-Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
--- Content provided by FirstRanker.com ---
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]19)
20)
21)
22)
--- Content provided by FirstRanker.com ---
23)24)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
--- Content provided by FirstRanker.com ---
i. Short life cycle
ii. Requires minimal space to cultivate
--- Content provided by FirstRanker.com ---
iii. Genome has been sequenced [Question ID = 52745]1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
--- Content provided by FirstRanker.com ---
Correct Answer :-(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
--- Content provided by FirstRanker.com ---
3. removal of a repressor protein. [Option ID = 91134]4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
--- Content provided by FirstRanker.com ---
1. Nonsense mediated decay. [Option ID = 91128]2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
--- Content provided by FirstRanker.com ---
RNA interference. [Option ID = 91129]A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
--- Content provided by FirstRanker.com ---
3. Mitosis [Option ID = 91056]4. Interphase [Option ID = 91059]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
--- Content provided by FirstRanker.com ---
1. L-lysine [Option ID = 91124]2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
--- Content provided by FirstRanker.com ---
D-lysine [Option ID = 91126]Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
--- Content provided by FirstRanker.com ---
3. Secondary structure [Option ID = 91001]4. Isoelectric point [Option ID = 91000]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
--- Content provided by FirstRanker.com ---
would be: [Question ID = 52758]1. equal to that of the G1 cell [Option ID = 91024]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
--- Content provided by FirstRanker.com ---
3. twice that of the G1 cell [Option ID = 91025]4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
--- Content provided by FirstRanker.com ---
fragment is: [Question ID = 52763]1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
--- Content provided by FirstRanker.com ---
Correct Answer :-320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
--- Content provided by FirstRanker.com ---
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shownabove?
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
--- Content provided by FirstRanker.com ---
3. [Option ID = 90950]4. [Option ID = 90948]
Correct Answer :-
FirstRanker.com - FirstRanker's Choice
1)
--- Content provided by FirstRanker.com ---
2)3)
4)
5)
6)
--- Content provided by FirstRanker.com ---
DU PhD in GeneticsTopic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
--- Content provided by FirstRanker.com ---
3. are found in gametes [Option ID = 91030]4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
--- Content provided by FirstRanker.com ---
[Question ID = 52740]1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
--- Content provided by FirstRanker.com ---
Correct Answer :-Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
--- Content provided by FirstRanker.com ---
2. The enzyme is a 6-base cutter. [Option ID = 91085]3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
--- Content provided by FirstRanker.com ---
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
--- Content provided by FirstRanker.com ---
4. Co-immunoprecipitation [Option ID = 91037]Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
--- Content provided by FirstRanker.com ---
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
--- Content provided by FirstRanker.com ---
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-APprotonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
7)
--- Content provided by FirstRanker.com ---
8)9)
10)
11)
12)
--- Content provided by FirstRanker.com ---
2. AT to CG [Option ID = 91072]3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
Correct Answer :-
AT to GC [Option ID = 91074]
--- Content provided by FirstRanker.com ---
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule andsite of accumulation when a 5min [
3
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
--- Content provided by FirstRanker.com ---
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
--- Content provided by FirstRanker.com ---
Correct Answer :-signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
--- Content provided by FirstRanker.com ---
3. eight [Option ID = 91071]4. four [Option ID = 91070]
Correct Answer :-
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
--- Content provided by FirstRanker.com ---
1. Sexual reproduction [Option ID = 90956]2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Mutations of pre-existing alleles [Option ID = 90957]How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
--- Content provided by FirstRanker.com ---
4. 46 [Option ID = 91050]Correct Answer :-
24 [Option ID = 91049]
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
--- Content provided by FirstRanker.com ---
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
--- Content provided by FirstRanker.com ---
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
--- Content provided by FirstRanker.com ---
4. thermostability [Option ID = 91105]Correct Answer :-
thermostability [Option ID = 91105]
13)
14)
--- Content provided by FirstRanker.com ---
15)16)
17)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
--- Content provided by FirstRanker.com ---
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
--- Content provided by FirstRanker.com ---
acetylation of histones in the euchromatin [Option ID = 91120]Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
--- Content provided by FirstRanker.com ---
3. Screen for recombinant vectors with inserts [Option ID = 91090]4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
--- Content provided by FirstRanker.com ---
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes theelution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
--- Content provided by FirstRanker.com ---
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
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[Question ID = 52768]1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
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Correct Answer :-dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
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3. Steroid hormones. [Option ID = 91109]4. Peptide. [Option ID = 91108]
Correct Answer :-
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
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gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
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4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
19)
20)
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21)22)
23)
24)
25)
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Why is Arabidopsis thalania widely used as model organism to study plant development?i. Short life cycle
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ii. Requires minimal space to cultivateiii. Genome has been sequenced [Question ID = 52745]
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
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3. (i), (ii) and (iii) [Option ID = 90975]4. (ii) only [Option ID = 90973]
Correct Answer :-
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
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1. a sensor protein on the ribosome. [Option ID = 91132]2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
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specific sigma factors. [Option ID = 91133]A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
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4. CRISPR. [Option ID = 91131]Correct Answer :-
RNA interference. [Option ID = 91129]
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
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1. Cytokinesis [Option ID = 91057]2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
4. Interphase [Option ID = 91059]
Correct Answer :-
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Meiosis I [Option ID = 91058]This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
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4. D-lysine [Option ID = 91126]Correct Answer :-
D-lysine [Option ID = 91126]
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
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1. Molecular mass [Option ID = 91002]2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
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Molecular mass [Option ID = 91002]The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
1. equal to that of the G1 cell [Option ID = 91024]
26)
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27)2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
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equal to that of the G1 cell [Option ID = 91024]A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
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3. 320 [Option ID = 91046]4. 160 [Option ID = 91045]
Correct Answer :-
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
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restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized toprobe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
above?
[Question ID = 52739]
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1. [Option ID = 90949]2. [Option ID = 90951]
3. [Option ID = 90950]
4. [Option ID = 90948]
Correct Answer :-
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28)29)
[Option ID = 90949]
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
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located near the promoter of genet. Two mutant strains were developed:a. DU
1
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
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In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet genemonitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Activity of genet in
Control cells Treated cells
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Wild type 100 40DU
1
05 05
?DUB 100 40
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Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
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Which of the above conclusions are correct?[Question ID = 52737]
1. [Option ID = 90943]
2. [Option ID = 90940]
3. [Option ID = 90942]
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4. [Option ID = 90941]Correct Answer :-
[Option ID = 90941]
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
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2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
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FirstRanker.com - FirstRanker's Choice1)
2)
3)
4)
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5)6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
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1. separate in meiosis II [Option ID = 91031]2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
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have genes for the same characters at the same loci [Option ID = 91029]Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
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3. Aa BB Cc Dd [Option ID = 90952]4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
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known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
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Correct Answer :-The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
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2. Yeast two hybrid assay [Option ID = 91039]3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
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Cyclins facilitate progression cell cycle by: [Question ID = 52762]1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
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Correct Answer :-Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
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1. AT to GC [Option ID = 91074]7)
8)
9)
10)
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11)12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
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Correct Answer :-AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
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H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
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3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
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1. two [Option ID = 91068]2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
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eight [Option ID = 91071]How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
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4. Mutations of pre-existing alleles [Option ID = 90957]Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
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2. 48 [Option ID = 91051]3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
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Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
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4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
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2. ability to use dNTPs as substrate [Option ID = 91104]3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
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13)14)
15)
16)
17)
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18)Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
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4. acetylation of DNA in the euchromatin [Option ID = 91122]Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
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1. Allow plasmid conjugation [Option ID = 91091]2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
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Screen for recombinant vectors with inserts [Option ID = 91090]You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
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2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
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Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them toone another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
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3. dominant and lethal in the homozygous state [Option ID = 91066]4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
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1. Insulin. [Option ID = 91111]2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
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Steroid hormones. [Option ID = 91109]In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
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2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
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19)20)
21)
22)
23)
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24)25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
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i. Short life cycleii. Requires minimal space to cultivate
iii. Genome has been sequenced [Question ID = 52745]
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1. (i) and (iii) only [Option ID = 90974]2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
Correct Answer :-
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(i), (ii) and (iii) [Option ID = 90975]When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
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4. specific sigma factors. [Option ID = 91133]Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
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2. Proteasome. [Option ID = 91130]3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
RNA interference. [Option ID = 91129]
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A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from anerror during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
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4. Interphase [Option ID = 91059]Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
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2. Pyrrolysine [Option ID = 91127]3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
D-lysine [Option ID = 91126]
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Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of thefollowing? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
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4. Isoelectric point [Option ID = 91000]Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
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1. equal to that of the G1 cell [Option ID = 91024]26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
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4. one-half that of the G1 cell [Option ID = 91026]Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
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1. 640 [Option ID = 91047]2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
Correct Answer :-
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320 [Option ID = 91046]1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
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above?[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
3. [Option ID = 90950]
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4. [Option ID = 90948]Correct Answer :-
28)
29)
[Option ID = 90949]
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1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further itwas observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
1
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: the gene encoding DU protein has a nonsense mutationb. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
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Activity of genet inControl cells Treated cells
Wild type 100 40
DU
1
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05 05?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
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ii. DU is a negative regulator (i.e. represses the activity) of the genet geneiii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
1. [Option ID = 90943]
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2. [Option ID = 90940]3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
[Option ID = 90941]
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[Question ID = 52751]1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
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Correct Answer :-N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
32)
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[Question ID = 52747]1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
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4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
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2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
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[Question ID = 52777]FirstRanker.com - FirstRanker's Choice
1)
2)
3)
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4)5)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
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Pairs of homologous chromosomes: [Question ID = 52759]1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
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Correct Answer :-have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
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2. Aa BB CC DD [Option ID = 90953]3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
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A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is notknown. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
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4. This was a partial digest. [Option ID = 91087]Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
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1. Yeast three hybrid assay [Option ID = 91038]2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
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Yeast three hybrid assay [Option ID = 91038]Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
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4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
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[Question ID = 52770]1. AT to GC [Option ID = 91074]
7)
8)
9)
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10)11)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
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4. GC to AT [Option ID = 91073]Correct Answer :-
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
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3H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
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91095]3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
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An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]1. two [Option ID = 91068]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
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Correct Answer :-eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
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3. Chromosomal aberrations [Option ID = 90959]4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
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1. 24 [Option ID = 91049]2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
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24 [Option ID = 91049]Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
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3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
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1. ability to use RNA as a template [Option ID = 91107]2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
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thermostability [Option ID = 91105]13)
14)
15)
16)
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17)18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
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3. acetylation of histones in the euchromatin [Option ID = 91120]4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
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purpose of including this gene in the vector? [Question ID = 52774]1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
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Correct Answer :-Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
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1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
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250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
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2. recessive and semi-lethal in the homozygous state [Option ID = 91065]3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
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Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
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Correct Answer :-Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
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1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
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Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]19)
20)
21)
22)
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23)24)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
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i. Short life cycle
ii. Requires minimal space to cultivate
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iii. Genome has been sequenced [Question ID = 52745]1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
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Correct Answer :-(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
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3. removal of a repressor protein. [Option ID = 91134]4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
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1. Nonsense mediated decay. [Option ID = 91128]2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
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RNA interference. [Option ID = 91129]A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
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3. Mitosis [Option ID = 91056]4. Interphase [Option ID = 91059]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
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1. L-lysine [Option ID = 91124]2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
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D-lysine [Option ID = 91126]Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
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3. Secondary structure [Option ID = 91001]4. Isoelectric point [Option ID = 91000]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
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would be: [Question ID = 52758]1. equal to that of the G1 cell [Option ID = 91024]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
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3. twice that of the G1 cell [Option ID = 91025]4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
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fragment is: [Question ID = 52763]1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
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Correct Answer :-320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
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If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shownabove?
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
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3. [Option ID = 90950]4. [Option ID = 90948]
Correct Answer :-
28)
29)
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[Option ID = 90949]1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
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1: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
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Bacterial StrainActivity of genet in
Control cells Treated cells
Wild type 100 40
DU
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105 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
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i. The genet gene is induced by PHD.ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
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1. [Option ID = 90943]2. [Option ID = 90940]
3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
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[Option ID = 90941][Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
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4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
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32)[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
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3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
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1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
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Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976][Question ID = 52777]
33)
1. (i) (iv) and (v) [Option ID = 91103]
2. (i) (iii) and (v) [Option ID = 91102]
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3. (i) (iii) and (iv) [Option ID = 91100]4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
(i) (iii) and (iv) [Option ID = 91100]
[Question ID = 52786]
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1. [Option ID = 91137]2. [Option ID = 91138]
3. [Option ID = 91139]
FirstRanker.com - FirstRanker's Choice
1)
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2)3)
4)
5)
6)
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DU PhD in GeneticsTopic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
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3. are found in gametes [Option ID = 91030]4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
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[Question ID = 52740]1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
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Correct Answer :-Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
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2. The enzyme is a 6-base cutter. [Option ID = 91085]3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
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Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
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4. Co-immunoprecipitation [Option ID = 91037]Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
--- Content provided by FirstRanker.com ---
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
--- Content provided by FirstRanker.com ---
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-APprotonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
7)
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8)9)
10)
11)
12)
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2. AT to CG [Option ID = 91072]3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
Correct Answer :-
AT to GC [Option ID = 91074]
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Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule andsite of accumulation when a 5min [
3
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
--- Content provided by FirstRanker.com ---
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
--- Content provided by FirstRanker.com ---
Correct Answer :-signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
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3. eight [Option ID = 91071]4. four [Option ID = 91070]
Correct Answer :-
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
--- Content provided by FirstRanker.com ---
1. Sexual reproduction [Option ID = 90956]2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Mutations of pre-existing alleles [Option ID = 90957]How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
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4. 46 [Option ID = 91050]Correct Answer :-
24 [Option ID = 91049]
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
--- Content provided by FirstRanker.com ---
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
--- Content provided by FirstRanker.com ---
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
--- Content provided by FirstRanker.com ---
4. thermostability [Option ID = 91105]Correct Answer :-
thermostability [Option ID = 91105]
13)
14)
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15)16)
17)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
--- Content provided by FirstRanker.com ---
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
--- Content provided by FirstRanker.com ---
acetylation of histones in the euchromatin [Option ID = 91120]Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
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3. Screen for recombinant vectors with inserts [Option ID = 91090]4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
--- Content provided by FirstRanker.com ---
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes theelution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
--- Content provided by FirstRanker.com ---
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
--- Content provided by FirstRanker.com ---
[Question ID = 52768]1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
--- Content provided by FirstRanker.com ---
Correct Answer :-dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
--- Content provided by FirstRanker.com ---
3. Steroid hormones. [Option ID = 91109]4. Peptide. [Option ID = 91108]
Correct Answer :-
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
--- Content provided by FirstRanker.com ---
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
--- Content provided by FirstRanker.com ---
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
19)
20)
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21)22)
23)
24)
25)
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Why is Arabidopsis thalania widely used as model organism to study plant development?i. Short life cycle
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ii. Requires minimal space to cultivateiii. Genome has been sequenced [Question ID = 52745]
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
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3. (i), (ii) and (iii) [Option ID = 90975]4. (ii) only [Option ID = 90973]
Correct Answer :-
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
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1. a sensor protein on the ribosome. [Option ID = 91132]2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
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specific sigma factors. [Option ID = 91133]A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
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4. CRISPR. [Option ID = 91131]Correct Answer :-
RNA interference. [Option ID = 91129]
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
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1. Cytokinesis [Option ID = 91057]2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
4. Interphase [Option ID = 91059]
Correct Answer :-
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Meiosis I [Option ID = 91058]This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
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4. D-lysine [Option ID = 91126]Correct Answer :-
D-lysine [Option ID = 91126]
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
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1. Molecular mass [Option ID = 91002]2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
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Molecular mass [Option ID = 91002]The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
1. equal to that of the G1 cell [Option ID = 91024]
26)
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27)2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
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equal to that of the G1 cell [Option ID = 91024]A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
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3. 320 [Option ID = 91046]4. 160 [Option ID = 91045]
Correct Answer :-
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
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restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized toprobe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
above?
[Question ID = 52739]
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1. [Option ID = 90949]2. [Option ID = 90951]
3. [Option ID = 90950]
4. [Option ID = 90948]
Correct Answer :-
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28)29)
[Option ID = 90949]
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
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located near the promoter of genet. Two mutant strains were developed:a. DU
1
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
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In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet genemonitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Activity of genet in
Control cells Treated cells
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Wild type 100 40DU
1
05 05
?DUB 100 40
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Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
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Which of the above conclusions are correct?[Question ID = 52737]
1. [Option ID = 90943]
2. [Option ID = 90940]
3. [Option ID = 90942]
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4. [Option ID = 90941]Correct Answer :-
[Option ID = 90941]
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
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2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
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30)31)
32)
[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
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2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
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The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982][Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
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4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
[Question ID = 52777]
33)
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1. (i) (iv) and (v) [Option ID = 91103]2. (i) (iii) and (v) [Option ID = 91102]
3. (i) (iii) and (iv) [Option ID = 91100]
4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
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(i) (iii) and (iv) [Option ID = 91100][Question ID = 52786]
1. [Option ID = 91137]
2. [Option ID = 91138]
3. [Option ID = 91139]
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34)35)
4. [Option ID = 91136]
Correct Answer :-
[Option ID = 91138]
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[Question ID = 52738]1. [Option ID = 90945]
2. [Option ID = 90946]
3. [Option ID = 90947]
4. [Option ID = 90944]
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Correct Answer :-[Option ID = 90945]
[Question ID = 52749]
FirstRanker.com - FirstRanker's Choice
1)
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2)3)
4)
5)
6)
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DU PhD in GeneticsTopic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
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3. are found in gametes [Option ID = 91030]4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
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[Question ID = 52740]1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
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Correct Answer :-Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
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2. The enzyme is a 6-base cutter. [Option ID = 91085]3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
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Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
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4. Co-immunoprecipitation [Option ID = 91037]Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
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2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
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After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-APprotonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
1. AT to GC [Option ID = 91074]
7)
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8)9)
10)
11)
12)
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2. AT to CG [Option ID = 91072]3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
Correct Answer :-
AT to GC [Option ID = 91074]
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Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule andsite of accumulation when a 5min [
3
H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
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1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
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Correct Answer :-signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
1. two [Option ID = 91068]
2. three [Option ID = 91069]
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3. eight [Option ID = 91071]4. four [Option ID = 91070]
Correct Answer :-
eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
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1. Sexual reproduction [Option ID = 90956]2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
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Mutations of pre-existing alleles [Option ID = 90957]How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
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4. 46 [Option ID = 91050]Correct Answer :-
24 [Option ID = 91049]
Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
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1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
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SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
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4. thermostability [Option ID = 91105]Correct Answer :-
thermostability [Option ID = 91105]
13)
14)
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15)16)
17)
18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
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1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
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acetylation of histones in the euchromatin [Option ID = 91120]Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
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3. Screen for recombinant vectors with inserts [Option ID = 91090]4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
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exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes theelution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
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4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
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[Question ID = 52768]1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
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Correct Answer :-dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
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3. Steroid hormones. [Option ID = 91109]4. Peptide. [Option ID = 91108]
Correct Answer :-
Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
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gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
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4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
19)
20)
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21)22)
23)
24)
25)
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Why is Arabidopsis thalania widely used as model organism to study plant development?i. Short life cycle
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ii. Requires minimal space to cultivateiii. Genome has been sequenced [Question ID = 52745]
1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
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3. (i), (ii) and (iii) [Option ID = 90975]4. (ii) only [Option ID = 90973]
Correct Answer :-
(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
--- Content provided by FirstRanker.com ---
1. a sensor protein on the ribosome. [Option ID = 91132]2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
--- Content provided by FirstRanker.com ---
specific sigma factors. [Option ID = 91133]A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
--- Content provided by FirstRanker.com ---
4. CRISPR. [Option ID = 91131]Correct Answer :-
RNA interference. [Option ID = 91129]
A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
--- Content provided by FirstRanker.com ---
1. Cytokinesis [Option ID = 91057]2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
4. Interphase [Option ID = 91059]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Meiosis I [Option ID = 91058]This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
--- Content provided by FirstRanker.com ---
4. D-lysine [Option ID = 91126]Correct Answer :-
D-lysine [Option ID = 91126]
Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
--- Content provided by FirstRanker.com ---
1. Molecular mass [Option ID = 91002]2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
4. Isoelectric point [Option ID = 91000]
Correct Answer :-
--- Content provided by FirstRanker.com ---
Molecular mass [Option ID = 91002]The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
1. equal to that of the G1 cell [Option ID = 91024]
26)
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27)2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
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equal to that of the G1 cell [Option ID = 91024]A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
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3. 320 [Option ID = 91046]4. 160 [Option ID = 91045]
Correct Answer :-
320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
--- Content provided by FirstRanker.com ---
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized toprobe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
above?
[Question ID = 52739]
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1. [Option ID = 90949]2. [Option ID = 90951]
3. [Option ID = 90950]
4. [Option ID = 90948]
Correct Answer :-
--- Content provided by FirstRanker.com ---
28)29)
[Option ID = 90949]
1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
--- Content provided by FirstRanker.com ---
located near the promoter of genet. Two mutant strains were developed:a. DU
1
: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
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In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet genemonitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
Activity of genet in
Control cells Treated cells
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Wild type 100 40DU
1
05 05
?DUB 100 40
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Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
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Which of the above conclusions are correct?[Question ID = 52737]
1. [Option ID = 90943]
2. [Option ID = 90940]
3. [Option ID = 90942]
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4. [Option ID = 90941]Correct Answer :-
[Option ID = 90941]
[Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
--- Content provided by FirstRanker.com ---
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
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30)31)
32)
[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
--- Content provided by FirstRanker.com ---
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
--- Content provided by FirstRanker.com ---
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982][Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
--- Content provided by FirstRanker.com ---
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
[Question ID = 52777]
33)
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1. (i) (iv) and (v) [Option ID = 91103]2. (i) (iii) and (v) [Option ID = 91102]
3. (i) (iii) and (iv) [Option ID = 91100]
4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
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(i) (iii) and (iv) [Option ID = 91100][Question ID = 52786]
1. [Option ID = 91137]
2. [Option ID = 91138]
3. [Option ID = 91139]
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34)35)
4. [Option ID = 91136]
Correct Answer :-
[Option ID = 91138]
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[Question ID = 52738]1. [Option ID = 90945]
2. [Option ID = 90946]
3. [Option ID = 90947]
4. [Option ID = 90944]
--- Content provided by FirstRanker.com ---
Correct Answer :-[Option ID = 90945]
[Question ID = 52749]
36)
37)
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38)39)
40)
41)
1. One [Option ID = 90988]
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2. Three [Option ID = 90990]3. Four [Option ID = 90991]
4. Two [Option ID = 90989]
Correct Answer :-
Two [Option ID = 90989]
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[Question ID = 52757]1. 3 genotypes; 4 phenotypes [Option ID = 91020]
2. 3 genotypes; 3 phenotypes [Option ID = 91022]
3. 4 genotypes; 3 phenotypes [Option ID = 91023]
4. 4 genotypes; 4 phenotypes [Option ID = 91021]
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Correct Answer :-4 genotypes; 3 phenotypes [Option ID = 91023]
Human beings carrying the dominant allele R can roll their tongue. In a population in which the frequency of this allele is 0.8, what is
the probability that a particular individual who can roll his/her tongue is homozygous?
[Question ID = 52776]
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1. 0.32 [Option ID = 91097]2. 0.96 [Option ID = 91098]
3. 0.66 [Option ID = 91099]
4. 0.64 [Option ID = 91096]
Correct Answer :-
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0.66 [Option ID = 91099]A PCR reaction that continues for 30 cycles will produce approximately how many PCR products from a single template DNA
molecule? [Question ID = 52744]
1. ~ 1 billion [Option ID = 90971]
2. ~ 1 million [Option ID = 90970]
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3. 128,000 [Option ID = 90969]4. 64 [Option ID = 90968]
Correct Answer :-
~ 1 billion [Option ID = 90971]
In a cell undergoing meiosis, the number of copies of a gene at Metaphase I, Anaphase I and Metaphase II would be: [Question ID =
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52755]1. 4, 4, 4 [Option ID = 91012]
2. 4, 4, 2 [Option ID = 91014]
3. 2, 2, 4 [Option ID = 91015]
4. 2, 2, 2 [Option ID = 91013]
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Correct Answer :-4, 4, 2 [Option ID = 91014]
Which of the following protein maintained at constant levels throughout the cell cycle and requires for cyclin to become catalytically
active? [Question ID = 52765]
1. Cyclins [Option ID = 91054]
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2. Acetyl transferase [Option ID = 91052]3. Cyclin dependent kinases (Cdk) [Option ID = 91055]
4. Protein kinase [Option ID = 91053]
Correct Answer :-
Cyclin dependent kinases (Cdk) [Option ID = 91055]
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Which of the following is a bypass repair system: [Question ID = 52742]FirstRanker.com - FirstRanker's Choice
1)
2)
3)
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4)5)
6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
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Pairs of homologous chromosomes: [Question ID = 52759]1. separate in meiosis II [Option ID = 91031]
2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
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Correct Answer :-have genes for the same characters at the same loci [Option ID = 91029]
Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
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2. Aa BB CC DD [Option ID = 90953]3. Aa BB Cc Dd [Option ID = 90952]
4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
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A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is notknown. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]
1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
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4. This was a partial digest. [Option ID = 91087]Correct Answer :-
The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
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1. Yeast three hybrid assay [Option ID = 91038]2. Yeast two hybrid assay [Option ID = 91039]
3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
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Yeast three hybrid assay [Option ID = 91038]Cyclins facilitate progression cell cycle by: [Question ID = 52762]
1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
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4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]Correct Answer :-
Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
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[Question ID = 52770]1. AT to GC [Option ID = 91074]
7)
8)
9)
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10)11)
12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
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4. GC to AT [Option ID = 91073]Correct Answer :-
AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
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3H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =
52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
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91095]3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
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An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]1. two [Option ID = 91068]
2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
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Correct Answer :-eight [Option ID = 91071]
How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
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3. Chromosomal aberrations [Option ID = 90959]4. Mutations of pre-existing alleles [Option ID = 90957]
Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
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1. 24 [Option ID = 91049]2. 48 [Option ID = 91051]
3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
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24 [Option ID = 91049]Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,
identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
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3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]
Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
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1. ability to use RNA as a template [Option ID = 91107]2. ability to use dNTPs as substrate [Option ID = 91104]
3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
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thermostability [Option ID = 91105]13)
14)
15)
16)
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17)18)
Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
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3. acetylation of histones in the euchromatin [Option ID = 91120]4. acetylation of DNA in the euchromatin [Option ID = 91122]
Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
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purpose of including this gene in the vector? [Question ID = 52774]1. Allow plasmid conjugation [Option ID = 91091]
2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
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Correct Answer :-Screen for recombinant vectors with inserts [Option ID = 91090]
You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
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1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]
3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
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250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them to
one another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
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2. recessive and semi-lethal in the homozygous state [Option ID = 91065]3. dominant and lethal in the homozygous state [Option ID = 91066]
4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
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Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]1. Insulin. [Option ID = 91111]
2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
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Correct Answer :-Steroid hormones. [Option ID = 91109]
In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
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1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]
3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
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Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]19)
20)
21)
22)
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23)24)
25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
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i. Short life cycle
ii. Requires minimal space to cultivate
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iii. Genome has been sequenced [Question ID = 52745]1. (i) and (iii) only [Option ID = 90974]
2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
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Correct Answer :-(i), (ii) and (iii) [Option ID = 90975]
When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
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3. removal of a repressor protein. [Option ID = 91134]4. specific sigma factors. [Option ID = 91133]
Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
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1. Nonsense mediated decay. [Option ID = 91128]2. Proteasome. [Option ID = 91130]
3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
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RNA interference. [Option ID = 91129]A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from an
error during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
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3. Mitosis [Option ID = 91056]4. Interphase [Option ID = 91059]
Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
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1. L-lysine [Option ID = 91124]2. Pyrrolysine [Option ID = 91127]
3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
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D-lysine [Option ID = 91126]Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of the
following? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
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3. Secondary structure [Option ID = 91001]4. Isoelectric point [Option ID = 91000]
Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
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would be: [Question ID = 52758]1. equal to that of the G1 cell [Option ID = 91024]
26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
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3. twice that of the G1 cell [Option ID = 91025]4. one-half that of the G1 cell [Option ID = 91026]
Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
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fragment is: [Question ID = 52763]1. 640 [Option ID = 91047]
2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
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Correct Answer :-320 [Option ID = 91046]
1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
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If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shownabove?
[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
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3. [Option ID = 90950]4. [Option ID = 90948]
Correct Answer :-
28)
29)
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[Option ID = 90949]1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further it
was observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
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1: the gene encoding DU protein has a nonsense mutation
b. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
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Bacterial StrainActivity of genet in
Control cells Treated cells
Wild type 100 40
DU
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105 05
?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
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i. The genet gene is induced by PHD.ii. DU is a negative regulator (i.e. represses the activity) of the genet gene
iii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
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1. [Option ID = 90943]2. [Option ID = 90940]
3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
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[Option ID = 90941][Question ID = 52751]
1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
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4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]Correct Answer :-
N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
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32)[Question ID = 52747]
1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
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3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]
Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
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1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
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Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976][Question ID = 52777]
33)
1. (i) (iv) and (v) [Option ID = 91103]
2. (i) (iii) and (v) [Option ID = 91102]
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3. (i) (iii) and (iv) [Option ID = 91100]4. (ii) (iii) and (v) [Option ID = 91101]
Correct Answer :-
(i) (iii) and (iv) [Option ID = 91100]
[Question ID = 52786]
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1. [Option ID = 91137]2. [Option ID = 91138]
3. [Option ID = 91139]
34)
35)
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4. [Option ID = 91136]Correct Answer :-
[Option ID = 91138]
[Question ID = 52738]
1. [Option ID = 90945]
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2. [Option ID = 90946]3. [Option ID = 90947]
4. [Option ID = 90944]
Correct Answer :-
[Option ID = 90945]
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[Question ID = 52749]36)
37)
38)
39)
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40)41)
1. One [Option ID = 90988]
2. Three [Option ID = 90990]
3. Four [Option ID = 90991]
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4. Two [Option ID = 90989]Correct Answer :-
Two [Option ID = 90989]
[Question ID = 52757]
1. 3 genotypes; 4 phenotypes [Option ID = 91020]
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2. 3 genotypes; 3 phenotypes [Option ID = 91022]3. 4 genotypes; 3 phenotypes [Option ID = 91023]
4. 4 genotypes; 4 phenotypes [Option ID = 91021]
Correct Answer :-
4 genotypes; 3 phenotypes [Option ID = 91023]
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Human beings carrying the dominant allele R can roll their tongue. In a population in which the frequency of this allele is 0.8, what isthe probability that a particular individual who can roll his/her tongue is homozygous?
[Question ID = 52776]
1. 0.32 [Option ID = 91097]
2. 0.96 [Option ID = 91098]
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3. 0.66 [Option ID = 91099]4. 0.64 [Option ID = 91096]
Correct Answer :-
0.66 [Option ID = 91099]
A PCR reaction that continues for 30 cycles will produce approximately how many PCR products from a single template DNA
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molecule? [Question ID = 52744]1. ~ 1 billion [Option ID = 90971]
2. ~ 1 million [Option ID = 90970]
3. 128,000 [Option ID = 90969]
4. 64 [Option ID = 90968]
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Correct Answer :-~ 1 billion [Option ID = 90971]
In a cell undergoing meiosis, the number of copies of a gene at Metaphase I, Anaphase I and Metaphase II would be: [Question ID =
52755]
1. 4, 4, 4 [Option ID = 91012]
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2. 4, 4, 2 [Option ID = 91014]3. 2, 2, 4 [Option ID = 91015]
4. 2, 2, 2 [Option ID = 91013]
Correct Answer :-
4, 4, 2 [Option ID = 91014]
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Which of the following protein maintained at constant levels throughout the cell cycle and requires for cyclin to become catalyticallyactive? [Question ID = 52765]
1. Cyclins [Option ID = 91054]
2. Acetyl transferase [Option ID = 91052]
3. Cyclin dependent kinases (Cdk) [Option ID = 91055]
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4. Protein kinase [Option ID = 91053]Correct Answer :-
Cyclin dependent kinases (Cdk) [Option ID = 91055]
Which of the following is a bypass repair system: [Question ID = 52742]
42)
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43)44)
45)
46)
47)
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1. Base excision repair [Option ID = 90960]2. SOS repair [Option ID = 90962]
3. Nucleotide excision repair [Option ID = 90961]
4. Recombinational repair [Option ID = 90963]
Correct Answer :-
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SOS repair [Option ID = 90962]Which of the following amino acids are incorrectly grouped based on their side chain polarity properties? [Question ID = 52780]
1. Isoleucine, Leucine, Alanine [Option ID = 91115]
2. Methionine, Cysteine, Serine [Option ID = 91112]
3. Phenylalanine, Tyrosine, Tryptophan [Option ID = 91114]
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4. Arginine, Lysine, Proline [Option ID = 91113]Correct Answer :-
Which one of the following listed processes below starts from 3? to 5? direction? [Question ID = 52781]
1. Trans-splicing [Option ID = 91118]
2. mRNA editing [Option ID = 91119]
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3. Translation [Option ID = 91117]4. Polyadenylation [Option ID = 91116]
Correct Answer :-
mRNA editing [Option ID = 91119]
The translation of an mRNA encoding a secretory protein using a cell free translation system containing microsomes (ER) lacking
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signal recognition particles (SRP) is initiated. Shortly afterwards SRP molecules in presence of TX100 are added followed by furtherincubation. Which of the following outcome is the most likely? [Question ID = 52748]
1. The protein will be fully synthesized but not incorporated into microsomes. [Option ID = 90987]
2. The protein will be fully synthesized and incorporated into microsomes. [Option ID = 90985]
3. The protein will be fully synthesized and its signal sequence will be removed without being incorporated into microsomes [Option ID = 90986]
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4. Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]Correct Answer :-
Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]
Interference is a common phenomenon during crossing over in meiosis. With the increase in the frequency of double cross over, the
coefficient of coincidence will: [Question ID = 52760]
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1. No relationship between double cross over and coefficient of coincidence [Option ID = 91035]2. Decrease [Option ID = 91033]
3. Remain same [Option ID = 91034]
4. Increase [Option ID = 91032]
Correct Answer :-
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Increase [Option ID = 91032]The spatial distribution of mRNA in a cell can be detected by:
[Question ID = 52743]
1. Fluorescent in situ hybridization [Option ID = 90967]
2. Northern blot hybridization [Option ID = 90965]
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3. Dot blot hybridization [Option ID = 90966]4. Immunofluorescence [Option ID = 90964]
Correct Answer :-
Fluorescent in situ hybridization [Option ID = 90967]
The development of the antero-posterior axis of Drosophila is initiated when:
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[Question ID = 52767]1. The terminal group protein Torso sets up the anterior and posterior poles of the embryo [Option ID = 91061]
2. The mother contributes and packages bicoid and nanos mRNA into the developing oocyte [Option ID = 91060]
3. The homeotic genes specify the fate of individual segments [Option ID = 91062]
4. The sperm enters the micropile at the anterior end, thus specifying the antero-posterior axis [Option ID = 91063]
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FirstRanker.com - FirstRanker's Choice1)
2)
3)
4)
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5)6)
DU PhD in Genetics
Topic:- DU_J18_PHD_GENETICS
Pairs of homologous chromosomes: [Question ID = 52759]
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1. separate in meiosis II [Option ID = 91031]2. have genes for the same characters at the same loci [Option ID = 91029]
3. are found in gametes [Option ID = 91030]
4. have identical DNA sequences in their genes [Option ID = 91028]
Correct Answer :-
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have genes for the same characters at the same loci [Option ID = 91029]Which of the following genotypes would produce the greatest variability of gametes if the alleles assorted independently?
[Question ID = 52740]
1. AA Bb Cc Dd [Option ID = 90954]
2. Aa BB CC DD [Option ID = 90953]
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3. Aa BB Cc Dd [Option ID = 90952]4. Aa Bb Cc Dd [Option ID = 90955]
Correct Answer :-
Aa Bb Cc Dd [Option ID = 90955]
A circular DNA of 4.7 Mb (Mb=million base pairs) length is cut with a restriction enzyme whose precise recognition sequence is not
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known. The digest shows ~75 fragments on a pulsed-field gel. What is the most likely conclusion from this data? [Question ID = 52773]1. The enzyme is an 8-base cutter. [Option ID = 91086]
2. The enzyme is a 6-base cutter. [Option ID = 91085]
3. The enzyme is a 4-base cutter. [Option ID = 91084]
4. This was a partial digest. [Option ID = 91087]
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Correct Answer :-The enzyme is an 8-base cutter. [Option ID = 91086]
Which of the following techniques CANNOT be utilized to demonstrate Protein:Protein interaction?
[Question ID = 52761]
1. Yeast three hybrid assay [Option ID = 91038]
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2. Yeast two hybrid assay [Option ID = 91039]3. Florescence resonance energy transfer (FRET) [Option ID = 91036]
4. Co-immunoprecipitation [Option ID = 91037]
Correct Answer :-
Yeast three hybrid assay [Option ID = 91038]
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Cyclins facilitate progression cell cycle by: [Question ID = 52762]1. Inducing synthesis of constitutively active forms of growth cell receptors to trigger signalling cascades. [Option ID = 91043]
2. Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
3. Increasing the production of DNA polymerases so cells can enter into G2 phase. [Option ID = 91042]
4. Directly activating G proteins which in turn affects the protein kinases [Option ID = 91041]
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Correct Answer :-Activating the protein kinases which are critical regulators of cell division. [Option ID = 91040]
After mutagen treatment, a molecule of 2-aminopurine (an adenine analogue) incorporates into DNA. During replication the 2-AP
protonates causing it to base-pair like guanine. The mutational event caused by this will be
[Question ID = 52770]
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1. AT to GC [Option ID = 91074]7)
8)
9)
10)
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11)12)
2. AT to CG [Option ID = 91072]
3. GC to CG [Option ID = 91075]
4. GC to AT [Option ID = 91073]
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Correct Answer :-AT to GC [Option ID = 91074]
Autoradiography of pulse-labelled cells can identify sites of biosynthetic activity and product accumulation. Identify the molecule and
site of accumulation when a 5min [
3
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H] uridine pulse followed by a 2-h chase in precursor-free media is given to the cells. [Question ID =52775]
1. signals will be in only the nucleus because labelled DNA is continuously synthesized and accumulated [Option ID = 91093]
2. signals will be in the cytoplasm because labelled DNA is formed in the nucleus however accumulated in the cytoplasm over a longer period. [Option ID =
91095]
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3. signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]4. signals will be in both nucleus and cytoplasm because labelled nuclear RNA will be continuously formed over 2 hours [Option ID = 91092]
Correct Answer :-
signals will be in the cytoplasm because labelled nuclear RNA is formed in the nucleus and then moves to the cytoplasm [Option ID = 91094]
An individual with the genotype AaBbccddEe can make how many different types of gametes? [Question ID = 52769]
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1. two [Option ID = 91068]2. three [Option ID = 91069]
3. eight [Option ID = 91071]
4. four [Option ID = 91070]
Correct Answer :-
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eight [Option ID = 91071]How do new alleles arise in a population? [Question ID = 52741]
1. Sexual reproduction [Option ID = 90956]
2. Meiosis [Option ID = 90958]
3. Chromosomal aberrations [Option ID = 90959]
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4. Mutations of pre-existing alleles [Option ID = 90957]Correct Answer :-
Mutations of pre-existing alleles [Option ID = 90957]
How many linkage groups will be present in the human beings? [Question ID = 52764]
1. 24 [Option ID = 91049]
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2. 48 [Option ID = 91051]3. 23 [Option ID = 91048]
4. 46 [Option ID = 91050]
Correct Answer :-
24 [Option ID = 91049]
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Depending on the criteria such as quality and content of information, reproducibility and speed of different DNA marker systems,identify the most suitable arrangement in the descending order: [Question ID = 52754]
1. AFLP ? SSR ? RFLP - RAPD [Option ID = 91008]
2. SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
3. RFLP ? AFLP ? SSR - RAPD [Option ID = 91009]
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4. RAPD ? SSR ? RFLP ? AFLP [Option ID = 91011]Correct Answer :-
SSR ? RFLP ? AFLP - RAPD [Option ID = 91010]
The unusual property of Taq polymerase that is critical to the PCR is its [Question ID = 52778]
1. ability to use RNA as a template [Option ID = 91107]
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2. ability to use dNTPs as substrate [Option ID = 91104]3. ability to synthesize DNA in the 3? to 5? direction [Option ID = 91106]
4. thermostability [Option ID = 91105]
Correct Answer :-
thermostability [Option ID = 91105]
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13)14)
15)
16)
17)
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18)Access of transcription factors to DNA is usually influenced by: [Question ID = 52782]
1. phosphorylation of CTD of Rpb1 in RNA polymerase II [Option ID = 91123]
2. phosphorylation of histones in the euchromatin [Option ID = 91121]
3. acetylation of histones in the euchromatin [Option ID = 91120]
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4. acetylation of DNA in the euchromatin [Option ID = 91122]Correct Answer :-
acetylation of histones in the euchromatin [Option ID = 91120]
Plasmid vectors used in cloning often contain a gene for the N-terminal 146 amino acids of the enzyme ?-galactosidase. What is the
purpose of including this gene in the vector? [Question ID = 52774]
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1. Allow plasmid conjugation [Option ID = 91091]2. Allow plasmid replication [Option ID = 91088]
3. Screen for recombinant vectors with inserts [Option ID = 91090]
4. Allow resistant transformants to grow in the selective medium [Option ID = 91089]
Correct Answer :-
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Screen for recombinant vectors with inserts [Option ID = 91090]You have a mixture of three proteins having molecular weights 40kDa, 150kDa and 250kDa respectively. You separate them on a size
exclusion column packed in such a manner that proteins greater than 200kDa elute in the void volume. What below best describes the
elution order of the three proteins? [Question ID = 52753]
1. 40kDa followed by 150kDa followed by 250kDa [Option ID = 91004]
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2. 40kDa and 150kDa in the same fraction followed by 250kDa [Option ID = 91007]3. 250kDa followed by 40kDa followed by 150kDa [Option ID = 91006]
4. 250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
Correct Answer :-
250kDa followed by 150kDa followed by 40kDa [Option ID = 91005]
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Occasionally, Drosophila flies are born with curly wings. A genetics professor takes several of these unusual flies and crosses them toone another with the following result: 532 curly wings, 266 normal wings. The mutation that causes curly wings is probably :
[Question ID = 52768]
1. recessive and lethal in the homozygous state [Option ID = 91064]
2. recessive and semi-lethal in the homozygous state [Option ID = 91065]
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3. dominant and lethal in the homozygous state [Option ID = 91066]4. dominant and semi-lethal in the homozygous state [Option ID = 91067]
Correct Answer :-
dominant and lethal in the homozygous state [Option ID = 91066]
Receptors of this ligand are NOT present on plasma membrane: [Question ID = 52779]
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1. Insulin. [Option ID = 91111]2. Serotonin. [Option ID = 91110]
3. Steroid hormones. [Option ID = 91109]
4. Peptide. [Option ID = 91108]
Correct Answer :-
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Steroid hormones. [Option ID = 91109]In sexually reproducing organism, association of alleles of different genes leads to gamete formation and subsequent fusion of
gametes leads to fertilization. Hence the state of linkage disequilibrium between a pair of genes is due to:
[Question ID = 52756]
1. Random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91019]
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2. Random association of the alleles of the two genes and non-random fusion of the gametes [Option ID = 91018]3. Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
4. Non-random association of alleles of the two genes and non-random fusion of the gametes [Option ID = 91016]
Correct Answer :-
Non-random association of the alleles of the two genes and random fusion of the gametes [Option ID = 91017]
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19)20)
21)
22)
23)
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24)25)
Why is Arabidopsis thalania widely used as model organism to study plant development?
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i. Short life cycleii. Requires minimal space to cultivate
iii. Genome has been sequenced [Question ID = 52745]
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1. (i) and (iii) only [Option ID = 90974]2. (i) only [Option ID = 90972]
3. (i), (ii) and (iii) [Option ID = 90975]
4. (ii) only [Option ID = 90973]
Correct Answer :-
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(i), (ii) and (iii) [Option ID = 90975]When a culture of bacteria is shifted to high temperatures, the heat shock response is triggered by: [Question ID = 52785]
1. a sensor protein on the ribosome. [Option ID = 91132]
2. a conversion of a repressor protein to an activator protein. [Option ID = 91135]
3. removal of a repressor protein. [Option ID = 91134]
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4. specific sigma factors. [Option ID = 91133]Correct Answer :-
specific sigma factors. [Option ID = 91133]
A protective mechanism in eukaryotic cells that destroys mRNA with the same sequence as dsRNA is: [Question ID = 52784]
1. Nonsense mediated decay. [Option ID = 91128]
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2. Proteasome. [Option ID = 91130]3. RNA interference. [Option ID = 91129]
4. CRISPR. [Option ID = 91131]
Correct Answer :-
RNA interference. [Option ID = 91129]
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A patient has an abnormal karyotype exhibiting 3 copies of chromosome 21. This chromosomal anomaly most likely arose from anerror during the following stage of cell cycle: [Question ID = 52766]
1. Cytokinesis [Option ID = 91057]
2. Meiosis I [Option ID = 91058]
3. Mitosis [Option ID = 91056]
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4. Interphase [Option ID = 91059]Correct Answer :-
Meiosis I [Option ID = 91058]
This amino acid is NOT yet found in proteins? [Question ID = 52783]
1. L-lysine [Option ID = 91124]
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2. Pyrrolysine [Option ID = 91127]3. Selenocysteine [Option ID = 91125]
4. D-lysine [Option ID = 91126]
Correct Answer :-
D-lysine [Option ID = 91126]
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Matrix assisted laser desorption ionization time of flight (MALDI-TOF) spectrometry is most useful for predicting which of thefollowing? [Question ID = 52752]
1. Molecular mass [Option ID = 91002]
2. Three-dimensional structure [Option ID = 91003]
3. Secondary structure [Option ID = 91001]
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4. Isoelectric point [Option ID = 91000]Correct Answer :-
Molecular mass [Option ID = 91002]
The DNA content of a diploid cell is measured in the G1 phase. After meiosis I, the DNA content of one of the two cells produced
would be: [Question ID = 52758]
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1. equal to that of the G1 cell [Option ID = 91024]26)
27)
2. one-fourth that of the G1 cell [Option ID = 91027]
3. twice that of the G1 cell [Option ID = 91025]
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4. one-half that of the G1 cell [Option ID = 91026]Correct Answer :-
equal to that of the G1 cell [Option ID = 91024]
A short length of double stranded DNA molecule has 80 thymidine and 80 guanine bases. The total number of nucleotide in the DNA
fragment is: [Question ID = 52763]
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1. 640 [Option ID = 91047]2. 40 [Option ID = 91044]
3. 320 [Option ID = 91046]
4. 160 [Option ID = 91045]
Correct Answer :-
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320 [Option ID = 91046]1. The autoradiogram below shows the pattern of hybridization following Southern hybridization of human DNA digested with a
restriction enzyme. In the figure below the autoradiogram on the left is hybridized to probe A while the one on the right is hybridized to
probe B.
If the arrows in the following maps represent the sites of the restriction enzyme, which map best explains the results shown
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above?[Question ID = 52739]
1. [Option ID = 90949]
2. [Option ID = 90951]
3. [Option ID = 90950]
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4. [Option ID = 90948]Correct Answer :-
28)
29)
[Option ID = 90949]
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1. A hypothetical gene called genet was identified in a bacterial strain. The gene is regulated by a chemical compound, PHD. Further itwas observed that PHD regulated genet through a protein called DU that probably bound to a DNA element DUB (Binding site for DU
located near the promoter of genet. Two mutant strains were developed:
a. DU
1
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: the gene encoding DU protein has a nonsense mutationb. ?DUB : where the probable binding site for the DU protein was deleted.
In an experiment, the wild type and mutant bacterial cells were treated with the chemical PHD and the expression of genet gene
monitored. Untreated cells were used as controls. The following table summarizes the observed results:
Bacterial Strain
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Activity of genet inControl cells Treated cells
Wild type 100 40
DU
1
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05 05?DUB 100 40
Based on the above data which of the following conclusion(s) can we made:
i. The genet gene is induced by PHD.
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ii. DU is a negative regulator (i.e. represses the activity) of the genet geneiii. DUB is not the binding site for DU protein.
Which of the above conclusions are correct?
[Question ID = 52737]
1. [Option ID = 90943]
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2. [Option ID = 90940]3. [Option ID = 90942]
4. [Option ID = 90941]
Correct Answer :-
[Option ID = 90941]
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[Question ID = 52751]1. N-terminus faces the cytosol and C-terminus faces the lumen of the membrane vesicle [Option ID = 90996]
2. N-terminus and C-terminus both face the cytosol [Option ID = 90999]
3. N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
4. C-terminus faces the cytosol and N-terminus faces the lumen of the membrane vesicle [Option ID = 90997]
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Correct Answer :-N-terminus and C-terminus both face the lumen of the membrane vesicle [Option ID = 90998]
30)
31)
32)
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[Question ID = 52747]1. The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
2. The mRNA encodes for a precursor protein which is translated on ER bound ribosomes with maturation taking place co-translationally within the ER.
[Option ID = 90983]
3. The mRNA encodes for a protein which is 50kDa in size and requires no processing within the ER [Option ID = 90980]
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4. The mRNA encodes for a protein which is 45kDa in size in vivo [Option ID = 90981]Correct Answer :-
The mRNA encodes for a precursor protein which is translated in the cytosol and matures within the ER prior to secretion. [Option ID = 90982]
[Question ID = 52746]
1. Mtg2p is a tightly associated peripheral membrane protein [Option ID = 90977]
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2. Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]3. Mtg2p is a soluble matrix protein [Option ID = 90979]
4. Mtg2p is partially imbedded in the inner mitochondrial membrane [Option ID = 90978]
Correct Answer :-
Mtg2p is an integral membrane protein of the mitochondria [Option ID = 90976]
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[Question ID = 52777]33)
1. (i) (iv) and (v) [Option ID = 91103]
2. (i) (iii) and (v) [Option ID = 91102]
3. (i) (iii) and (iv) [Option ID = 91100]
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4. (ii) (iii) and (v) [Option ID = 91101]Correct Answer :-
(i) (iii) and (iv) [Option ID = 91100]
[Question ID = 52786]
1. [Option ID = 91137]
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2. [Option ID = 91138]3. [Option ID = 91139]
34)
35)
4. [Option ID = 91136]
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Correct Answer :-[Option ID = 91138]
[Question ID = 52738]
1. [Option ID = 90945]
2. [Option ID = 90946]
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3. [Option ID = 90947]4. [Option ID = 90944]
Correct Answer :-
[Option ID = 90945]
[Question ID = 52749]
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36)37)
38)
39)
40)
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41)1. One [Option ID = 90988]
2. Three [Option ID = 90990]
3. Four [Option ID = 90991]
4. Two [Option ID = 90989]
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Correct Answer :-Two [Option ID = 90989]
[Question ID = 52757]
1. 3 genotypes; 4 phenotypes [Option ID = 91020]
2. 3 genotypes; 3 phenotypes [Option ID = 91022]
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3. 4 genotypes; 3 phenotypes [Option ID = 91023]4. 4 genotypes; 4 phenotypes [Option ID = 91021]
Correct Answer :-
4 genotypes; 3 phenotypes [Option ID = 91023]
Human beings carrying the dominant allele R can roll their tongue. In a population in which the frequency of this allele is 0.8, what is
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the probability that a particular individual who can roll his/her tongue is homozygous?[Question ID = 52776]
1. 0.32 [Option ID = 91097]
2. 0.96 [Option ID = 91098]
3. 0.66 [Option ID = 91099]
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4. 0.64 [Option ID = 91096]Correct Answer :-
0.66 [Option ID = 91099]
A PCR reaction that continues for 30 cycles will produce approximately how many PCR products from a single template DNA
molecule? [Question ID = 52744]
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1. ~ 1 billion [Option ID = 90971]2. ~ 1 million [Option ID = 90970]
3. 128,000 [Option ID = 90969]
4. 64 [Option ID = 90968]
Correct Answer :-
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~ 1 billion [Option ID = 90971]In a cell undergoing meiosis, the number of copies of a gene at Metaphase I, Anaphase I and Metaphase II would be: [Question ID =
52755]
1. 4, 4, 4 [Option ID = 91012]
2. 4, 4, 2 [Option ID = 91014]
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3. 2, 2, 4 [Option ID = 91015]4. 2, 2, 2 [Option ID = 91013]
Correct Answer :-
4, 4, 2 [Option ID = 91014]
Which of the following protein maintained at constant levels throughout the cell cycle and requires for cyclin to become catalytically
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active? [Question ID = 52765]1. Cyclins [Option ID = 91054]
2. Acetyl transferase [Option ID = 91052]
3. Cyclin dependent kinases (Cdk) [Option ID = 91055]
4. Protein kinase [Option ID = 91053]
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Correct Answer :-Cyclin dependent kinases (Cdk) [Option ID = 91055]
Which of the following is a bypass repair system: [Question ID = 52742]
42)
43)
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44)45)
46)
47)
1. Base excision repair [Option ID = 90960]
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2. SOS repair [Option ID = 90962]3. Nucleotide excision repair [Option ID = 90961]
4. Recombinational repair [Option ID = 90963]
Correct Answer :-
SOS repair [Option ID = 90962]
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Which of the following amino acids are incorrectly grouped based on their side chain polarity properties? [Question ID = 52780]1. Isoleucine, Leucine, Alanine [Option ID = 91115]
2. Methionine, Cysteine, Serine [Option ID = 91112]
3. Phenylalanine, Tyrosine, Tryptophan [Option ID = 91114]
4. Arginine, Lysine, Proline [Option ID = 91113]
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Correct Answer :-Which one of the following listed processes below starts from 3? to 5? direction? [Question ID = 52781]
1. Trans-splicing [Option ID = 91118]
2. mRNA editing [Option ID = 91119]
3. Translation [Option ID = 91117]
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4. Polyadenylation [Option ID = 91116]Correct Answer :-
mRNA editing [Option ID = 91119]
The translation of an mRNA encoding a secretory protein using a cell free translation system containing microsomes (ER) lacking
signal recognition particles (SRP) is initiated. Shortly afterwards SRP molecules in presence of TX100 are added followed by further
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incubation. Which of the following outcome is the most likely? [Question ID = 52748]1. The protein will be fully synthesized but not incorporated into microsomes. [Option ID = 90987]
2. The protein will be fully synthesized and incorporated into microsomes. [Option ID = 90985]
3. The protein will be fully synthesized and its signal sequence will be removed without being incorporated into microsomes [Option ID = 90986]
4. Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]
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Correct Answer :-Protein synthesis will begin but will be terminated prematurely leading to shorter products. [Option ID = 90984]
Interference is a common phenomenon during crossing over in meiosis. With the increase in the frequency of double cross over, the
coefficient of coincidence will: [Question ID = 52760]
1. No relationship between double cross over and coefficient of coincidence [Option ID = 91035]
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2. Decrease [Option ID = 91033]3. Remain same [Option ID = 91034]
4. Increase [Option ID = 91032]
Correct Answer :-
Increase [Option ID = 91032]
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The spatial distribution of mRNA in a cell can be detected by:[Question ID = 52743]
1. Fluorescent in situ hybridization [Option ID = 90967]
2. Northern blot hybridization [Option ID = 90965]
3. Dot blot hybridization [Option ID = 90966]
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4. Immunofluorescence [Option ID = 90964]Correct Answer :-
Fluorescent in situ hybridization [Option ID = 90967]
The development of the antero-posterior axis of Drosophila is initiated when:
[Question ID = 52767]
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1. The terminal group protein Torso sets up the anterior and posterior poles of the embryo [Option ID = 91061]2. The mother contributes and packages bicoid and nanos mRNA into the developing oocyte [Option ID = 91060]
3. The homeotic genes specify the fate of individual segments [Option ID = 91062]
4. The sperm enters the micropile at the anterior end, thus specifying the antero-posterior axis [Option ID = 91063]
48)
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49)50)
Correct Answer :-
The mother contributes and packages bicoid and nanos mRNA into the developing oocyte [Option ID = 91060]
You want to express recombinant human insulin protein in E. coli. You are given a clone containing the pig insulin gene and human
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pancreatic tissue. Listed below are steps that are required.a. cDNA library with cloned pig insulin gene
b. isolate mRNA from human pancreas
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c. express recombinant human insulin in E. coli
d. using reverse transcriptase, make cDNA
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e. select positive clones that hybridize to the cloned pig insulin genef. clone cDNAs into expression vector to make library
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Which of the following best describes the correct order?[Question ID = 52772]
1. aecbdf [Option ID = 91080]
2. bdfaec [Option ID = 91083]
3. bdafec [Option ID = 91081]
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4. abdfec [Option ID = 91082]Correct Answer :-
bdfaec [Option ID = 91083]
You have five yeast strains each having distinct temperature sensitive allele of YFG1 named ts1-ts5 for impaired growth at 42?C. In
the laboratory you identify a suppressor to ts1 named sup1 which restores growth at 42?C. Using pairwise crossing you combine ts2-ts5
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with sup1. It turns out that sup1 when combined with ts2-ts5 does not suppress impaired growth at 42?C. Which statement below bestdescribes sup1 function with respect to ts1?
[Question ID = 52750]
1. sup1 is a either a dosage or bypass suppressor of ts1 [Option ID = 90995]
2. sup1 is a bypass suppressor of ts1 [Option ID = 90994]
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3. sup1 is a dosage suppressor of ts1 [Option ID = 90992]4. sup1 is an interaction suppressor of ts1 [Option ID = 90993]
Correct Answer :-
sup1 is an interaction suppressor of ts1 [Option ID = 90993]
You wish to amplify the region in BOLD CAPS below using PCR.
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5'gagatcaggacttaGATTACAGATTACAGATTACAGATTACAggccaagtc3'
Select the correct set of 8bp primer pair:
[Question ID = 52771]
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1. 5'AGGACTTA3' and 5'GGCCAAGT3' [Option ID = 91076]2. 5'AGGACTTA3' and 5'TGAACCGG3' [Option ID = 91079]
3. 5'AGGACTTA3' and 5'ACTTGGCC3' [Option ID = 91078]
4. 5'TAAGTCCT3' and 5'ACTTGGCC3' [Option ID = 91077]
Correct Answer :-
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5'AGGACTTA3' and 5'ACTTGGCC3' [Option ID = 91078]FirstRanker.com - FirstRanker's Choice