Download GTU BE/B.Tech 2018 Winter 3rd Sem New 2133606 Material And Energy Balance Calculations Question Paper

Download GTU (Gujarat Technological University) BE/BTech (Bachelor of Engineering / Bachelor of Technology) 2018 Winter 3rd Sem New 2133606 Material And Energy Balance Calculations Previous Question Paper

www.FirstRanker.com
1
Seat No.: ________ Enrolment No.___________

GUJARAT TECHNOLOGICAL UNIVERSITY

BE - SEMESTER?III (New) EXAMINATION ? WINTER 2018
Subject Code: 2133606 Date:12/12/2018

Subject Name: Material & Energy Balance Calculations

Time: 10:30 AM TO 01:00 PM Total Marks: 70

Instructions:

1. Attempt all questions.

2. Make suitable assumptions wherever necessary.

3. Figures to the right indicate full marks.
Marks
Q.1 (a) Define the quantities with SI units: i) Force ii) Pressure iii) Work. 03
(b) A force of 20 kgf is applied on a piston of diameter 5 cm. Find the
pressure exerted on a piston in KPa.
04
(c) A chemist is interested in preparing 500 ml of 1 normal, 1 molar and 1
molal solution of H 2SO 4. Assuming the density of H 2SO 4 solution to be
1.075 g/cm
3
, calculate the quantities of H2SO4 to be taken to prepare these
solutions.
07

Q.2 (a) Define the laws with their equations:
i) Ideal Gas Law ii) Raoult?s Law iii) Henry?s Law
03
(b) A certain quantity of a gas contained in a closed vessel of volume 1 m
3
at
a temperature of 298 K (25
0
C) and pressure of 131.7 KPa is to be heated
such that the pressure should not exceed 303.98 KPa. Calculate the
temperature of gas attained.
04
(c) Derive: Pressure%=Mole%=Volume% 07
OR
(c) A weight of 1.10 kg of Carbon dioxide occupies a volume of 0.033 m
3
at
300 K. Using the Van der Waals equation of state, calculate the pressure.
Data: For CO2 gas, take a = 3.60 [(m
3
)
2
.kPa] / (kmol)
2
and b = 4.3 x 10
-2

m
3
/kmol.
07
Q.3 (a)
Derive: ?
mix
= (PM
avg
) / RT
03
(b) A gas mixture contains 0.274 kmol of HCl, 0.337 kmol of N 2 and 0.089
kmol of O2. Calculate: (a) Average molecular weight of gas.
04
(c) A solution containing 55% benzene, 28% toluene and 17% xylene by
weight is in contact with its vapour at 373 K. Calculate the total pressure
and molar composition of the liquid & vapour.
Data: Vapour Press. Data at 373 K: Benzene: 178.60KPa, Toluene:
74.60KPa, Xylene: 28KPa.
07
OR
Q.3 (a) Define the terms: (a) % Conversion (b) % Yield (c) % Excess 03
(b) In the production of sulphur trioxide, 100 kmol of SO 2, 200 kmol O 2 are
fed to reactor. The product stream is found to contain 80 kmol SO 3. Find
the % conversion of SO2.
SO2 + 1/2O2 = SO3
04
(c) In the manufacture of acetic acid by oxidation of acetaldehyde, 100 kmol
of acetaldehyde is fed to the reactor per hour. The product leaving the
reactor contains 14.81% acetaldehyde, 59.26% acetic acid, and the rest
oxygen (on mole basis). Find the percentage conversion of acetaldehyde.
CH 3CHO + 1/2O 2 = CH 3COOH
07

Q.4 (a) Define the following terms:
i) Limiting Reactant ii) Excess Reactant iii) Stoichiometric Ratio
03
www.FirstRanker.com www.FirstRanker.com
www.FirstRanker.com
FirstRanker.com - FirstRanker's Choice
www.FirstRanker.com
1
Seat No.: ________ Enrolment No.___________

GUJARAT TECHNOLOGICAL UNIVERSITY

BE - SEMESTER?III (New) EXAMINATION ? WINTER 2018
Subject Code: 2133606 Date:12/12/2018

Subject Name: Material & Energy Balance Calculations

Time: 10:30 AM TO 01:00 PM Total Marks: 70

Instructions:

1. Attempt all questions.

2. Make suitable assumptions wherever necessary.

3. Figures to the right indicate full marks.
Marks
Q.1 (a) Define the quantities with SI units: i) Force ii) Pressure iii) Work. 03
(b) A force of 20 kgf is applied on a piston of diameter 5 cm. Find the
pressure exerted on a piston in KPa.
04
(c) A chemist is interested in preparing 500 ml of 1 normal, 1 molar and 1
molal solution of H 2SO 4. Assuming the density of H 2SO 4 solution to be
1.075 g/cm
3
, calculate the quantities of H2SO4 to be taken to prepare these
solutions.
07

Q.2 (a) Define the laws with their equations:
i) Ideal Gas Law ii) Raoult?s Law iii) Henry?s Law
03
(b) A certain quantity of a gas contained in a closed vessel of volume 1 m
3
at
a temperature of 298 K (25
0
C) and pressure of 131.7 KPa is to be heated
such that the pressure should not exceed 303.98 KPa. Calculate the
temperature of gas attained.
04
(c) Derive: Pressure%=Mole%=Volume% 07
OR
(c) A weight of 1.10 kg of Carbon dioxide occupies a volume of 0.033 m
3
at
300 K. Using the Van der Waals equation of state, calculate the pressure.
Data: For CO2 gas, take a = 3.60 [(m
3
)
2
.kPa] / (kmol)
2
and b = 4.3 x 10
-2

m
3
/kmol.
07
Q.3 (a)
Derive: ?
mix
= (PM
avg
) / RT
03
(b) A gas mixture contains 0.274 kmol of HCl, 0.337 kmol of N 2 and 0.089
kmol of O2. Calculate: (a) Average molecular weight of gas.
04
(c) A solution containing 55% benzene, 28% toluene and 17% xylene by
weight is in contact with its vapour at 373 K. Calculate the total pressure
and molar composition of the liquid & vapour.
Data: Vapour Press. Data at 373 K: Benzene: 178.60KPa, Toluene:
74.60KPa, Xylene: 28KPa.
07
OR
Q.3 (a) Define the terms: (a) % Conversion (b) % Yield (c) % Excess 03
(b) In the production of sulphur trioxide, 100 kmol of SO 2, 200 kmol O 2 are
fed to reactor. The product stream is found to contain 80 kmol SO 3. Find
the % conversion of SO2.
SO2 + 1/2O2 = SO3
04
(c) In the manufacture of acetic acid by oxidation of acetaldehyde, 100 kmol
of acetaldehyde is fed to the reactor per hour. The product leaving the
reactor contains 14.81% acetaldehyde, 59.26% acetic acid, and the rest
oxygen (on mole basis). Find the percentage conversion of acetaldehyde.
CH 3CHO + 1/2O 2 = CH 3COOH
07

Q.4 (a) Define the following terms:
i) Limiting Reactant ii) Excess Reactant iii) Stoichiometric Ratio
03
www.FirstRanker.com www.FirstRanker.com
www.FirstRanker.com
www.FirstRanker.com
2
(b) Calculate the following for the reaction:
C2H4 + 2Cl2 ? C2HCl3 + H2 + HCl
(i) The stoichiometric ratio of Cl 2 to C 2H 4
(ii) If 4 kmol Cl 2 is used per kmol of C 2H 4, find the % excess Cl 2.
04
(c) A coke is known to contain 90% carbon and 10% non-combustible
ash(by weight):
C + O 2=CO 2
i) Find the moles of oxygen theoretically required to burn 100 kg of
coke completely.
ii) If 50% excess air is supplied, find the analysis of the gases at the end
of the combustion?
07
OR
Q.4 (a) Define the following terms:
i) Law of Conservation of Mass ii)Heat Capacity iii) recycling
03
(b) Explain the following unit operations with their block diagram and
material balances: i) Distillation ii) Evaporation.
04
(c) Fresh juice contains 15% solids and 85% water by weight and is to be
concentrated to contain 40% solids by weight.
In a single stage evaporation system, it is found that volatile constituents
of juice escape with water leaving the concentrated juice with a flat taste.
In order to overcome this problem, part of the fresh juice bypasses the
evaporator. The operation is shown schematically:

Calculate:
i) The fraction of juice that bypasses the evaporator.
ii) The concentrated juice produced (containing 40% solids) per 100 kg
of fresh juice fed to the process.
07
Q.5 (a) Explain standard heat of reaction and standard heat of combustion. 03
(b) Explain the significance of bypass operation with neat flow diagram. 04
(c) Soyabean seeds are extracted with the hexane in batch extractors. The
flaked seeds are found to contain 18.6% oil, 69% solids, 12.4% moisture
(by weight). At the end of the extraction process, cake is separated from
hexane-oil mixture. The cake is analyzed to contain 0.8% oil, 87.7%
solids and 11.5% moisture (by weight). Find the percent recovery of oil.
07
OR
Q.5 (a) Define: i) Dry-bulb temperature ii) Wet-bulb temperature. 03
(b) Chlorinated diphenyl is heated from 313 K (40
0
C) to 533 K (260
0
C) in an
indirectly fired heater at the rate of 4000 kg/h. Calculate the heat required
to be added to the fluid in the heater. The heat capacity of the fluid in this
temperature range is given by the equation: C= 0.7511+1.465?10
-3
T,
kJ/(kg.K) where T is in K.
04
(c) Calculate the change in enthalpy between reactants and products if both
are at 298 K (25
0
C) and if 5 mole of ethylene oxide is produced as per the
following reaction:
C2H4(g) + 1/2 O2(g) = C2H4O(g)
Data:
Component ?H
0
f, kJ/mol at 298.15 K(250C)
C2H4(g) 52.50
C2H4O(g) -52.63

07
***************
www.FirstRanker.com www.FirstRanker.com
www.FirstRanker.com
FirstRanker.com - FirstRanker's Choice

This post was last modified on 20 February 2020