Download CBSE Class 10 Maths Basic Marking Scheme 2021 Model Paper

Max. Marks: 80

Class- X

Mathematics-Basic (241)

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Marking Scheme SQP-2020-21

Duration: 3hrs

1. 156 = 2² x 3 x 13

   1

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2. Quadratic polynomial is given by x² - (a +b) x +ab

   x²-2x -8

   1

3. HCF X LCM =product of two numbers

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   LCM (96,404) = 96 X 404

   4

   LCM = 9696

   ¹/₂

   OR

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   Every composite number can be expressed (factorized) as a product of primes, and this factorization is unique, apart from the order in which the factors occur.

   1

4. x – 2y =0

   3x + 4y -20 =0

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   ¹/₃ ? ^-2/₄

   As, ^a₁/_a2 ? ^b₁/_b2 is one condition for consistency.

   Therefore, the pair of equations is consistent.

   ¹/₂

   ¹/₂

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5. 1

   1

6. ? = 60°

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   Area of sector = ^?/_360° ?r²

   A = ^60°/_360° X ²²/₇ X (6)² cm²

   A= ¹/₆ X ²²/₇ X36 cm²

   = 18.86cm²

   ¹/₂

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   OR

   Another method-

   Horse can graze in the field which is a circle of radius 28 cm.

   So, required perimeter = 2?r= 2.?(28) cm

   =2 x ²²/₇ X (28)cm

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   = 176 cm

   ¹/₂

   ¹/₂

7. By converse of Thale's theorem DE II BC

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   ?ADE = ? ABC = 70°

   Given ? BAC = 50°

   ?ABC + ? BAC +?BCA =180° (Angle sum prop of triangles)

   70° + 50° + ? BCA = 180°

   ?BCA = 180° - 120° = 60°

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   ¹/₂

   ¹/₂

   OR

   EC = AC – AE = (7- 3.5) cm 3.5 cm

   ^AD/_BD = ²/₃ and ^AE/_EC= ^3.5/_3.5 = 1

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   So, ^AD/_BD ? ^AE/_EC

   Hence, By converse of Thale's Theorem, DE is not Parallel to BC.

   ¹/₂

   ¹/₂

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8. Length of the fence = ^{Total cost}/_Rate

   = ^Rs.5280/_Rs.24/metre = 220 m

   So, length of fence = Circumference of the field

   : 220m= 2 ?r=2X²²/₇X r

   So, r = ^{220 x 7}/_{2 x 22} m =35 m

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   ¹/₂

   ¹/₂

9. //Question 15
   

   This download link is referred from the post: CBSE Class 10 Marking Scheme 2021 Model Question Paper || CBSE Board Exams 2021 Marking Scheme

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